w***w
发帖数: 362 | 1 有
A=[a1, a2, a3]
B=[b1, b2, b3]
C=[c1, c2, c3]
怎么生成：
[{'A':a1, 'BC':{'B':b1,'C': c1}},
{'A':a2, 'BC':{'B':b2,'C': c2}},
{'A':a3, 'BC':{'B':b3,'C': c3}}]
多谢啦！ | a*****a
发帖数: 46 | 2 import pprint
A = ['a1', 'a2', 'a3']
B = ['b1', 'b2', 'b3']
C = ['c1', 'c2', 'c3']
res = []
for i in range(3):
l1 = {}
l1['A'] = A[i]
l1['BC'] = {}
l1['BC']['B'] = B[i]
l1['BC']['C'] = C[i]
res.append(l1)
pprint.pprint(res)
不知道理解的对不对，觉得说的有点模糊
【在 w***w 的大作中提到】
: 有
: A=[a1, a2, a3]
: B=[b1, b2, b3]
: C=[c1, c2, c3]
: 怎么生成：
: [{'A':a1, 'BC':{'B':b1,'C': c1}},
: {'A':a2, 'BC':{'B':b2,'C': c2}},
: {'A':a3, 'BC':{'B':b3,'C': c3}}]
: 多谢啦！
| w***w
发帖数: 362 | 3
对的
【在 a*****a 的大作中提到】
: import pprint
: A = ['a1', 'a2', 'a3']
: B = ['b1', 'b2', 'b3']
: C = ['c1', 'c2', 'c3']
: res = []
: for i in range(3):
: l1 = {}
: l1['A'] = A[i]
: l1['BC'] = {}
: l1['BC']['B'] = B[i]
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