m*******r
发帖数: 3 | 1 det(Z*Z') == sum(Z.^2)
or
Z*Z' == sum(Z.^2)
just don't understand why? Any intuitive explanation? | c****n
发帖数: 2031 | 2 If Z is a row vector, these are correct. For row vector Z, the operation
Z.^2 returns another row vector with each element the square of the
corresponding element of Z. When you sum up the elements, you get exactly
Z*Z'.
【在 m*******r 的大作中提到】
: det(Z*Z') == sum(Z.^2)
: or
: Z*Z' == sum(Z.^2)
: just don't understand why? Any intuitive explanation?
| m*******r
发帖数: 3 | 3
THANK YOU FOR THE CLARIFYING!
【在 c****n 的大作中提到】
: If Z is a row vector, these are correct. For row vector Z, the operation
: Z.^2 returns another row vector with each element the square of the
: corresponding element of Z. When you sum up the elements, you get exactly
: Z*Z'.
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