b**j 发帖数: 20742 | 1 Shonne Greene - 2009 Round 7 (count as 2010 round 6)
Percy Harvin - 2010 Round 3 (2010 round 3)
加起来是9, >7, 合法。 |
R*********s 发帖数: 132 | 2 我是这么理解的,好象是应该算2011的轮次。所以
Shonne Greene - 2009 Round 7 (count as 2011 round 5)
Percy Harvin - 2010 Round 3 (2011 round 2)
5+2 = 7, 所以illegal。
如果我理解不对,告诉我一声。我暂时先留这三个人,如果明天3:00pm EST之前没有
confirm,我就drop percy harvin了。 |
m*********s 发帖数: 354 | 3 I think it counts like this.
Count as 2010 rounds.
2009 Rd 7 = 2010 Rd 6.
2010 Rd 3 = 2010 Rd 3.
Total: 9 > 7. Eligible. |
J**e 发帖数: 15008 | 4 不是把10得-1,09得-2,你不能keep去年得第一轮,前年得第二轮
【在 m*********s 的大作中提到】 : I think it counts like this. : Count as 2010 rounds. : 2009 Rd 7 = 2010 Rd 6. : 2010 Rd 3 = 2010 Rd 3. : Total: 9 > 7. Eligible.
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b**j 发帖数: 20742 | 5 规则是keeper去年draft轮次和必须大于7. 不能keep last year 1st round.
greene = 6 (2009 7, count as 2010 6)
harvin = 3
减一仅限于连续第二次keep a player.
so percy is legal
【在 R*********s 的大作中提到】 : 我是这么理解的,好象是应该算2011的轮次。所以 : Shonne Greene - 2009 Round 7 (count as 2011 round 5) : Percy Harvin - 2010 Round 3 (2011 round 2) : 5+2 = 7, 所以illegal。 : 如果我理解不对,告诉我一声。我暂时先留这三个人,如果明天3:00pm EST之前没有 : confirm,我就drop percy harvin了。
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