b******g
发帖数: 669 | 1 All set cares uniqueness and equals() determine whether two object are
identical.
但是我test 了下
import java.util.HashSet;
public class testT {
private String name;
public testT(String name){
this.name=name;
}
public boolean equals(Object o){
if(!(o instanceof testT))return false;
testT person=(testT)o;
return person.name.equals(this.name);
}
public static void main(String[] args){
HashSet hs=new HashSet();
testT p1= new testT("jing");
... 阅读全帖 |
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s******r
发帖数: 1524 | 2 data testt;
input id $3. cat val ;
datalines;
aaa 1 123
aaa 2 456
aaa 9 789
bbb 1 235
bbb 9 666
ccc 1 124
ccc 2 675
ccc 3 222
ccc 9 111
;
run;
proc sort data=testt;by id;run;
data testt_new;merge testt testt(where=(cat9=9) rename=(val=val9 cat=cat9));
by id;
drop cat9;
run;
ID |
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N****g
发帖数: 5172 | 4 ☆─────────────────────────────────────☆
DVD209 (dvd209) 于 (Mon Mar 30 17:49:03 2009) 提到:
test |
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w*****3
发帖数: 16 | 5 来自主题: Immigration版 - testt test |
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r***y
发帖数: 4379 | 8 跟 hashcode 没关系, 你的 equals() 方法实现错误
的 equals() 中 -- return person.name.equals(this.name);
比较的就是 string pool 中的静态string "jing"
你两次new testT 都指向同一个 string object
当然 equals() 是 true
另外, 即使你 new String("jing") 两次, 用 string 的equals 还会是 true
因为 String 的 equals 在比较它内涵的 char[]
are |
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s******r
发帖数: 1524 | 9 not sure what you want.Try
data test1 test2(keep=idx);set test;
idx=_n_;
if **** then output test2;
else output test1;
run;
data test2;set test2;
idx=.;
run;
data testt;set test1 test2(in=in2);
drop idx;
run;
在 hehehehe (入了大圣教，心中充满喜乐) 的大作中提到: 】 |
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m*********k
发帖数: 10521 | 10 [HongKong] pricess2008 Nov 2 ● 恭祝HK新斑竹板斧上任，发100个包纸同乐*^_
^*
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