m**D
发帖数: 134 | 1 I defined it as \addots.
\def\addots {{
\settowidth {\wid} {$\ddots$}
\settoheight {\hei} {$\ddots$}
\raisebox{.07\hei}{\makebox[0.3\wid]{.}}
\raisebox{0.27\hei}{\makebox[0.3\wid]{.}}
\raisebox{0.46\hei}{\makebox[0.3\wid]{.}} }} |
|
a*****r
发帖数: 443 | 2 \begin{tabular}
{ccccc} \hline \raisebox{-1.50ex}[0cm][0cm]{cur\_sta}&
\multicolumn{3}{p{90pt}}{\centering{next\_sta}} &
\raisebox{-1.50ex}[0cm][0cm]{output} \\
\cline{2-4}
&
$x=1$& $x=2$& $x=3$& \\\hline
\end{tabular} |
|
A*r
发帖数: 22 | 3 \raisebox{-1ex}{\underline{\raisebox{1ex}{text...}}}
思路可能比贾土 |
|
T*******n
发帖数: 493 | 4 I couldn't find an easier way.
\documentclass{minimal}
\usepackage{amsmath}
\begin{document}
\noindent
Equation~\eqref{eqn} includes Equations~\eqref{eqna} and~\eqref{eqnb}:
\begin{subequations}
\label{eqn}
\begin{alignat}{3}
&\smash{%
\raisebox{-0.5\baselineskip}%
{$\displaystyle |x|= \left\{
\vphantom{\begin{gathered}x\\x\end{gathered}}%
\right.$}%
}
& & x, &\quad &x\ge0; \label{eqna} \\
& & &{-}x, &\quad &x<0. \label{eqnb}
\end{alignat}
\end{su |
|
