Does
E_{t-2} [ E_{t-1} [f(Y_t) | X_t] ] = E_{t-2} [f(Y_t) | X_t]
Hold? Here Y_t and X_t are solutions to SDEs and they are not independent.
Thanks!
s******k 发帖数: 6659
2
Would it be E_{t-2} [f(Y_t)] by the tower rule?
【在 L*******t 的大作中提到】 : Does : E_{t-2} [ E_{t-1} [f(Y_t) | X_t] ] = E_{t-2} [f(Y_t) | X_t] : Hold? Here Y_t and X_t are solutions to SDEs and they are not independent. : Thanks!