c******f
发帖数: 2144 | 1 看到这样一段代码：
for(vector::size_type ix = 0;ix != ivec.size(); ++ix, --cnt)
ivec[ix] = cnt;
为什么不写
for(int ix = 0;ix != ivec.size(); ++ix, --cnt)
ivec[ix] = cnt; | s*********t
发帖数: 1663 | 2 就是int,解决兼容性吧
【在 c******f 的大作中提到】
: 看到这样一段代码：
: for(vector::size_type ix = 0;ix != ivec.size(); ++ix, --cnt)
: ivec[ix] = cnt;
: 为什么不写
: for(int ix = 0;ix != ivec.size(); ++ix, --cnt)
: ivec[ix] = cnt;
| l******t
发帖数: 12659 | 3 因为ivect.size()是unsigned的;
size_type:
Type defined by the string and vector classes that is capable of containing
the size of any string or vector, respectively. Library classes that define
size_type define it as an unsigned type. | y**i
发帖数: 1112 | 4 这个也可以用size_t吧，我一般都写size_t
containing
define
【在 l******t 的大作中提到】
: 因为ivect.size()是unsigned的;
: size_type:
: Type defined by the string and vector classes that is capable of containing
: the size of any string or vector, respectively. Library classes that define
: size_type define it as an unsigned type.
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