S*********g
发帖数: 5298 | 1 p(x)=n*(n - 1)(1 - (n - 1)x)^(n - 1)
L=1, n为小球数
mathematica程序：http://htsc.stanford.edu/hdchen/ball.nb
蓝线为经验公式
红条为模拟 | t******y
发帖数: 239 | 2
It was me. :-)
Actually I did this problem in this way:
(1) The system is self similar, i.e. the mechanisms in a n-ball subsystem
in a (n+1)-ball system should be the same as that of an independent n-ball
system.
(2) The probability for the first interval in a (n+1)-ball system equals a
is p1(a), with p1 being the probability function for (n+1)-ball system.
(3) The probability for the (n+1)-ball system to be of an interval of x,
p1(x),
equals the probability for the n-ball subsystem to have an
【在 S*********g 的大作中提到】
: p(x)=n*(n - 1)(1 - (n - 1)x)^(n - 1)
: L=1, n为小球数
: mathematica程序：http://htsc.stanford.edu/hdchen/ball.nb
: 蓝线为经验公式
: 红条为模拟
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