o****l
发帖数: 21 | 1 Maybe we can evaluate lim{ln[(n^m)/(m^n)]}. Then we have
lim{ln[(n^m)/(m^n)]}=lim{m*ln(n)-[ln(m)]*n}
if m>1, lim{m*ln(n)-[ln(m)]*n}<0
i.e. (n^m)/(m^n)<1 and lim[(n^m)/(m^n)]=0
if 0
if -1
if m<-1, lim[(n^m)/(m^n)]=0 .
The process is not strictly correct. It is just a guess. Hopefully, it
can give you some help. |
|
