w*******i 发帖数: 525 | 1 x1*x2=c1
x2*x3=c2
x3*x4=c3
x4*x1=c4
x1,x2,x3,x4的循环乘积为c1,c2,c3, c4,求x1,x2,x3,x4
对于更普通的多元二次方程组,有没有数值解法? | d*****1 发帖数: 1837 | | j******n 发帖数: 271 | 3 taking logarithm on both sides for all equations turns the set to a a set of
linear equations, with coefficients in C (some may be complex numbers). |
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