发帖数: 1 | 1 【 以下文字转载自 Stock 讨论区 】
发信人: CornucopiaX (Danio,Inc.), 信区: Stock
标 题: 公司的分红到底是怎么计算的：divident
发信站: BBS 未名空间站 (Thu Aug 16 21:45:00 2018, 美东)
能不能请高手指点一下。。。 |
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G**Y
发帖数: 33224 | 2 DNC要脸吗？
Unify not divide？！Say it to BLM |
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S*******h
发帖数: 7021 | 4 It is already divided before he becomes the president. |
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c******n
发帖数: 5697 | 6 lexus sedan的人在换胎， VW tiguan 冲上去侧撞
这个也太给VW丢脸了
比newtown枪手还不如
REDWOOD CITY -- Three members of a Santa Clara family were killed in a
horrific traffic accident Friday afternoon when their car was rear-ended at
high speed by an SUV while they were trying to fix a flat tire next to the
Interstate 280 median, authorities said.
According to the San Mateo County coroner's office, Manjit Kaur, 48; her son
Manpreet Singh, 28; and daughter Jasdeep Kaur, 21, were killed in the crash
. All were pronounced dea... 阅读全帖 |
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f*********j
发帖数: 69 | 7 今天早上第一次在大路（双向四车道，不包括分出来的left/right turn lane，限速45
）上碰到了在对面方向闪着灯的校车。（如图，红圈处为校车位置）
由于我前面没车所以没法参考别人。当时的判断是因为路中间有barrier隔着所以应该
不用停。但开过去了之后从后视镜里发现在我后面的车却停了。回来后赶紧查DMV的
manual，发现在NYS哪怕是divided highway只要碰到闪着灯的校车都需要双向停车。
顺便想问下，被校车司机抄牌收到罚单的可能性大吗？ |
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t********i
发帖数: 7856 | 8 这种可能不算严格意义上的divided。很明显人是可以走过来的。
45 |
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b**********7
发帖数: 404 | 10 office cubicles/dividers for sale - $250 (Edison)
office cubicles almost new, only used few times, total together $990
Call: 732-429-2035 or 732-877-7797, if interested |
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K*****n
发帖数: 1406 | 11 rebate for mark II 是不是要求一张receipt？
Order Summary:
Your purchase has been divided into 2 orders.
Order #1 : (order will arrive in 1 shipment)
xxxx...
Order #2 : (order will arrive in 1 shipment)
printer
在一封邮件里面发给我的。请问这样能拿rebate嘛？
谢谢， 有包子！ (前2正确的...) |
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b**********7
发帖数: 404 | 13 office cubicles/dividers for sale - $250 (Edison)
office cubicles almost new, only used few times, total together $990
Call: 732-429-2035 or 732-877-7797, if interested |
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j******n
发帖数: 8 | 14 $700/ Big living room for rental/ 1 min to G*R*V subway/ New, Clean & Safe
Building
Available right now!
25 min train to Manhattan
1 min walk to Subway station *63 Dr-Rego Park* (G*R*V)
New, Clean & Safe Building
Washer & Dryer inside the APT.
Big Living room for rental in 1BR apt. (with room divider screen)
Big Balcony
Free street parking
$120/month parking lot
Share Bathroom
Share Kitchen
I am a very kind and tidy lady, just graduated, looking for a job in NYC.
Requirement: Female, clean, norm |
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f********e
发帖数: 93 | 15 that what i am asking..
google search when this stock distribute divident, but my accout cash balanc
e and the shares are still the same, i didn't trade very often, so the cash
balance is the same..
thanks any way. |
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r****n
发帖数: 309 | 16 比如在yahoo finance 里, 分红股票的 divident&yield: 1.52(4.81%),这是什么意思
，怎么计算年回报率呢？
另外，SPY的回报率怎么计算呢？
谢谢！ |
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k***t
发帖数: 276 | 17 Divide a list of numbers into group of consecutive numbers but their
original order should be preserved? e.g.
8,2,4,7,1,0,3,6
2,4,1,0,3 and 8,7,6
obviously in shortest time and space.
=========================================
看到一个comment，但不确定其中的find/union是否可以O(n)实现。
1. Identify range - One pass
2. Identify number of elements within each range - One pass
3. Fill destination array by maintaining starting positions of each range -
One pass of source array.
O(n) time and O(n) space |
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d****o
发帖数: 1055 | 18 这道题除了-n次以外，还有更好的办法吗？
Divide two integers without using multiplication, division and mod operator. |
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g*********e
发帖数: 14401 | 19 suppose
10101 divided by 11
11>110>1100 4
(10101-1100)=1001
11>110 2
(1001-110)=11
11 1
(11-11)=0
so result is 4+2+1=7 |
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p*****2
发帖数: 21240 | 20 常规题得多练呀。
public int divide(int dividend, int divisor)
{
if (divisor == 0)
throw new ArithmeticException();
long a = dividend;
long b = divisor;
boolean neg = false;
if (a < 0)
neg = !neg;
if (b < 0)
neg = !neg;
a=Math.abs(a);
b=Math.abs(b);
int c = 0;
while (b << c <= a)
c++;
int ans = 0;
while (c >= 0)
{
if (b << c <=... 阅读全帖 |
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l*********8
发帖数: 4642 | 21 我也练习一个：
// caculate a/b
int devide(int a, int b)
{
if (b==0) throw std::overflow_error("Divide by zero exception");
if (a<0) return -devide(-a,b);
if (b<0) return -devide(a,-b);
if (a
int d = 1;
while(b>0 && b<=a) {
b <<= 1;
d <<= 1;
}
b = unsigned int(b) >> 1;
d = unsigned int(d) >> 1;
int ans = 0;
while(b) {
ans += d;
a -= b;
while(b>a) {
b >>= 1;
d >>= 1;
}
}
return ans;
} |
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l*********8
发帖数: 4642 | 22 How to divide two Long integers then? |
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d****o
发帖数: 1055 | 23 这道题除了-n次以外，还有更好的办法吗？
Divide two integers without using multiplication, division and mod operator. |
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g*********e
发帖数: 14401 | 24 suppose
10101 divided by 11
11>110>1100 4
(10101-1100)=1001
11>110 2
(1001-110)=11
11 1
(11-11)=0
so result is 4+2+1=7 |
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p*****2
发帖数: 21240 | 25 常规题得多练呀。
public int divide(int dividend, int divisor)
{
if (divisor == 0)
throw new ArithmeticException();
long a = dividend;
long b = divisor;
boolean neg = false;
if (a < 0)
neg = !neg;
if (b < 0)
neg = !neg;
a=Math.abs(a);
b=Math.abs(b);
int c = 0;
while (b << c <= a)
c++;
int ans = 0;
while (c >= 0)
{
if (b << c <=... 阅读全帖 |
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l*********8
发帖数: 4642 | 26 我也练习一个：
// caculate a/b
int devide(int a, int b)
{
if (b==0) throw std::overflow_error("Divide by zero exception");
if (a<0) return -devide(-a,b);
if (b<0) return -devide(a,-b);
if (a
int d = 1;
while(b>0 && b<=a) {
b <<= 1;
d <<= 1;
}
b = unsigned int(b) >> 1;
d = unsigned int(d) >> 1;
int ans = 0;
while(b) {
ans += d;
a -= b;
while(b>a) {
b >>= 1;
d >>= 1;
}
}
return ans;
} |
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l*********8
发帖数: 4642 | 27 How to divide two Long integers then? |
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P******r
发帖数: 842 | 28 这题能用log exp做吗？能用的话code太短了。另外偷懒了，除0就返回0了。
int divide(int dividend, int divisor) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
long long x = dividend;
long long y = divisor;
if (0 == x || 0 == y)
return 0;
int sign = (x > 0 && y > 0 || x < 0 && y < 0) ? 1 : -1;
x = abs(x);
y = abs(y);
int r = exp(log(x)-log(y));
return sign*r;
} |
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l**b
发帖数: 457 | 29 public int divide(int dividend, int divisor) {
assert(divisor != 0);
if (dividend == 0) {
return 0;
}
boolean negative = false;
if ((dividend > 0 && divisor < 0) || (dividend < 0 && divisor > 0)) {
negative = true;
}
int result = 0;
long lDividend = Math.abs((long) dividend);
long lDivisor = Math.abs((long) divisor);
while (lDividend >= lDivisor) {
long d = lDiv... 阅读全帖 |
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e***s
发帖数: 799 | 30 Find the contiguous subarray within an array (containing at least one number
) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.
More practice:
If you have figured out the O(n) solution, try coding another solution using
the divide and conquer approach, which is more subtle.
想知道O(nlogn)的解法。 |
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f**********t
发帖数: 1001 | 31 我的方法如下：
int divide(int dividend, int divisor) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (divisor == 0)
return 0;
int sign = 1;
if (dividend * divisor < 0)
sign = -1;
if (dividend < 0)
dividend *= -1;
if (divisor < 0)
divisor *= -1;
int result = 0;
int tmp;
int tmpret;
while (dividend >= divisor) {
tmp = diviso... 阅读全帖 |
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d****n
发帖数: 1637 | 32 知道很无聊一个题，拿出来解闷。bit shift operator都被人玩出好多花样了。
http://stackoverflow.com/questions/11694546/divide-a-number-by-
// replaces the + operator
int add(int x, int y) {
int a, b;
do {
a = x & y;
b = x ^ y;
x = a << 1;
y = b;
} while (a);
return b;
}
int divideby3 (int num) {
int sum = 0;
while (num > 3) {
sum = add(num >> 2, sum);
num = add(num >> 2, num & 3);
}
if (num == 3)
sum = add(sum, 1);
return sum;
} |
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w**********6
发帖数: 800 | 33 请教，RTL design中，divided by 3 和 50% duty cycle怎么实现？
Hint：use two always using posedge and negedge |
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r*****e
发帖数: 146 | 34 不会啊，上来请教一下。
Given an unsorted array, how to divide them into two equal arrays whose
difference of sum is minimum in O(n) time? |
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g***j
发帖数: 1275 | 35 Divide two integers without using multiplication, division and mod operator.
这个题目怎么做呀，我用的是数学公式exp(logx - logy)
但是，large set就这一个通不过，难道这个除出来不是-1么？他说expected是0,这是
为什么？
2147483647, -2147483648 -1 0
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o**f
发帖数: 76 | 36 Line 2/3 ignore sign of dividend/divisor.
Line 5 to 12 try to remove divisor (or multiple of
divisors) from dividend, until a becomes < b.
Note that line 8 c<<=1 is bit operation and so does
line 10 ret += 1 <
Line 14 check signs of dividend/divisor, if they are
same, return ret. Otherwise, return -1 * ret.
1 int divide(int dividend, int divisor) {
2 long long a = abs((double)dividend);;
3 long long b = abs((double)divisor);
4
5 long long ret = 0;
6 while (a >= b) {
7 ... 阅读全帖 |
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z****e
发帖数: 54598 | 37 public class Solution {
public int divide(int dividend, int divisor) {
// Start typing your Java solution below
// DO NOT write main() function
if(dividend == 0) return 0;
long a = Math.abs((long)dividend);
long b = Math.abs((long)divisor);
long[] result = div(a,b);
long r = ((dividend>0&&divisor<0)||(dividend<0&&divisor>0))?-result[
0]:result[0];
return (int)r;
}
private long[] div(long a, long b){
l... 阅读全帖 |
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g***j
发帖数: 1275 | 39 class Solution {
如下的code可以过，但是有个疑问，为啥，我吧下面的long long的部分改成int，就过
不了了啊？
public:
int divide(int dividend, int divisor) {
// Note: The Solution object is instantiated only once and is reused
by each test case.
if(divisor == 1) return dividend;
if(divisor == -1) return -1*dividend;
int sign = 1;
if(dividend < 0) sign = -1*sign;
if(divisor < 0) sign = -1*sign;
long long remain = abs((long long)dividend); // ？？？
... 阅读全帖 |
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a***e
发帖数: 413 | 40 看到soulmachine的答案说
‘最简单的方法，是不断减去被除数。在这个基础上，可以做一点优化，每次把被除数
翻倍，从
而加速。’
不太懂为啥可以用这个翻倍除数来加速。看那个code也是有点晕。
int divide(int dividend, int divisor) {
// 当dividend = INT_MIN 时，-dividend 会溢出，所以用long long
long long a = dividend >= 0 ? dividend : -(long long)dividend;
long long b = divisor >= 0 ? divisor : -(long long)divisor;
// 当dividend = INT_MIN 时，divisor = -1 时，结果会溢出，所以用long long
long long result = 0;
while (a >= b) {
long long c = b;
for (int i = 0; a >= c; ++i, c <<= 1) {
a -= c;
result += 1 << i;
}
}
... 阅读全帖 |
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a***e
发帖数: 413 | 41 通过的code，但不清楚怎么能证明这个是对的，有人知道怎么证明吗？
长除法也可以写，但没这么简洁。
class Solution {
public:
int divide(int dividend, int divisor) {
if (divisor==0) return INT_MAX;
long long r=0;
if (dividend==0) return r;
if (-1==divisor) return (-(long long int)dividend>INT_MAX? INT_MAX :
-(long long int)dividend);
long long a = dividend>=0?dividend:-(long long)dividend;
long long b = divisor>=0?divisor:-(long long)divisor;
while(a>=b)
{
long ... 阅读全帖 |
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x****3
发帖数: 62 | 42 continental divider
给一个矩阵，其中0代表海洋，其他数字代表高度，秉着水往低处流的原则，求出能够
流向任意海洋的点。 比如说
0 0 0 1 2 3 0
0 1 2 2 4 3 2
2 1 1 3 3 2 0
0 3 3 3 2 3 3
那么就要给出 第二行的4 （这有这点出发，能够找到连通道四个0的区域的一条非递增
路线），当然也有可能找不到这样的点，或者找到多个点。 |
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n***z
发帖数: 29 | 43 ok
寄信人: shuiya (shuiya)
标 题: Re: 请教G家新题 continental divider
发信站: 未名空间 (Fri Feb 6 13:40:33 2015)
来 源: 131.
不好意思一直忙别的事。是会出现这种情况但也比较容易fix，就是在能扩展的点都做
完了之后，再做所有没做过BFS的。然后还是遵循Q里面有就先做Q里的，没有就弄没做
BFS的。这个对复杂度没有影响。
还有就是这种情况平路的话能循环的依赖，也是要平路的BFS一下。
3 3 3 3 3 3
3 0 3 3 0 3
3 3 3 3 3 3
但是不管怎么说都是保证每个点BFS一次。关键是做BFS的顺序
就是说复杂度也就是O(n^2)的不变。
我是真的觉得这种题对于我来说真的很难的面试了。我只能写出我帖子里说的第一种做
法，写代码的时候应该能想出这种优化的。但一个小时肯定不够我再写这种的和处理些
特殊情况。 |
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T*****u
发帖数: 7103 | 44 Leetcode divide two integers
why ???
Submission Result: Wrong Answer
Input:
-2147483648, -1
Output:
2147483648
Expected:
2147483647
|
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C*********y
发帖数: 1424 | 45 怎么样，觉得，爸妈9月要来，条件比较简陋，在客厅，想弄一个room divider, 好看
点儿的。 |
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C*********y
发帖数: 1424 | 46 怎么样，觉得，爸妈9月要来，条件比较简陋，在客厅，想弄一个room divider, 好看
点儿的。 |
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i*****0
发帖数: 1113 | 48 【 以下文字转载自 Money 讨论区 】
发信人: ice2000 (ice), 信区: Money
标 题: 急问用Citi Divident 租车出事故， 该怎么办呢？
发信站: BBS 未名空间站 (Sat Nov 2 20:49:25 2013, 美东)
我自己只有liability insurance from Geico， 只保对方车，不保自己车。
问题：
我用citi dividend market card租车出去玩，由于我的原因追尾了别人的车 （没有吃
ticket）。关于对方的车，我给了对方我的GEIGO liability insurance info 让对方
去cliam。
我的问题是：我租的车没有买租车公司的保险，而是就是用CITI dividend card 付的
租车cost
。我的liability auto insurance是不保自己开的车的，请问现在会发生什么事情呢？
Citi
credit card会cover我租的车的修理费用吗？
谢谢帮助！！ |
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p*p
发帖数: 492 | 49 3个人share的冰箱，三个shelf比较好分，一人一格。冰箱门那里的三栏狭窄的道，如
果也向分隔成三分之一这样用，怎么隔开，有什么推荐的美观便宜的方法来分隔吗？因
为每一栏高度不同，希望每一栏都分隔成1/3，1/3，1/3。谢谢！
我唯一能想到的是用Ikea里那个分隔五斗橱的白色的divider，但那个也可能会滑动的
。 |
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H***a
发帖数: 189 | 50 just received the cash back check today with a notice.
additional %1 cash back on purchase for 90 days
6% cash back on gas, grocery and drugstore purchases.
2% cash back on all other purchases
1% cash back on all cash advance
$5 for each $1500 balance transfer
I already reached the $300 year limit on this card and started using another
divident card. I think the cash back I earn this year should carry over
to the next year, am I right? |
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