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Science版 - Re: Ask:
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1 (共1页)
P***a
发帖数: 9
1

If n=2k, the answer is (4k^4-12k^3+23k^2-27k+18)/6
If n=2k-1, the answer is (4k^3-4k^2+11k-5)k/6
So, when n=3, A=1;
4, 4
5, 11
6, 24
......
H****h
发帖数: 1037
2
把后一条件改为n=2k+1,验证到n=7还是对的。
但如果n=8,你的答案是89,而事实上是80。
问题的困难就在于有若干三线交于一点。

【在 P***a 的大作中提到】
:
: If n=2k, the answer is (4k^4-12k^3+23k^2-27k+18)/6
: If n=2k-1, the answer is (4k^3-4k^2+11k-5)k/6
: So, when n=3, A=1;
: 4, 4
: 5, 11
: 6, 24
: ......

1 (共1页)
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