d****o
发帖数: 1112 | 1 另外一个site的hardware engineer
号称有30年经验，开口闭口my expertise的那种
做一个LDO
3.3V to 1.8V, 1A
他老人家不知道从3.3V需要多少电流
well, he gives a efficiency first, 65%. don't ask me why he didn't culculate
it by Vou/Vin.
Then he figured out input current should be
I in = I out / efficiency.... | c****n
发帖数: 21367 | 2 不知道LDO是啥的软件工程师打酱油问一下
这个难道服从3.3/x = 1.8/1？有损耗吧？
科普一下正确答案吧 :)
culculate
【在 d****o 的大作中提到】
: 另外一个site的hardware engineer
: 号称有30年经验，开口闭口my expertise的那种
: 做一个LDO
: 3.3V to 1.8V, 1A
: 他老人家不知道从3.3V需要多少电流
: well, he gives a efficiency first, 65%. don't ask me why he didn't culculate
: it by Vou/Vin.
: Then he figured out input current should be
: I in = I out / efficiency....
| d****o
发帖数: 1112 | 3 LDO = Low Dropout Regulator, linear
I (in) = I (out) + I (q)
but Iq is really low around 40uA so normally we don't count it.
efficiency is about V(out)/V(in) if eliminate Iq.
yes LDO has pretty big loss, Ploss=(V(in)-V(out))*Iload
hehe
【在 c****n 的大作中提到】
: 不知道LDO是啥的软件工程师打酱油问一下
: 这个难道服从3.3/x = 1.8/1？有损耗吧？
: 科普一下正确答案吧 :)
:
: culculate
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