s*****w
发帖数: 1527 | 1 say
Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
Array 2 = {1, 2, 3, 4}
how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
is there such function ? | N***m
发帖数: 4460 | 2 how about sorting the corresponding map?
【在 s*****w 的大作中提到】
: say
: Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
: Array 2 = {1, 2, 3, 4}
: how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
: is there such function ?
| c**t
发帖数: 2744 | 3 var qry = from b in Array2
select Array.IndexOf(Array1, b);
say
Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
Array 2 = {1, 2, 3, 4}
how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
is there such function ?
【在 s*****w 的大作中提到】
: say
: Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
: Array 2 = {1, 2, 3, 4}
: how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
: is there such function ?
| s*****w
发帖数: 1527 | 4 兄弟，你牛！
【在 c**t 的大作中提到】
: var qry = from b in Array2
: select Array.IndexOf(Array1, b);
:
: say
: Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
: Array 2 = {1, 2, 3, 4}
: how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
: is there such function ?
| l********f
发帖数: 149 | 5 Linq just looks fancy, underneath the hood it still doing two foreach loop and complexity for this algo is O(n2).
Correct me if i am wrong.
【在 c**t 的大作中提到】
: var qry = from b in Array2
: select Array.IndexOf(Array1, b);
:
: say
: Array 1 = {1, 3, 2, 4}, idx is 0, 1 ,2 3
: Array 2 = {1, 2, 3, 4}
: how do i know it's idx is actually 0, 2, 1, 3 from Array 1 ?
: is there such function ?
|
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