a*****n
发帖数: 439 | 1 #include
main()
{
printf("Maybe.\n");
execl("/bin/echo","echo","Always.\n",NULL);
printf("display?");
}
为什么display?不会被显示? | D****g
发帖数: 2860 | 2 man execl:
...
Each of the functions in the exec family replaces the
current process image with a new process image. The new
image is constructed from a regular, executable file called
the new process image file. This file is either an execut-
able object file or a file of data for an interpreter. There
is no return from a successful call to one of these func-
tions because the calling process image is overlaid by the
new process image.
【在 a*****n 的大作中提到】
: #include
: main()
: {
: printf("Maybe.\n");
: execl("/bin/echo","echo","Always.\n",NULL);
: printf("display?");
: }
: 为什么display?不会被显示?
| a*****n
发帖数: 439 | 3 是不是说这个main
process在执行了execl以后,线程就被替换为echo,然后结束,无论execl后面有任何代码都
不会被执行?
谢了?
【在 D****g 的大作中提到】
: man execl:
: ...
: Each of the functions in the exec family replaces the
: current process image with a new process image. The new
: image is constructed from a regular, executable file called
: the new process image file. This file is either an execut-
: able object file or a file of data for an interpreter. There
: is no return from a successful call to one of these func-
: tions because the calling process image is overlaid by the
: new process image.
| D****g
发帖数: 2860 | 4 correct.
【在 a*****n 的大作中提到】
: 是不是说这个main
: process在执行了execl以后,线程就被替换为echo,然后结束,无论execl后面有任何代码都
: 不会被执行?
: 谢了?
|
|
