g**********y
发帖数: 14569 | 1 I find this annoyance in ArrayList/HashSet/HashMap...
If I want to loop through iterator and delete some elements on condition, I
have to do it:
1. Loop through iterator and find all elements satisfy condition, save them
in a collection.
2. Delete temp collection elements from original collection.
I have to do two steps because iterator can't be broken during loop. Is
there a better/simpler way to do this? I have no limitation on the data
structure.
Thanks. | g*****g
发帖数: 34805 | 2 This is probably the best practice anyway, you know
delete one item at a time from an Array can be N times
slower than what you are doing here.
I
them
【在 g**********y 的大作中提到】
: I find this annoyance in ArrayList/HashSet/HashMap...
: If I want to loop through iterator and delete some elements on condition, I
: have to do it:
: 1. Loop through iterator and find all elements satisfy condition, save them
: in a collection.
: 2. Delete temp collection elements from original collection.
: I have to do two steps because iterator can't be broken during loop. Is
: there a better/simpler way to do this? I have no limitation on the data
: structure.
: Thanks.
| m******t
发帖数: 2416 | 3 You can certainly do iterator.remove() while in the loop. That's what
AbstractCollection.removeAll does anyway.
I
them
【在 g**********y 的大作中提到】
: I find this annoyance in ArrayList/HashSet/HashMap...
: If I want to loop through iterator and delete some elements on condition, I
: have to do it:
: 1. Loop through iterator and find all elements satisfy condition, save them
: in a collection.
: 2. Delete temp collection elements from original collection.
: I have to do two steps because iterator can't be broken during loop. Is
: there a better/simpler way to do this? I have no limitation on the data
: structure.
: Thanks.
|
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