r**c
发帖数: 30 | 1 You have 5 unknown numbers. There are 10 options in selecting two out of
these five. Sum each of those two together, thus you have 10 numbers. You're
given these, find the original 5 numbers. |
d**e
发帖数: 6098 | 2 应该可以这样
(x1 + x2 + x3 + x4 + x5) * 4 = 10个数的和
已经
x1 + x2 = ..
x3 + x4 = ..
所以解出x5，然后其它就出来了
re
【在 r**c 的大作中提到】
: You have 5 unknown numbers. There are 10 options in selecting two out of
: these five. Sum each of those two together, thus you have 10 numbers. You're
: given these, find the original 5 numbers.
|
r**c
发帖数: 30 | 3 不知到哪个是x1+x2, x3+x4. 只给你10个数。有可能取到x1+x2, x2+x3.
【在 d**e 的大作中提到】
: 应该可以这样
: (x1 + x2 + x3 + x4 + x5) * 4 = 10个数的和
: 已经
: x1 + x2 = ..
: x3 + x4 = ..
: 所以解出x5，然后其它就出来了
:
: re
|
d**e
发帖数: 6098 | 4 明白，再回去想想。。。
【在 r**c 的大作中提到】
: 不知到哪个是x1+x2, x3+x4. 只给你10个数。有可能取到x1+x2, x2+x3.
|
c*****r
发帖数: 214 | 5 假设5个数从小到大是x1...x5
假设10个和从小到大分别是s1，...s10
x1+...x5=(s1+...+s10)/4
另外可以知道s1=x1+x2,s10 = x4+x5
然后就可以得到x3
然后由s2 = x1+x3,
s9 = x3+x5
可解x1，x5
re
【在 r**c 的大作中提到】
: You have 5 unknown numbers. There are 10 options in selecting two out of
: these five. Sum each of those two together, thus you have 10 numbers. You're
: given these, find the original 5 numbers.
|
l*********8
发帖数: 4642 | 6 re这个
【在 c*****r 的大作中提到】
: 假设5个数从小到大是x1...x5
: 假设10个和从小到大分别是s1，...s10
: x1+...x5=(s1+...+s10)/4
: 另外可以知道s1=x1+x2,s10 = x4+x5
: 然后就可以得到x3
: 然后由s2 = x1+x3,
: s9 = x3+x5
: 可解x1，x5
:
: re
|
