Re: Tough for me, Easy for you! - Science版

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Science版 - Re: Tough for me, Easy for you!

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t***h
发帖数: 5601

f(n) = (2*[n/2]+1)!
g(n) = (2*[(n+1)/2])!
where [] is Gauss interger function
The idea is to let f(n), g(n) be alternatively larger than the other,
and keep the multiple growing.

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