w*g
发帖数: 413 | 1 I am using window.open to open a new window (named "b") from
window "a". Now I want to add another link to window "a"
which will also appear in window "b". The problem is: I
click the first link to pop-up window "b", then go back to
"a" to click the second link, the new content will be shown
in "b", but "b" won't go back to the top (still behind "a").
How to solve this problem? Thanks! | b****e
发帖数: 985 | 2
var bmouse=window.open(blahblah...);
bmouse.focus();
【在 w*g 的大作中提到】
: I am using window.open to open a new window (named "b") from
: window "a". Now I want to add another link to window "a"
: which will also appear in window "b". The problem is: I
: click the first link to pop-up window "b", then go back to
: "a" to click the second link, the new content will be shown
: in "b", but "b" won't go back to the top (still behind "a").
: How to solve this problem? Thanks!
| w*g
发帖数: 413 | 3
Thanks!
【在 b****e 的大作中提到】
:
: var bmouse=window.open(blahblah...);
: bmouse.focus();
| w*g
发帖数: 413 | 4
Another problem: If I clicked link1, link2, then back to
click link1, the window won't pop-up again. It seems only
work for unclicked links. Any idea? Thanks!
【在 b****e 的大作中提到】
:
: var bmouse=window.open(blahblah...);
: bmouse.focus();
|
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