t**********a
发帖数: 35 | 1 Charlie Oppenheim of DOS informed AILA that EB-2 priority dates for China-
mainland and India will retrogress for the remainder of FY2012 to August 15,
2007, as of the May Visa Bulletin.
Please pay attention to the words "for the remainder of FY2012". |
|
j*****y
发帖数: 1071 | 2 void add(vector & a, uint b)
{
int remainder = 0;
int i;
for(i = a.size() - 1; i > -1 && b > 0; --i)
{
a[i] += remainder + b % 10;
b = b / 10;
if(a[i] >= 10)
{
a[i] -= 10;
remainder = 1;
}
else
{
remainder = 0;
}
}
if(i == -1)
... 阅读全帖 |
|
i*****h
发帖数: 1534 | 3 lc原题啊，给你贴上来了。
public String fractionToDecimal(int numerator, int denominator) {
StringBuilder sb=new StringBuilder();
if(denominator==0) return "";
if(numerator>0&&denominator<0 || numerator<0&&denominator>0) sb.
append("-");
long num=Math.abs((long)numerator), den=Math.abs((long)denominator);
sb.append(num/den);
long remainder=num%den;
if(remainder==0) return sb.toString();
sb.append(".");
Map hashMap=new Hash... 阅读全帖 |
|
k****n
发帖数: 369 | 4 do it directly as you do by hand?
int division(int numerator, int denominator) {
HashMap remainders = new HashMap();
StringBuffer sb = new StringBuffer();
sb.append(numerator / denominator).append(".");
return helper(numerator % denominator, denominator, remainders, sb);
}
int helper(int n, int d, HashMap remainders, StringBuffer
result) {
if (n == 0) return 0; // non-recurring
if (remainders.containsKey(n)) {
return result.toStr... 阅读全帖 |
|
j*****y
发帖数: 1071 | 5 这题目还要考 big integer的相乘, 其实感觉挺难的
vector power(vector &a, vector & b)
{
int m = a.size() - 1;
int n = b.size() - 1;
vector result(m + n + 1, 0);
for(int i = 0; i < result.size(); ++i)
{
int power = m + n - i;
for(int k = 0; k <= power; ++k)
{
if(power - k > n)
{
... 阅读全帖 |
|
s********0
发帖数: 71 | 6 在RSA算法里头经常要用到“求x的n次方模m”这样的过程，通常使用O(log(n))的模重
复平方算法来实现，提高效率。
其实这是大二学的《信息安全数学基础》里面的内容，那时为了考试需要（手算+写出
很罗嗦的过程），还专门写了代码放在Blog空间里考试的时候用—……
同样O(log(n))的递归算法其实很容易理解：
/* C */
int fast_mod(int x, int n, int m)
{
if (n == 0)
return 1;
else if (n % 2 == 0)
return square(fast_mod(x, n / 2, m)) % m;
else
return x * fast_mod(x, n - 1, m) % m;
}
#Python
fast_mod = lambda x, n, m: 1 if n == 0 else fast_mod(x, n / 2, m) ** 2 % m
if n % 2 == 0 else x * fast_mod(x, n - 1, m) % m... 阅读全帖 |
|
r*****g
发帖数: 434 | 7 这么学术的东东放错地方了吧
在RSA算法里头经常要用到“求x的n次方模m”这样的过程，通常使用O(log(n))的模重
复平方算法来实现，提高效率。
其实这是大二学的《信息安全数学基础》里面的内容，那时为了考试需要（手算+写出
很罗嗦的过程），还专门写了代码放在Blog空间里考试的时候用—……
同样O(log(n))的递归算法其实很容易理解：
/* C */
int fast_mod(int x, int n, int m)
{
if (n == 0)
return 1;
else if (n % 2 == 0)
return square(fast_mod(x, n / 2, m)) % m;
else
return x * fast_mod(x, n - 1, m) % m;
}
#Python
fast_mod = lambda x, n, m: 1 if n == 0 else fast_mod(x, n / 2, m) ** 2 % m
if n % 2 == 0 else x * fast_mod(x... 阅读全帖 |
|
g**********y
发帖数: 14569 | 8 我只能写到这样了。
public String multiply(String a, String b) {
ArrayList la = convert(a);
ArrayList lb = convert(b);
ArrayList lc = new ArrayList();
for (int i=0; i
int remainder = 0;
for (int i=0; i
for (int j=0; j
int s = lc.get(i+j) + la.get(i)*lb.get(j) + remainder;
lc.set(i+j, s%1000);... 阅读全帖 |
|
j*****y
发帖数: 1071 | 9 这是最后的 code
vector plusOne(vector &input)
{
if(input.size() == 0)
{
return vector(1, 1);
}
int remainder = 1;
for(int i = input.size() -1 ; i > -1; --i)
{
int tmp = input[i] + remainder;
if(tmp >= 10)
{
input[i] = tmp - 10;
remainder = 1;
}
esle
{
input[i] = tmp;
remainder = 0;
break;
}
}
if(remainder != 0)
{
vector tmp(1, remainder);
input.insert(input.begin(),... 阅读全帖 |
|
g**********y
发帖数: 14569 | 10 我只能写到这样了。
public String multiply(String a, String b) {
ArrayList la = convert(a);
ArrayList lb = convert(b);
ArrayList lc = new ArrayList();
for (int i=0; i
for (int i=0; i
int remainder = 0;
for (int j=0; j
int s = lc.get(i+j) + la.get(i)*lb.get(j) + remainder;
lc.set(i+j, s%1000);
remainder = s/1000;
}
if (remainder > 0) lc.set(i+lb.size(), remainder);
}
StringBuilder sb = new StringBui... 阅读全帖 |
|
B****2
发帖数: 8892 | 11 过去，SEC联盟，参加Bowl Game的球队，除SEC报销差旅费外，参加Bowl的球队还要留
下一小部分。下面是以前12个队时SEC怎么分。变化不应该太大。
There seems to be a lot of confusion about how the SEC schools split bowl
revenue (as there always is this time of year). Here's how it works:
*For bowl games with receipts <$1.5M, the participating school retains $925k
plus travel expenses; the remainder is remitted to the SEC.
*For bowl games with receipts of $1.5M or more, but <$4M, the participating
school retains $1.125M plus travel expenses; the remainder is re... 阅读全帖 |
|
f******6
发帖数: 67 | 12 #include
#include
int main(int argc, char *argv[])
{
int value, base;
int remainder, place=79;
char buffer[80];
line_1 //buffer[79]=(char)(0);//不加这一行就有乱码
char *table ="0123456789ABCDEF";
value = atoi(argv[1]);
base = atoi(argv[2]);
printf("%d %dn", value, base);
do {
remainder = value%base;
printf("%cn", table[remainder]);
buffer[place] = (char)(table[remainder]);
printf("%cn", buffer[place]);... 阅读全帖 |
|
c*****z
发帖数: 182 | 13 //division i suppose it ask for integer division which means 5/2=2
// input is big and small , do big/small
result = 0;
remainder = big;
loop(remainder)
remainder = subtract(remainder,small);
result ++;
end loop
decrement(result);
//result = big/small |
|
j*****8
发帖数: 3635 | 14 都是同一个dealer的，基本决定在这3个里面订了，求高人指点。
2010 Hyundai Sonata GLS, 4 cylinder, automatic, 33 mpg highway, tilt wheel,
cruise control, power windows, power locks, AM/FM/MP3 compatible CD/XM
satellite radio, IPOD jack and USB port, side air curtains, side air bags,
ABS, traction control, electronic stability control, manual height
adjustment on driver seat, keyless entry on key fob, rear seat flip down for
trunk access, Gray with Tan cloth interior, 7,424 miles with remainder of 5
year/60k bumper to bumper... 阅读全帖 |
|
w*****x
发帖数: 374 | 15 谢谢楼主分享. 刚才试着解了一下第三题, 犯了一个低级错误: 要先算remainder再算
quotient, 我一开始搞反了......
static char toChar(int number) {
return (char) (number % 26 + 97);
}
static void toBase26(int number) {
// do not handle negative number
if (number < 0) {
return;
}
char[] result = new char[1000];
int quotient = number;
int remainder = 0;
int i = 0;
do {
remainder = quotient % 26;
quotient = quotient / 26 |
|
d**e
发帖数: 6098 | 16 好像很繁琐，只处理 n>= 0。谁能提供一个简易版？怎么处理负数的情况？
char * intToBinStr(int n)
{
char * binStr = 0;
int length = 0;
int remainder = 0;
int factor = 1;
int result = 0;
if(n == 0)
{
binStr = new char('0');
}
else{
while (n >= 1)
{
remainder = n % 2;
result += remainder * factor;
n = n / 2;
factor *= 10;
length++;
}
binStr = new char[length];
while(result >= 1)
{
binStr[--length] = '0' + (result % 10);
|
|
w****o
发帖数: 2260 | 17 我用C语言里的 / 去求商，用 % 求余数，得到以下的结果：
div(12/-5) = -2, remainder = 2
div(-12/5) = -2, remainder = -2
div(-12/-5) = 2, remainder = -2
不太明白的是当除数或者 被除数是负数的时候，不能整除的情况下，到底商是向上靠
，还是向下靠，有什么规律吗？
比如，12/-5 = -2, 余数为 2，而不是12/-5 = -3, 余数为-3
-12/5 = -2, 余数为-2, 而不是 -12/5 = -3, 余数为3
-12/-5 = 2, 余数为-2, 而不是 -12/-5 = 3, 余数为3
谁能说说计算机是根据什么算商和余数的？
谢谢！ |
|
d*****y
发帖数: 1365 | 18 这道题是大数++的变体
int maxmin(vector digits,int target)
{
if(digits.size()<1) return -1;
int clone = target;
int carry = 0;
int result=0;
sort(digits.begin(),digits.end());
int mul=1;
bool firstdigit= true;
while(clone){
int remainder=clone%10+carry;
vector::iterator iter;
if(firstdigit){... 阅读全帖 |
|
A****e
发帖数: 382 | 19 刚才又看了一下以往的Visa Bulletin，特别是section D。鳌拜特别在这里注明一些东
西，可以发现一些蛛丝马迹：
May 2012:
D. RETROGRESSION OF THE CHINA-MAINLAND AND INDIA EMPLOYMENT SECOND
PREFERENCE CUT-OFF DATE
Due to the rapid forward movement of the cut-off date, demand for China and
India Employment Second preference numbers has increased dramatically during
recent months, and at a much faster rate than had been expected. Therefore
, it has been necessary to retrogress that cut-off date to August 15, 2007
in an attempt to hold number u... 阅读全帖 |
|
a*****g
发帖数: 19398 | 20 Number of legal Go positions
The 361 points on a 19x19 Go board can be colored empty, black, or white.
Only some of the 3^361 possible positions are legal, namely those where
every group of connected stones of the same color has an empty point
adjacent to it. In the position above, black stones at E18 and N9 lack such
``liberties'', making the position illegal. Due to its capture rule, the
positions that can arise in a game of Go are exactly the legal positions. On
Jan 20, 2016, the number of le... 阅读全帖 |
|
h*h
发帖数: 27852 | 21 【 以下文字转载自 Mathematics 讨论区 】
发信人: ananpig (●○ 围棋数学一把抓的安安猪), 信区: Mathematics
标 题: 19路围棋的所有合法图案终于出来了 Number of legal Go positi
发信站: BBS 未名空间站 (Wed Jan 27 18:50:19 2016, 美东)
发信人: ananpig (●○ 围棋数学一把抓的安安猪), 信区: Programming
标 题: 19路围棋的所有合法图案终于出来了 Number of legal Go positi
发信站: BBS 未名空间站 (Fri Jan 22 10:38:03 2016, 美东)
Number of legal Go positions
The 361 points on a 19x19 Go board can be colored empty, black, or white.
Only some of the 3^361 possible positions are legal, namely those where
every group... 阅读全帖 |
|
y***v
发帖数: 270 | 22 你们看看： 比较长，
转一篇文章。让事实为肖传国说话
转自：虹桥科教论坛 http://www.rainbowplan.org/bbs/topic.php?topic=114563&select=&forum=1
有人在散仙谷转了一篇文章。应该把这篇文章广为转发。让当局和国内不明真相的人民
都知道肖传国的医学探索的价值。方舟子夹私打假必然会被钉在科学的耻辱柱上。
“肖氏反射弧”真相解析
肖传国教授在世界上第一个提出并证实 “人工建立体神经-内脏神经反射弧” 用于治
疗各种脊髓损伤导致的排尿障碍。这一发现在肖传国与方舟子之间挑起了一场科学与反
科学长达五年的论战。为帮助公众了解这场论战的事实真相，本文首先从学术角度根据
科学文献和科学事实对“肖氏反射弧”作一番解析。
反射是神经支配机体生理机能的基本方式。反射弧一般由感受器，传入神经，反射中枢
，传出神经和效应器组成。正常的排尿反射由位于脑干和大脑皮层的高级排尿中枢控制
达骶髓的排尿反射初级中枢完成。膀胱充盈时，膀胱壁的牵张感受器受到刺激而兴奋。
冲动传入高级中枢产生排尿欲。中枢经过判断认为可以排尿，于是发出神经冲动沿下行
传导束到脊髓初... 阅读全帖 |
|
G****e
发帖数: 11198 | 23 The Darker Side Of God
If you ask Christians to describe their quasi-chosen god of worship,
you’ll often hear such descriptors as “wonderful” and “loving.” This
choice of selective designation seems commonplace within the Christian
community. In fact, most churches ignore the Old Testament all together so
that the members feel comfortable propagating this view. Fueled by such
blatant omission, this lengthy chapter will fill the void by offering a look
at the volume of horrendous acts perfo... 阅读全帖 |
|
G****e
发帖数: 11198 | 24 【 以下文字转载自 WaterWorld 讨论区 】
发信人: GoBlue (Wolverines), 信区: WaterWorld
标 题: The Darker Side Of God
发信站: BBS 未名空间站 (Sat Jul 12 13:10:33 2014, 美东)
The Darker Side Of God
If you ask Christians to describe their quasi-chosen god of worship,
you’ll often hear such descriptors as “wonderful” and “loving.” This
choice of selective designation seems commonplace within the Christian
community. In fact, most churches ignore the Old Testament all together so
that the members feel comfortable propagatin... 阅读全帖 |
|
f*******n
发帖数: 12623 | 25 Actually, it depends on how integer division is rounded.
In C and Java, integer division rounds towards 0. So 17 / -3 = -5. So the
remainder is 17 - (-3 * -5) = 2.
In Python and Ruby, integer division always rounds down. So 17 / -3 = -6. So
the remainder is 17 - (-3 * -6) = -1.
Alternately, you can say that the remainder in C/Java takes the sign of the
dividend, and in Python/Ruby takes the sign of the divisor. |
|
a****m
发帖数: 693 | 26 #include
using namespace std;
class CFraction
{
public: //public method to get GCD
int iNumerator;
int iDenominator;
double dValue;
//constructor...
CFraction( int iNumeratorParam, int iDenominatorParam )
{
iNumerator = iNumeratorParam;
iDenominator = iDenominatorParam;
dValue = iNumerator/ iDenominator;
}
//getGCD
int getGCD( int iNumerator, int iDenominator )
{
int remainder = iDenominator % iNumerator;
if ( remainder != 0 )
return getGCD( remainder,iNumerator );
}
//Reduce (wha... 阅读全帖 |
|
s***a
发帖数: 299 | 27 //getGCD
int getGCD( int iNumerator, int iDenominator )
{
int remainder = iDenominator % iNumerator;
if ( remainder != 0 )
return getGCD( remainder,iNumerator );
// I think you must add else here since you must return an int here
} |
|
a****m
发帖数: 693 | 28 #include
#include "GCD.hpp"
using namespace std;
class CFraction
{
public: //private method to get GCD
int iNumerator;
int iDenominator;
//constructor...
CFraction( int iNumeratorParam, int iDenominatorParam )
{
iNumerator = iNumeratorParam;
iDenominator = iDenominatorParam;
}
//getGCD
int getGCD( int iNumerator, int iDenominator )
{
int remainder = iDenominator % iNumerator;
if ( remainder != 0 )
return getGCD( remainder,iNumerator );
else return 0;
}
CFraction reduce()
{
int iGC... 阅读全帖 |
|
a*****g
发帖数: 19398 | 29 Number of legal Go positions
The 361 points on a 19x19 Go board can be colored empty, black, or white.
Only some of the 3^361 possible positions are legal, namely those where
every group of connected stones of the same color has an empty point
adjacent to it. In the position above, black stones at E18 and N9 lack such
``liberties'', making the position illegal. Due to its capture rule, the
positions that can arise in a game of Go are exactly the legal positions. On
Jan 20, 2016, the number of le... 阅读全帖 |
|
e***y
发帖数: 4307 | 30 states:
start, s1, s2, s3, s4, s5, s6, s7
state transitions (input, next state)
start: (1, s1), (0, start)
s1: (1, s3), (0, s2)
s2: (1, s3), (0, s6)
s3: (1, s7), (0, s6)
s4: (1, s5), (0, s1)
s5: (1, s4), (0, s3)
s6: (1, s6), (0, s5)
s7: (1, s1), (0, s7) ==> output 1 at s7
basically the idea is to represent the remainders of division by 7 using
states s1-s7. there are only 7 different remainders so 7 states are needed.
at each input you'd determine the next remainder and hence the next state. |
|
F********g
发帖数: 475 | 31 unsigned int calculate_1X_LO_period(unsigned int input_freq_khz, unsigned
int if_freq_khz)
{
unsigned int
remainder;
unsigned int temp_result;
unsigned int divisor;
DISABLE_TMR1_INT;
DISABLE_TMR4_INT;
DISABLE_SPI1_INT;
dividend.all=32000;
divisor=input_freq_khz+if_freq_khz;
if (0==divisor)
... 阅读全帖 |
|
a*********3
发帖数: 660 | 32 定义 definition变量 variable面积 area直径 diameter半径 radius公式 formula
单价 unit price范围 range/scope/extent集合 set法则 principle本金 principal利
率 interest rate利息 interest单利 simple interest复利 compound interest正数
positive number负数 negative number解析式 analytic expression分类讨论
classified discussion性质 nature （不是很确定）奇函数 odd function偶函数
even function对称 symmetric坐标原点 origin单调性 monotonicity（不是很确定）
任意 random周期性 periodic 有界性 boundedness 数学 mathematics, maths(BrE)
, math(AmE) 公理 axiom 定理 theorem 计算 calculation 运算 operat... 阅读全帖 |
|
a*****g
发帖数: 19398 | 33 【 以下文字转载自 Programming 讨论区 】
发信人: ananpig (●○ 围棋数学一把抓的安安猪), 信区: Programming
标 题: 19路围棋的所有合法图案终于出来了 Number of legal Go positi
发信站: BBS 未名空间站 (Fri Jan 22 10:38:03 2016, 美东)
Number of legal Go positions
The 361 points on a 19x19 Go board can be colored empty, black, or white.
Only some of the 3^361 possible positions are legal, namely those where
every group of connected stones of the same color has an empty point
adjacent to it. In the position above, black stones at E18 and N9 lack such
``liberti... 阅读全帖 |
|
D********n
发帖数: 978 | 34 Let red = 0, blue = 1 and green = 2. Consider the remainder of mod 3.
In other words, do all calculations in F3.
Verify:
red + blue = 2*green
red + green = 2*blue
blue + green = 2*red
So all the color changing preserves the remainder of mod 3.
10*red + 11*blue +12*green = 2
However, if they change to the same color, since there are 33 of them, the
total remainder will be 0 for sure. Hence impossible.
be |
|
z**********3
发帖数: 11979 | 35 【 以下文字转载自 PDA 讨论区 】
发信人: zhizunbao123 (你在红楼我在西游), 信区: PDA
标 题: FBI paid more than 1.3million to break into iPhone
发信站: BBS 未名空间站 (Thu Apr 21 15:57:58 2016, 美东)
By Julia Edwards
WASHINGTON (Reuters) - Federal Bureau of Investigation Director James Comey
said on Thursday the agency paid more to get into the iPhone of one of the
San Bernardino shooters than he will make in the remaining seven years and
four months he has in his job.
According to figures from the FBI and the U.S. Office of Manageme... 阅读全帖 |
|
发帖数: 1 | 36 12月 谈谈间谍问题
我一直感觉Reuters 有日本的间谍，他们会通过报道来传递针对华人屠杀的计划，和发
布不利于华人的报道，制造舆论。最重要他们后边的势力和犯罪集团有关。有必要好好
调查这个组织。
How top U.S. colleges hooked up with controversial Chinese companies
By Steve Stecklow and Alexandra Harney
Filed Dec. 2, 2016, noon GMT
New Oriental, China’s biggest private educator, has been accused of
academic fraud. Thanks to two enterprising Americans, it has also gained
access to leading U.S. college admissions officers.
SHANGHAI/SHELTER ISLAND, New York - Thomas Benson once ran a small... 阅读全帖 |
|
发帖数: 1 | 37 Yarmouth Port, Massachusetts
From Wikipedia, the free encyclopedia
Yarmouth Port, Massachusetts
Census-designated place
Boardwalk at Bass Hole
Location in Barnstable County and the state ofMassachusetts.
Coordinates: 41°42′17″N 70°13′15″WCoordinates: 41°42′17″N 70°13′
15″W
Country United States
State Massachusetts
County Barnstable
Town Yarmouth
Area
• Total 6.47 sq mi (16.76 km2)
• Land 6.04 sq mi (15.65 km2)
• Water 0.43 sq mi (1.11 km2)
Elevation 52 f... 阅读全帖 |
|
发帖数: 1 | 38 在网上发现了一个圣诞节商店，商店的建筑很有特色，而且遍布全美国，大概有70多个
店铺，以后大家买圣诞节用品可以去那里，似乎各州都有。我们这里和麻州的地址是：
CHRISTMAS TREE SHOP AUGUSTA, GA, 239 ROBERT C. DANIEL JR. PARKWAY,
AUGUSTA EXCHANGE, AUGUSTA, GA 30909, 706.738.0570, CHRISTMAS TREE SHOP
, MAGNOLIA PARK, 1117 WOODRUFF ROAD, GREENVILLE, SC 29607. 864. 297.
3667
CHRISTMAS TREE SHOPS NATICK, 1298 WORCESTER ST. ROUTE 9, SHERWOOD
PLAZA, NATICK, MA 01760, 508.655.9800
CHRISTMAS TREE SHOPS SOMERVILLE, 177 MIDDLESEX AVENUE, ASSEMBLY SQUARE
... 阅读全帖 |
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发帖数: 1 | 39 12月26日 事实的真相
以前我们分析过，Augusta, GA 只是这个人体基地的一个点，而且我们也追踪到还有一
个点在加州。那么经过更多的分析，显示事实的真相可能是如此。这些地下通道是很久
以前就存在的，是为了战争或避难用的，后来在南北战争中，又充当奴隶逃跑到北方的
通道。那么在后来的后来，就被一些别有用心的人充当了非法活动的场地。而到了80年
代后，日本人就加入进来，把其改造成了一个军事，人体实验基地，成了报复美国的一
种手段。当然，我也强调历史和解，仇恨和解，但要在正确的认知，悔改下的和解。如
果一边在屠杀受害者，一边高谈和解，并千方百计掩盖事情真相的曝光，这不是悔改的
表现，最多是转移了屠杀的目标，我们不能原谅罪恶势力彼此勾结下的和解。根据分析
，这个基地的入口就在Deerfield, ILLinois. 世界每一个人都是这个基地的受害者，
都是这些大药厂的受害者，受害者以亿为单位来计算。你们很可能都在不知不觉中受到
了他们的伤害，请把信息传达到世界每一个角落，让我们一起携手和世界上最邪恶的势
力做顽强的斗争，他们现在还在屠杀无辜的受害者，每天在我家里杀人。请你们和我站
在... 阅读全帖 |
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发帖数: 1 | 40 【Filariasis
From Wikipedia, the free encyclopedia
Filariasis
Life cycle of Wuchereria bancrofti, a parasite that causes filariasis
Classification and external resources
Specialty Infectious disease
ICD-10 B74
ICD-9-CM 125.0-125.9
Patient UK Filariasis
MeSH D005368
[edit on Wikidata]
Filariasis is a parasitic disease caused by an infection with roundworms of
the Filarioidea type.[1] These are spread by blood-feeding black flies and
mosquitoes. This disease belongs to the group of d... 阅读全帖 |
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发帖数: 1 | 41 12月27日 为什么我要替中国辩护
我要替中国辩护，并不是因为我是一个中国人，而是因为我知道中国就和这世界上绝大
数的国家一样，虽然有很多丑陋的现象，但是他们是受害者。就
象这个犯罪集团里很多的人一样，他们来自各种种族，他们可能充当了工具，但他们不
是制造这一切，谋划这一切的人。虽然经常会暴露中国产品出现问题。但要知道中国是
世界工厂，他们只是打工者，他们只是按照各种雇主提供的配方来生产，他们并不知道
他们会产生怎样的后果。或者这些工人知道后果，但他们只是奴隶，他们又如何去改变
这一切？ 所以，当我的调查不断往前推进的时候，不可避免地会涉及各国的企业，但
这并不表明是针对这个国家或这个国家的人民，而是针对一种社会现实和丑陋现象。就
拿菲律宾来说，菲律宾是一个犯罪猖獗的国家，有很多犯罪分子，但是菲律宾人民却是
这个集团的受害者，他们／她们被绑架，沦为了牺牲品，人体实验对象。一个日本人，
强奸上千名菲律宾女孩，却没有受到惩罚。以前我也提到过，有20个国家的名单，这20
个国家的人民其实都是受害者。现在他们把矛头对准中国，或许仅仅是因为我揭示了他
们图害世界人民的内幕，而我是一个中国人的缘... 阅读全帖 |
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发帖数: 1 | 42 12月27日 为什么我要替中国辩护
我要替中国辩护，并不是因为我是一个中国人，而是因为我知道中国就和这世界上绝大
数的国家一样，虽然有很多丑陋的现象，但是他们是受害者。就
象这个犯罪集团里很多的人一样，他们来自各种种族，他们可能充当了工具，但他们不
是制造这一切，谋划这一切的人。虽然经常会暴露中国产品出现问题。但要知道中国是
世界工厂，他们只是打工者，他们只是按照各种雇主提供的配方来生产，他们并不知道
他们会产生怎样的后果。或者这些工人知道后果，但他们只是奴隶，他们又如何去改变
这一切？ 所以，当我的调查不断往前推进的时候，不可避免地会涉及各国的企业，但
这并不表明是针对这个国家或这个国家的人民，而是针对一种社会现实和丑陋现象。就
拿菲律宾来说，菲律宾是一个犯罪猖獗的国家，有很多犯罪分子，但是菲律宾人民却是
这个集团的受害者，他们／她们被绑架，沦为了牺牲品，人体实验对象。一个日本人，
强奸上千名菲律宾女孩，却没有受到惩罚。以前我也提到过，有20个国家的名单，这20
个国家的人民其实都是受害者。现在他们把矛头对准中国，或许仅仅是因为我揭示了他
们图害世界人民的内幕，而我是一个中国人的缘... 阅读全帖 |
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发帖数: 1 | 43 12月28日 仔细阅读以下文章
或许这些文章可以告诉你们孩子被伤害病毒的答案。
Astellas Pharma 应该和这些人体实验有莫大的关系！
Founded 2005; 11 years ago
Headquarters 2-5-1, Nihonbashi-Honcho, Chūō-ku, Tokyo 103-8411, Japan
Key people Yoshihiko Katakana
(President and CEO)
Filariasis
From Wikipedia, the free encyclopedia
Filariasis
Life cycle of Wuchereria bancrofti, a parasite that causes filariasis
Classification and external resources
Specialty Infectious disease
ICD-10 B74
ICD-9-CM 125.0-125.9
Patient UK Filariasis
MeSH ... 阅读全帖 |
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发帖数: 1 | 45 不知道是不是玩笑。管他呢。给大家开心一笑。
Actors Needed For National Convention (Philadelphia) hide this posting
© craigslist - Map data © OpenStreetMap
1900 Market Street
(google map)
compensation: $50.00
Looking for 700 people to be utilized as actors during the National
Convention.
We currently have a number of empty seats that will need to be filled as we
are currently removing a number of people and need to refill their seats for
the remainder of the conference.
You will be paid $50.00 each night for... 阅读全帖 |
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c*****e
发帖数: 1106 | 46 还应该有12/12K bumper to bumper保修啊。
Honda Certified Program Warranty
“Remainder of original powertrain warranty plus coverage through 7 yr/100k
miles. Remainder of non-powertrain equipment warranty plus 1 yr/12,000 mile
extension.” |
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G******i
发帖数: 5226 | 47 ☆─────────────────────────────────────☆
houston9 (Look for a job) 于 (Sat Oct 29 21:03:32 2011, 美东) 提到:
Subject to Board approval and after your probationary period, you shall be
granted an option to purchase xxx shares of the Company’s common stock. The
exercise price of such shares shall be the fair market value of the stock
at the time of the grant, as determined by the Company’s Board of Directors
.
☆─────────────────────────────────────☆
springland (没经验) 于 (Sat Oct 29 21:13:35 2011,... 阅读全帖 |
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k****r
发帖数: 807 | 48 anyone's idea is welcome.
I provide mine for the question 1.
My way is like that
1. separate the file into many smaller files by this way. use (input%1000)
to decide which file to save; So each file includes some integers with same
remainder when divided by 1000.
2. read the file one by one. firstly, use hash table to save the elements of
the file. Then, check the complete list whose elements have some remainder
when divided by 1000 in this hashtable. the one not in it is the result.
Please help... 阅读全帖 |
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p*****2
发帖数: 21240 | 49 找到这题的出处了。还没看太懂。
A typical problem seen quite often is: given a string find its shortest
substring, such that the concatenation of one or more copies of it results
in the original string. Again the problem can be reduced to the properties
of the failure function. Let's consider the string
A B A B A B
and all its proper suffix/prefixes in descending order:
1 A B A B
2 A B
3 /the empty string/
Every such suffix/prefix uniquely defines a string, which after being "
inserted" in front of the given su... 阅读全帖 |
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w****y
发帖数: 56 | 50 is it the problem here?
http://community.topcoder.com/tc?module=Static&d1=tutorials&d2=
A typical problem seen quite often is: given a string find its shortest
substring, such that the concatenation of one or more copies of it results
in the original string. Again the problem can be reduced to the properties
of the failure function. Let's consider the string
A B A B A B
and all its proper suffix/prefixes in descending order:
1 A B A B
2 A B
3 /the empty string/
Every such suffix/prefix uniquely ... 阅读全帖 |
|
