G****A
发帖数: 4160 | 1 cited from C++ faq
"Unlike a pointer, once a reference is bound to an object, it can not be
reseated to another object.
....
In that sense, a reference is similar to a const pointer such as int*
const p."
我怎么觉得不对呢，还是我理解错了？ |
y*******g
发帖数: 6599 | 2 怎么不对？
【在 G****A 的大作中提到】
: cited from C++ faq
: "Unlike a pointer, once a reference is bound to an object, it can not be
: reseated to another object.
: ....
: In that sense, a reference is similar to a const pointer such as int*
: const p."
: 我怎么觉得不对呢，还是我理解错了？
|
G****A
发帖数: 4160 | 3 I tried (in g++) to bound a reference to a second object. It did not give
me any error.
【在 y*******g 的大作中提到】
: 怎么不对？
|
S**I
发帖数: 15689 | 4 Show the code.
【在 G****A 的大作中提到】
: I tried (in g++) to bound a reference to a second object. It did not give
: me any error.
|
A*********l
发帖数: 2005 | 5 reference is just another name of the object, so you can't re-bound it.
What you did is probably assign the second object to the original object
that the reference points to.
give
【在 G****A 的大作中提到】
: I tried (in g++) to bound a reference to a second object. It did not give
: me any error.
|
G****A
发帖数: 4160 | 6 That is the part confused me.
Since it mentioned in c++ FAQ "a reference is similar to a const pointer
such as int* const p.", so I thought there should be an error if I throw
following code to the compiler:
**************
int& c = a; //a, b are int variables.
int& c = b;
**************
I understand the point, but the expression in C++ FAQ here may not be
accurate.
【在 A*********l 的大作中提到】
: reference is just another name of the object, so you can't re-bound it.
: What you did is probably assign the second object to the original object
: that the reference points to.
:
: give
|
t****t
发帖数: 6806 | 7 就算挖坑也要有专业精神, 你这个显然是过不了编译的
【在 G****A 的大作中提到】
: That is the part confused me.
: Since it mentioned in c++ FAQ "a reference is similar to a const pointer
: such as int* const p.", so I thought there should be an error if I throw
: following code to the compiler:
: **************
: int& c = a; //a, b are int variables.
: int& c = b;
: **************
: I understand the point, but the expression in C++ FAQ here may not be
: accurate.
|
G****A
发帖数: 4160 | 8 什么时候大家都来这个版挖坑，买买提就牛打发了。:)
太急，打错了，应该是
**************
int& c = a; //a, b are int variables.
c = b;
**************
【在 t****t 的大作中提到】
: 就算挖坑也要有专业精神, 你这个显然是过不了编译的
|
X****r
发帖数: 3557 | 9
This is the same as a = b here. try:
printf("&a=%p, &b=%p, &c=%p\n", &a, &b, &c);
【在 G****A 的大作中提到】
: 什么时候大家都来这个版挖坑，买买提就牛打发了。:)
: 太急，打错了，应该是
: **************
: int& c = a; //a, b are int variables.
: c = b;
: **************
|
A*********l
发帖数: 2005 | 10 你这个就是重新给a赋值。
你没有办法让c成为另外一个int 的 reference，c永远只能是a的reference。
【在 G****A 的大作中提到】
: 什么时候大家都来这个版挖坑，买买提就牛打发了。:)
: 太急，打错了，应该是
: **************
: int& c = a; //a, b are int variables.
: c = b;
: **************
|
