o**a
发帖数: 86 | 1 Folks, thanks for your time first!
function f = x.cos(a)**2 + y.cos(b)**2 + z.cos(c)**2
I know x > y > z. a, b, c are the angles between a vector and x, y, z axes
of a cartesian coordinate respectively.
If written in nutation and azimuthal angles,
f = x.sin(theta)**2.cos(phi)**2 + y.sin(theta)**2.sin(phi)**2 + z.cos(theta)
**2.
This vector is undergoing random re-orientation, i.e, the probability
density at (theta, phi) position is 1/(4pi)*sin(theta).
It is easy to see that z <= f <= x. Is th |
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