EE版 - 如何从spice level49的模型中计算effective length? |
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b*******r
发帖数: 1130 | 1 例如TSMC.25um的spice model
.MODEL CMOSN NMOS ( LEVEL = 49
+VERSION = 3.1 TNOM = 27 TOX = 5.7E-9
+XJ = 1E-7 NCH = 2.3549E17 VTH0 = 0.3951677
+K1 = 0.4881677 K2 = -1.465714E-6 K3 = 1E-3
+K3B = 1.2222493 W0 = 1E-7 NLX = 1.927361E-7
+DVT0W = 0 DVT1W = 0 DVT2W = 0
+DVT0 = 0.4751286 DVT1 = 0.5660833 DVT2 = -0.3026132
+U0 = 314.8066794 UA = -1.152667E-9 UB = 2.42808E-18
+UC = 4.12734E-11 VSAT = 1.287591E5 A0 = 1.7957675
+AGS = 0.359392 B0 = 1.272642E-10 B1 = 4.171173E-9
+KETA = -9.762332E-3 A1 = 4.569146E-4 A2 = 0.531924
+RDSW = 200 PRWG = 0.5 PRWB = -0.1243425
+WR = 1 WINT = 0 LINT = 0
+XL = 0 XW = -4E-8 DWG = -4.486604E-9
+DWB = 5.37129E-9 VOFF = -0.1090174 NFACTOR = 1.5319983
+CIT = 0 CDSC = 2.4E-4 CDSCD = 0
+CDSCB = 0 ETA0 = 6.182294E-3 ETAB = 2.692579E-4
+DSUB = 0.0454551 PCLM = 1.6205616 PDIBLC1 = 0.9594821
+PDIBLC2 = 2.748496E-3 PDIBLCB = -0.0120856 DROUT = 1
+PSCBE1 = 6.837438E8 PSCBE2 = 2.319772E-4 PVAG = 9.534155E-3
+DELTA = 0.01 RSH = 4.6 MOBMOD = 1
+PRT = 0 UTE = -1.5 KT1 = -0.11
+KT1L = 0 KT2 = 0.022 UA1 = 4.31E-9
+UB1 = -7.61E-18 UC1 = -5.6E-11 AT = 3.3E4
+WL = 0 WLN = 1 WW = 0
+WWN = 1 WWL = 0 LL = 0
+LLN = 1 LW = 0 LWN = 1
+LWL = 0 CAPMOD = 2 XPART = 0.5
+CGDO = 4.08E-10 CGSO = 4.08E-10 CGBO = 1E-12
+CJ = 1.73899E-3 PB = 0.983128 MJ = 0.4655282
+CJSW = 3.528754E-10 PBSW = 0.8515942 MJSW = 0.2684911
+CJSWG = 3.29E-10 PBSWG = 0.8515942 MJSWG = 0.2684911
+CF = 0 PVTH0 = -6.690647E-3 PRDSW = -8.4014148
+PK2 = 1.959318E-3 WKETA = 3.580257E-3 LKETA = 8.792764E-4
) | m*****t
发帖数: 3477 | 2 Level49 就是HSPICE的BSIM3吧。
这个如果不是binnning model的话，基本近似等于
Weff=Wdrawn-2*WINT
Leff=Ldrawn-2*LINT
W有一些bias dependency，公式复杂些，不过如果没有很强的back-bias（Vbs=0），就
忽略吧。
如果是binning model的话，dl,dw要分别scale。
你算它干吗？让simulator handle 就完了。
【在 b*******r 的大作中提到】
: 例如TSMC.25um的spice model
: .MODEL CMOSN NMOS ( LEVEL = 49
: +VERSION = 3.1 TNOM = 27 TOX = 5.7E-9
: +XJ = 1E-7 NCH = 2.3549E17 VTH0 = 0.3951677
: +K1 = 0.4881677 K2 = -1.465714E-6 K3 = 1E-3
: +K3B = 1.2222493 W0 = 1E-7 NLX = 1.927361E-7
: +DVT0W = 0 DVT1W = 0 DVT2W = 0
: +DVT0 = 0.4751286 DVT1 = 0.5660833 DVT2 = -0.3026132
: +U0 = 314.8066794 UA = -1.152667E-9 UB = 2.42808E-18
: +UC = 4.12734E-11 VSAT = 1.287591E5 A0 = 1.7957675
| b*******r
发帖数: 1130 | 3 靠，这个model里面Lint，Wlin都为0，hand calculation需要啊。 | l****o
发帖数: 184 | 4 hand calculation 干吗要这么准确地 大概知道数量级就完啦 |
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