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Quant版 - Generate correlated unifrom random numbers?
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m******e
发帖数: 45
1
How to generate uniform [0,1] distributed random numbers with correlation
rho?
generating correlated gaussian r.vs are trivial, but it seems there is no
clean way
for uniform r.v. , any idea? thanks.
c******s
发帖数: 90
2
Please see this link below.
http://www.noise.cz/sbra/sibram02/2-Ses/Fegan.htm
In this paper, the author present a way to generated correlated uniform R.V.
Another result you may be able to use is:
If X and Y are bivariate-normal with correlation rho,
Let Ux=normcdf(X) and Uy=normcdf(Y), then
Ux and Uy are bivariate-uniform with correlation
(6/pi)*arcsin(rho/2).

【在 m******e 的大作中提到】
: How to generate uniform [0,1] distributed random numbers with correlation
: rho?
: generating correlated gaussian r.vs are trivial, but it seems there is no
: clean way
: for uniform r.v. , any idea? thanks.

m******e
发帖数: 45
3
consolas, Thanks very much! I will take a look of the link.
BTW, for the second method, is there any reference on how the correlation
(6/pi)*arcsin(rho/2) is obtained?

V.

【在 c******s 的大作中提到】
: Please see this link below.
: http://www.noise.cz/sbra/sibram02/2-Ses/Fegan.htm
: In this paper, the author present a way to generated correlated uniform R.V.
: Another result you may be able to use is:
: If X and Y are bivariate-normal with correlation rho,
: Let Ux=normcdf(X) and Uy=normcdf(Y), then
: Ux and Uy are bivariate-uniform with correlation
: (6/pi)*arcsin(rho/2).

S*****x
发帖数: 20
4
I kind of remember Hull mentioned this in his book when he discussed credit
VaR. You can check it out.

【在 m******e 的大作中提到】
: How to generate uniform [0,1] distributed random numbers with correlation
: rho?
: generating correlated gaussian r.vs are trivial, but it seems there is no
: clean way
: for uniform r.v. , any idea? thanks.

c******s
发帖数: 90
5
Essentially the correlated bi-variate uniforms generated
by the second method can be viewed as a Gaussian copula with marginal
uniform distribution. You can calculate the spearman's rho, which
is given by that formula.

【在 m******e 的大作中提到】
: consolas, Thanks very much! I will take a look of the link.
: BTW, for the second method, is there any reference on how the correlation
: (6/pi)*arcsin(rho/2) is obtained?
:
: V.

1 (共1页)
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话题: correlated话题: generate话题: uniform话题: rho话题: random