h*l
发帖数: 19 | 1 Ok, now, in general, this is a Fredholm integral
equation of the 1st kind.
h(r) = \integral (f(r,r')*g(r')*dr') r,r' is n
dim vector.
h(r), f(r,r') is known, we want to find g(r).
For this 3-general problem, f(r,r')=0 if outside
r-3-trangle; f(r,r')=1 if inside r-3-trangle. h(r)=
0.5. Domain is the large trangle.
As we know, Fredholm operator here is a continue
linear operator, and we should find it's spectrum
to solve. Of course, practically, we just use the
technique I proposed |
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f*******d
发帖数: 12693 | 2 赢得基本上很顺利。开始倒地的时候差不多就trangle了，然后对手挣脱的时候固定住
了他的右手，想做个arm bar，力量不够，被他站起身来punch的同时顺势破了对手的防
守姿态，trangle成功。 |
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b******h
发帖数: 2715 | 3 在trangle地区房子首选的结构是不是：crawl space〉slab〉basement。google了好些
说法，都是泛泛而谈，没有地区针对性。 |
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n*********g
发帖数: 219 | 4 错。空姐老家在trangle, 在GSO的是她一别墅。 |
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c*******y
发帖数: 89 | 5 各位可否推荐一下自己的ob/gyn？（在版上搜了一下，似乎没有什么推荐的帖子。）
我自己尝试了cary这里wakemed旁边的trangle women center，算是网上评价比较不差
的一个了，但是的确如有些review说的，态度不是特别好，每次大约3、4分钟，说几句
话就要往外冲，被我叫住又问两个问题，然后倒着歉就跑了！两次visit都是如此。
多谢多谢！ |
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S*********n
发帖数: 895 | 6 seems the Ob/gyn here is not as nice/patient compared to other states. but t
hey are professional, so not worry too much; parents still need to do their
home work well
we tried the capital ob/gyn, so far so good
各位可否推荐一下自己的ob/gyn？（在版上搜了一下，似乎没有什么推荐的帖子。）
我自己尝试了cary这里wakemed旁边的trangle women center，算是网上评价比较不差
的一个了，但是的确如有些review说的，态度不是特别好，每次大约3、4分钟，说几句
话就要往外冲，被我叫住又问两个问题，然后倒着歉就跑了！两次visit都是如此。
多谢多谢！ |
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e******l
发帖数: 1416 | 7 from:
http://work.colum.edu/~cshaw/scutigera.php
Controlling Scutigera-Coleoptrata
If you are reading this page because you'd like to get rid of the centipedes
in your home, please take heed of the following warning: you will not be
rid of scutigera-coleoptrata. They do not disappear by any human means that
I know of. But I contend that for some of the reasons outlined above, maybe
that's a good thing. I may have had scutigera in several apartments, but I
never had cockroaches. So - before you ... 阅读全帖 |
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p***e
发帖数: 1318 | 8 you are right. I was first thinking of the quadralateral of OEAF,
O being the center of the trangles, which was a cyclic quadrilateral,
then made a leap of faith because the form of Ptolemy is very attractive
in terms of utilizing the knowns. Actually proving inscribing is probably
not worth it anyway since it would requires strong conditions on the angles
already.
looks like contraditicton is the way to go. analytical method should
also work. pure geometric method seems a bit tricky le. |
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x****7
发帖数: 387 | 9 如果有选择，最好不要买 Norinco SKS。真正的 Norico SKS 质量参次不齐，有些大概
算是市场上最烂的SKS。如果可以挑，买296产的五六半（带有 Trangle 26 厂标，很多
打有 Norinco 标志）。 |
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P******9
发帖数: 183 | 10 我只是猜测,因为身边有这样的例子.你老兄直爽,值得一交,以后有机会到北卡research
trangle park 来，我们切磋切磋。 |
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F*******e
发帖数: 485 | 11 豆瓣上的
此片的评论常常分为两派，一派主张用时空重叠的理论想要理清现实逻辑，一派主
张Jess的鬼魂在车祸后进行了一场幻境之旅。其实这两种解释并非互相矛盾的，即使是
幻境也是一个完整的程序也是遵循严密的内在逻辑的。
【1】关于官方解释
那么究竟有没有一个比较权威的解答？是有的，那就是Jess的确一开始就死于车祸
。
请参考这段对Christopher Smith（导演兼编剧）的采访视频：
http://www.youtube.com/watch?v=CMcHN4_bJBo
导演谈到此片是“that kind of wearied psychological story”（导演还提到他
是Memento的超级粉丝，可见此片强调心理分析），当问到他最初的概念是来自何处时，
导演说想拍一部关于：“what would it be like if you go to work and find yours
elf...already dead”的电影（如果有一天你照常去工作却发现你其实早就死了），后
来在他构筑剧本时又加入了越来越多的元素，让整个故事变得非常复杂一环套一环，但
是整体基调是不变... 阅读全帖 |
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k**L
发帖数: 3630 | 12 我觉得第一张构图很巧妙.也很复杂.但却很平衡.肯定有divider,就是男人身后的线条
和他身下的边连成一个Z字,让人一下子就注意到这个男人和妇女小孩,而男人的滑板却
和周围的对比相当强烈,这应该是framing的效果,也是leading line的效果,加强了对男
人的注意.同时妇女和小孩也是一个小构图.如果单独把妇女小孩看作一个独立的画作,
就可以看出trangular抓得很好.男人本身也是一个小构图,(golden trangle)
第二张我看出是比较简单明了的leading line.但注意桌子下的女人腿,和男人这两个
subject是通过那条贯穿整个画面的divider/leading line来联系的.而深色的墙被白色
的餐桌所截断,应该是framing 的作用吧?(看framing 第二种用法) |
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k**L
发帖数: 3630 | 13 我觉得第一张构图很巧妙.也很复杂.但却很平衡.肯定有divider,就是男人身后的线条
和他身下的边连成一个Z字,让人一下子就注意到这个男人和妇女小孩,而男人的滑板却
和周围的对比相当强烈,这应该是framing的效果,也是leading line的效果,加强了对男
人的注意.同时妇女和小孩也是一个小构图.如果单独把妇女小孩看作一个独立的画作,
就可以看出trangular抓得很好.男人本身也是一个小构图,(golden trangle)
第二张我看出是比较简单明了的leading line.但注意桌子下的女人腿,和男人这两个
subject是通过那条贯穿整个画面的divider/leading line来联系的.而深色的墙被白色
的餐桌所截断,应该是framing 的作用吧?(看framing 第二种用法) |
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c*****t
发帖数: 1879 | 14 Is there a way to change the JSlider thumb icon for individual
sliders?
I want to change 1 slider to have a triangle tip down thumb
and the other one with a trangle tip up thumb.
Any help?
Thanks. |
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c********e
发帖数: 383 | 15 1) given the taylor seirous expension of sin(t), write the most effecient pr
ogram in c/c++ to calculate the result given a t and the number of expension
unit.
2) write code to implement itoa
3) painball game. 3 participants. A 90% chance of hiting target, B 75%, C 45
%. they are initially positioned at the verties of a equal latteral trangle.
the rule is they will all roll a fair dice once and got a number. Assuming
there is no duplicates, once each one got a number, their shooting sequence
is |
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c***d
发帖数: 996 | 16 ☆─────────────────────────────────────☆
crystalike (Motivation) 于 (Sat Jan 13 11:52:34 2007) 提到:
1) given the taylor seirous expension of sin(t), write the most effecient pr
ogram in c/c++ to calculate the result given a t and the number of expension
unit.
2) write code to implement itoa
3) painball game. 3 participants. A 90% chance of hiting target, B 75%, C 45
%. they are initially positioned at the verties of a equal latteral trangle.
the rule is they will all roll a fair dice once and |
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r*******g
发帖数: 453 | 17 sc. Thanks for your information.
I have another question though ^_^
After you get the surface (of a bunch trangles), how to generate 3-D mesh for
FEM? What kind of FEA package did you use? And with it, how to incorporate the
surface information? Thanks.
specimen
FEM
sacnned
to |
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h*l
发帖数: 19 | 18 There is clearly a problem. Say, suppose (x1,x2,x3)
(x1<=x2<=x3)
is a good strategy, A will always use it since he asumes it
always
leads highest winning probability(故伎重演). Then B can just
choose
(x1+d,x2+d,x3-2d) for 100% win. So, A actually don't have a
optimzed
winning point even in propability sense. People's thinking
choosing
a point cover maximum area in the sense someone points out
in his
post before (outside of "three-trangle") is wrong! It
depends on
rival's strategy.
However, it' |
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I*****a
发帖数: 5425 | 19 Here I only consider a solution when P(d) is discrete. Don't know how to
deal with a continuous P(d). And the solution will not be unique because of
the nature of this problem.
Based on P(d), we can get the frequency of a bunch of d values to a reduced
fraction form. For example suppose we have three points on (0, 0), (1, 0)
and (0, 1). Then P(d) gives P(d = 1) / P(d = sqrt(2)) = 2:1.
We first guess the smallest number of n based on this 2:1 and the
combination number. We set n = 3 although n = ... 阅读全帖 |
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