l***e
发帖数: 50 | 1 我有一个问题，如果我扫描一个信号峰，然后fit这个峰。第一次，我得到峰的中心频
率x1,fitting error是delta x1.反复扫描6次，那么average x=(x1+x2+x3+x4+x5+x6)/
6.或者用fitting error的平方倒加weight算weighted average.那么average x的误差
怎么算呢？fitting error要比standard deviation of (x1,x2,x3,x4,x5,x6)要小，是
不是应该是两个的卷积？ | l***e
发帖数: 50 | | w*******e
发帖数: 83 | 3 f(x)=N(x1,e1)*N(x2,e2)...N(x6,e6), where N(xi,ei)is the gaussian
distribution;Simplify the expression, you will get the probability
distribution of the peak position, which should be also a gaussian
distribution. The mean of the simplified gaussian distribution is the
average, and the error of the gaussian distribution is the error of the
average. |
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