k*******v
发帖数: 237 | 1 1.轮数的定义：举例说明
Paul,今年第一轮选的,keeper,去年第三轮,keeper轮数不变，轮数=3
Wilcox,今年第4轮选的,keeper,去年undrafted,keeper轮数不变，轮数=13
Peja,今年第6轮选的,non-keeper,轮数=infinity
Gasol,今年第7轮选的,轮数=7
Banks,今年undrafted,轮数=13
2.４个keeper的轮数之和>=27
3. Keeper must be on the FINAL roster at the end of fantasy season. (not the
regular season)
4. Keeper CANNOT be kept CONSECUTIVELY 3 times (4 years). | n****e
发帖数: 1677 | 2 I think Peja is 6-4=2 and gasol is 7-4=3
the
【在 k*******v 的大作中提到】
: 1.轮数的定义：举例说明
: Paul,今年第一轮选的,keeper,去年第三轮,keeper轮数不变，轮数=3
: Wilcox,今年第4轮选的,keeper,去年undrafted,keeper轮数不变，轮数=13
: Peja,今年第6轮选的,non-keeper,轮数=infinity
: Gasol,今年第7轮选的,轮数=7
: Banks,今年undrafted,轮数=13
: 2.４个keeper的轮数之和>=27
: 3. Keeper must be on the FINAL roster at the end of fantasy season. (not the
: regular season)
: 4. Keeper CANNOT be kept CONSECUTIVELY 3 times (4 years).
| m*********r
发帖数: 4692 | 3 no, 6 and 7
【在 n****e 的大作中提到】
: I think Peja is 6-4=2 and gasol is 7-4=3
:
: the
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