w*r
发帖数: 64 | 1 需要用一个简单的math expression parser。类似于做：
f(x1, x2,... xn) = (a1x1 + x2 *x3)*a2 -x4 ..
基本上都是四则运算。有没有什么open source的上手就可以用的library？谢谢！ | m******t
发帖数: 2416 | 2
antlr? It's fairly straightfoward.
【在 w*r 的大作中提到】
: 需要用一个简单的math expression parser。类似于做：
: f(x1, x2,... xn) = (a1x1 + x2 *x3)*a2 -x4 ..
: 基本上都是四则运算。有没有什么open source的上手就可以用的library？谢谢！
| F****n
发帖数: 3271 | 3 Why not use Rhino, hoho.
【在 m******t 的大作中提到】
:
: antlr? It's fairly straightfoward.
| c*****t
发帖数: 1879 | 4 No need to use antlr. My CookCC is smaller, faster and better :)
In fact, operator precedence is the worst nightmare for LL parsers
such as antlr.
CookCC even comes with a calculator example (well, a mini script
interpreter of a few hundred lines) that you just need to do minor
modifcations:
http://code.google.com/p/cookcc/source/browse/trunk/tests/javaap/calc/Calculator.java
【在 m******t 的大作中提到】
:
: antlr? It's fairly straightfoward.
| w*r
发帖数: 64 | 5 thanks!
永远向唐僧大师学习!
【在 c*****t 的大作中提到】
: No need to use antlr. My CookCC is smaller, faster and better :)
: In fact, operator precedence is the worst nightmare for LL parsers
: such as antlr.
: CookCC even comes with a calculator example (well, a mini script
: interpreter of a few hundred lines) that you just need to do minor
: modifcations:
: http://code.google.com/p/cookcc/source/browse/trunk/tests/javaap/calc/Calculator.java
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