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Statistics版 - linear algebra question
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话题: ab话题: idempotent话题: linear话题: symmetric
进入Statistics版参与讨论
1 (共1页)
i******n
发帖数: 839
1
A and B are idempotent, prove AB is idempotent as well, provided A and B
commute in multiplication.
Help please,
I thought A and B should also be symmetric for AB to be Idempotent.
A*******s
发帖数: 3942
2
i forget most of what i learned in linear theory, but i do remember
sometimes the matrices are assumed to be symmetric in the context about
quadratic forms.

【在 i******n 的大作中提到】
: A and B are idempotent, prove AB is idempotent as well, provided A and B
: commute in multiplication.
: Help please,
: I thought A and B should also be symmetric for AB to be Idempotent.

y*****t
发帖数: 1367
3
这。。这不是很简单吗?直接把乘积写出来就证明了~

【在 i******n 的大作中提到】
: A and B are idempotent, prove AB is idempotent as well, provided A and B
: commute in multiplication.
: Help please,
: I thought A and B should also be symmetric for AB to be Idempotent.

l*********s
发帖数: 5409
4
AB=BA --> (AB)(AB)=A(BA)A=A(AB)B=(AA)(BB)=AB
p**********l
发帖数: 1160
5
I forgot a lot too.
But I think there is a typo here.

【在 l*********s 的大作中提到】
: AB=BA --> (AB)(AB)=A(BA)A=A(AB)B=(AA)(BB)=AB
l*********s
发帖数: 5409
6
Thanks for pointing out ^__^

【在 p**********l 的大作中提到】
: I forgot a lot too.
: But I think there is a typo here.

p**********l
发帖数: 1160
7
We all make this type of mistakes from time to time, hehe.

【在 l*********s 的大作中提到】
: Thanks for pointing out ^__^
i******n
发帖数: 839
8
man, "A and B commute in multiplication" means "AB=BA".
I thought it only means, the product of AB exists.
Then it is a relief.
thanks.
English, always my pain.

【在 l*********s 的大作中提到】
: AB=BA --> (AB)(AB)=A(BA)A=A(AB)B=(AA)(BB)=AB
1 (共1页)
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相关话题的讨论汇总
话题: ab话题: idempotent话题: linear话题: symmetric