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发帖数: 18 | 1 我的方程如下：
P=f1(e, de/dt, dphai/dt,theta) (关系式已知)
WX=Integrate (P*cos(theta)), theta varies among[0, 2*pi]
WY=Integrate (P*sin(theta)), theta varies among[0, 2*pi]
Fcos(phai)=WX(e,de/dt,dphai/dt)+m*(d2e/d2t)-m*e*(dphai/dt)*(dphai/dt) (1)
Fsin(phai)=WY(e,de/dt,dphai/dt)+m*e*(d2phai/d2t)+2*m*(de/dt)*(dphai/dt) (2)
Objective: Solve (1) and (2) for e(t) and phai(t).
Known: e(0)=0.5, e(2*pi)=0.5, phai(0)=0.5, phai(2*pi)=0.5,
de and dphai need to be assumed.
麻烦讲讲求解的步骤。多谢。 |
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发帖数: 18 | 2 我的方程如下：
U=2*Sin(alpha*t)
P=f1(e, de/dt, dphai/dt,theta,U) (关系式已知)
WX=Integrate (P*cos(theta)), theta varies in[0, pi]
WY=Integrate (P*sin(theta)), theta varies in[0, pi]
Fcos(phai)=WX(e,de/dt,dphai/dt)+m*(d2e/d2t)-m*e*(dphai/dt)*(dphai/dt) (1)
Fsin(phai)=WY(e,de/dt,dphai/dt)+m*e*(d2phai/d2t)+2*m*(de/dt)*(dphai/dt) (2)
Objective: Solve (1) and (2) for e(t) and phai(t).
Known: F, m,
Initial conditions: e(0)=0.5, phai(0)=0.5, de and dphai are assumed to be
zero.
My approa |
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G*********o
发帖数: 49669 | 3 恩，不错，喜欢泰国phai thai吗？
很好吃，还要了一个越南春卷。 |
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