A******g
发帖数: 612 | 1 A C/C++ question, I know
int* foo(void) foo
will return a pointer to int type
how about
int &foo(void)
what does it return?
Thank a lot! |
N***m
发帖数: 4460 | 2 reference to int?瞎猜得，哈哈
【在 A******g 的大作中提到】
: A C/C++ question, I know
: int* foo(void) foo
: will return a pointer to int type
: how about
: int &foo(void)
: what does it return?
: Thank a lot!
|
g*********s
发帖数: 1782 | 3
not verifying its correctness. but if it's right, what does this line
mean?
【在 A******g 的大作中提到】
: A C/C++ question, I know
: int* foo(void) foo
: will return a pointer to int type
: how about
: int &foo(void)
: what does it return?
: Thank a lot!
|
N***m
发帖数: 4460 | 4 I guess he means int (*foo)(void)=foo;
【在 g*********s 的大作中提到】
:
: not verifying its correctness. but if it's right, what does this line
: mean?
|
g*********s
发帖数: 1782 | 5 self-assignment?
【在 N***m 的大作中提到】
: I guess he means int (*foo)(void)=foo;
|
N***m
发帖数: 4460 | 6 well, it is sth like:
int foo()
{
return 1;
}
int main()
{
int (*foo)(void)=::foo;
foo();
}
【在 g*********s 的大作中提到】
: self-assignment?
|
g*********s
发帖数: 1782 | 7 i turn on shadow warning and always avoid such code.
【在 N***m 的大作中提到】
: well, it is sth like:
: int foo()
: {
: return 1;
: }
: int main()
: {
: int (*foo)(void)=::foo;
: foo();
: }
|
N***m
发帖数: 4460 | 8 that's for sure. the demo code is to just try to figure out what lz means.
【在 g*********s 的大作中提到】
: i turn on shadow warning and always avoid such code.
|
