r**c 发帖数: 30 | 1 You have 5 unknown numbers. There are 10 options in selecting two out of
these five. Sum each of those two together, thus you have 10 numbers. You're
given these, find the original 5 numbers. |
d**e 发帖数: 6098 | 2 应该可以这样
(x1 + x2 + x3 + x4 + x5) * 4 = 10个数的和
已经
x1 + x2 = ..
x3 + x4 = ..
所以解出x5,然后其它就出来了
re
【在 r**c 的大作中提到】 : You have 5 unknown numbers. There are 10 options in selecting two out of : these five. Sum each of those two together, thus you have 10 numbers. You're : given these, find the original 5 numbers.
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r**c 发帖数: 30 | 3 不知到哪个是x1+x2, x3+x4. 只给你10个数。有可能取到x1+x2, x2+x3.
【在 d**e 的大作中提到】 : 应该可以这样 : (x1 + x2 + x3 + x4 + x5) * 4 = 10个数的和 : 已经 : x1 + x2 = .. : x3 + x4 = .. : 所以解出x5,然后其它就出来了 : : re
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d**e 发帖数: 6098 | 4 明白,再回去想想。。。
【在 r**c 的大作中提到】 : 不知到哪个是x1+x2, x3+x4. 只给你10个数。有可能取到x1+x2, x2+x3.
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c*****r 发帖数: 214 | 5 假设5个数从小到大是x1...x5
假设10个和从小到大分别是s1,...s10
x1+...x5=(s1+...+s10)/4
另外可以知道s1=x1+x2,s10 = x4+x5
然后就可以得到x3
然后由s2 = x1+x3,
s9 = x3+x5
可解x1,x5
re
【在 r**c 的大作中提到】 : You have 5 unknown numbers. There are 10 options in selecting two out of : these five. Sum each of those two together, thus you have 10 numbers. You're : given these, find the original 5 numbers.
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l*********8 发帖数: 4642 | 6 re这个
【在 c*****r 的大作中提到】 : 假设5个数从小到大是x1...x5 : 假设10个和从小到大分别是s1,...s10 : x1+...x5=(s1+...+s10)/4 : 另外可以知道s1=x1+x2,s10 = x4+x5 : 然后就可以得到x3 : 然后由s2 = x1+x3, : s9 = x3+x5 : 可解x1,x5 : : re
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