S**Y
发帖数: 136 | 1 a list of words, given one word, such as "sun", get all the words which
contains all the characters of "sun" in the list.
这个，板上的题目，看有大虾说以前讨论过？谁能给个思路？谢谢。 | r**u
发帖数: 1567 | 2 就直接搞个array[26]，每个array[word[i]]++，然后check array['s'], array['u'],
array['n']是不是 > 0。
O（(k + m) * n), len(word) = m, len(pattern) = k, num(words) = n。
【在 S**Y 的大作中提到】
: a list of words, given one word, such as "sun", get all the words which
: contains all the characters of "sun" in the list.
: 这个，板上的题目，看有大虾说以前讨论过？谁能给个思路？谢谢。
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