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NCAA版 - OSU needs 35 voters: Math of being No.2 team
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话题: voters话题: oklahoma话题: state话题: osu话题: bcs
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1 (共1页)
U*******1
发帖数: 1565
1
OSU needs 35 voters: Math of being No.2 team:
BCS Ranking = Harris/3+ coach/3+Computer/3
Oklahoma State=2 in computer
Alabama =3 in computer
If (1/4 voters of 174 voters: Oklahoma State=2 AND 3/4 voters of 174 voters
: Oklahoma State=3) then Oklahoma State=2 in BCS
Before, 9.5/10 of voters: Alabama =2
1/4 voters =44 voters.
So really Oklahoma State only needs 35 more voters to change from Alabama to
Oklahoma State.
So the question is whether Oklahoma State can take away 35 voters to become
no. 2 in BCS
w*****p
发帖数: 450
2
只要1/4都不到?那估计没戏了
U*******1
发帖数: 1565
3
The possible success of Bama is to thank Stanford, who will take away some
voters from OSU, but may not from Bama
S**********e
发帖数: 852
4
似乎不是这么算的...
BCS计算机排名是6个排名里面去除最高最低剩下4个的平均数

voters
to
become

【在 U*******1 的大作中提到】
: OSU needs 35 voters: Math of being No.2 team:
: BCS Ranking = Harris/3+ coach/3+Computer/3
: Oklahoma State=2 in computer
: Alabama =3 in computer
: If (1/4 voters of 174 voters: Oklahoma State=2 AND 3/4 voters of 174 voters
: : Oklahoma State=3) then Oklahoma State=2 in BCS
: Before, 9.5/10 of voters: Alabama =2
: 1/4 voters =44 voters.
: So really Oklahoma State only needs 35 more voters to change from Alabama to
: Oklahoma State.

B*****t
发帖数: 3012
5
計算機將Cowboys排第二應該沒啥懸念
之前Cowboys和Tide一半對一半吧
但是這場Cowboy說贏球基本上超Tide無懸念
只要有1/4的人類投票者投Cowboys就夠了

【在 S**********e 的大作中提到】
: 似乎不是这么算的...
: BCS计算机排名是6个排名里面去除最高最低剩下4个的平均数
:
: voters
: to
: become

1 (共1页)
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话题: voters话题: oklahoma话题: state话题: osu话题: bcs