c**********t
发帖数: 80 | 1 I was off line and could not join the discussion last night. But now I believe
my proof is correct. The key to the proof is that if there does not exist a
segment of length 1/n, then there does not exist a segment of length k/n, for
any integer k. This will induce a contradiction at k=n. And such a proof does
explicitly require the length of the segment being the reciprocal of an
integer. The proof does not apply to general 1/a.
In fact, now I think the above key insight can be further genera | f******k
发帖数: 297 | 2 now you convinced me this is a correct one. so both parts are
solved :)
【在 c**********t 的大作中提到】
: I was off line and could not join the discussion last night. But now I believe
: my proof is correct. The key to the proof is that if there does not exist a
: segment of length 1/n, then there does not exist a segment of length k/n, for
: any integer k. This will induce a contradiction at k=n. And such a proof does
: explicitly require the length of the segment being the reciprocal of an
: integer. The proof does not apply to general 1/a.
: In fact, now I think the above key insight can be further genera
| c***r
发帖数: 46 | 3 This one seems correct to me. :)
【在 f******k 的大作中提到】
: now you convinced me this is a correct one. so both parts are
: solved :)
|
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