Implement an algorithm to sort a linked list. Why did you pick the method
you did? Now do it in O(n) time.
how to get O(n)???
The famous sort algorithms are all O(nlog(n))
thanks a lto!
Hi, How to Sort XML Records in Visual Basic?
LZ编程为菜鸟级别, 请求immediate帮助, codes越详细越好, 可以酬谢上百包子。
Here I want to sort this xml file using the element .
My sample xml:
Code:
How about sort from right to left?
I mean first sort by edu, com, then by university name, then by deptname.
Like:
yahoo.com
cs.mit.edu
ee.mit.edu
cs.purdue.edu
...
i found online that the lysate needs to be pre-filtered with 70um mesh
before sorting.
if the aggregates are smaller than 70um (say 60um), is it possible to sort?
do not use your staining buffer with nan3 if you want to sort cells, just
use pbs with 5% fcs or HBSS with 5% fcs; large volume wash once. sort cells
into tube with fcs
depending on your rules. For example, you can sort by the length of vectors,
a1 = 1^2 + 1^2 + 1^2 + 1^2 + 4^2, etc. You can also look for their spatial
distribution. We have many software for high-content screenings that can do
it. It's not sorting though
【 以下文字转载自 Science 讨论区,原文如下 】
发信人: kingforever (蛋糕屎), 信区: Science
标 题: Anybody tried sorting algorithm from NR?
发信站: The unknown SPACE (Mon Apr 22 21:03:33 2002) WWW-POST
i tried sort2(n, a, b), which sorts a while re-arranging b. doesn't seem to
work. anybody else has the same problem?
去面試:
被問到how to sort a very long list?
(好像還不能佔用太多Memory)...
我的回答是: 把這個long list 截斷成幾段, 分別在並行運算中同時分別sort。
然後讀出每截的第一個元素, 比較,打印出最小值;再讀出下一個, 比較, 打印出
下一個最小值。。。
(請勿見笑,非計算機major)
不知答的對不對?
謝謝!
none of the above provides any actionable solution.
you should try to index the table before sorting to reduce the demand for
resources.
by the way, did you add "sortsize = max" in the sort procedure?
Try this~ It should work well no matter you have 18 or 16 obs.
DATA temp;
SET test;
BY input outcome;
IF FIRST.outcome THEN n=1;
ELSE n+1;
RUN;
PROC SORT DATA=temp OUT=sorted(DROP=n);
BY input n outcome;
RUN;
data Test;
input input $ outcome $ @@;
datalines;
A 0 A 0 A 0
A 1 A 1 A 1
A 2 A 2 A 2
B 0 B 0 B 0
B 1 B 1 B 1
B 2 B 2 B 2
;
run;
proc sort data=test;
by input outcome;
run;
data test2; set test;
input class @@;
cards;
1 2 3 1 2 3
1 2 3 1 2 3
1 2 3 1 2 3
;
run;
proc sort data = test2;
by input class;
run;
我忘了如何把一个dataset中的三个变量中的两个存到另外一个dataset中了。
可以考虑用sql.
how to avoid changing the raw dataset when you work on proc sort?
精华区里sas programmer的一个问题,不晓得该怎么回答。
changing raw data set是指什么呐? sort了,当然顺序就变了,但是其它还会改变什
么吗?
Do someone think it is feasible to sort a matrix (1M rows x 100 columns) for
each row in GPU? We keeping the repeating sorting every day and want to
know whether the performance could be improved to 10X or 20X faster (
Currently we just bought a server with 8 GPU K40).
please refer https://solarianprogrammer.com/2013/02/04/sorting-data-in-
parallel-cpu-gpu/
In my opinion, cpu should be fast enough for the size if the sort alg and
implementation is correct. CPU-GPU data copy is a big overhead for such a
task
https://twitter.com/ScienceInsider/status/1241912988996698114
ScienceInsider @ScienceInsider
NEW: Tony Fauci talks with @sciencecohen today: "Well, I'm sort of exhausted
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Given three sorted arrays, A, B, C, each of length n (assume odd), with all
3n elements distinct, find the median of the 3n elements.
O(n) time is easy to do. Is there an O(logn) time algorithm?
basic idea, for three sorted arrays of A_1, A_2, A_3 (arbitratry length), (
assume you already know the smallest n_1 numbers and largest n_2 number),
find the longest one and choose the medium, say K in A_1, then find K's
position in all other two. Now you know K's position in all 3n, if it is <
3n/2 then the mediam then update to exclude all numbers smaller than K in
three arrays, and update n_1 = n_1 + all numbers smaller than K. recursion
then
so every time, you reduce the size at least by 5/
guys,
I have write a C++ code for rotated sorted array, help me to check which
part need optimize
{7,8,9,10,11,12,1,2,3,4,5,6};
int CQuesionts::BinarySearch2(void)
{
/*
the array like
7 8 9 10 11 12 1 2 3 4 5 6, search x
*/
int x = 2;
int len = 12;
int data[]= {7,8,9,10,11,12,1,2,3,4,5,6};
int start = 0;
int end = 11;
int mid = 0;
int find = 0;
std::cout << "find " << x << std::endl;
for(int i =0 ; i < log((double)len) +1; ++i)
{
mi
Given a sorted list of N integers that has been rotated an unknown number of
positions, e.g., 15 36 1 7 12 13 14
design an algorithm to determine if a given integer is in the list