|
W****t
发帖数: 8270 | 2 阿姨我爱死你了
居然找到1个在垃圾箱
Coupon Total: $120.00
lol |
|
g****o
发帖数: 547 | 3 coupon的要求写着是不能和其他coupon合用啊.
staple实际不管？
Minimum HP printer purchase requirement of $199 must be met with purchases
to which no other coupon or instant savings offer applies. |
|
|
l**t
发帖数: 10440 | 5 All sent, Please check your email!
***Full for this round,thanks for your interest***
Baozi is welcome if you think it is good
Bricks/Tomatoes/Eggs are also welcome if you thinks it is not good
enough :-)
--------------------------------------
方便Amazon扫货用,前20免费试用,请附上email
***Feature List***
1)Strong encryption: NO personal account password can be leaked when
your PC is misused/hacked/stolen.
2)Robust database: All Account/Product/Order information is stored in
robust databases which can survive ... 阅读全帖 |
|
z**********3
发帖数: 11979 | 6 【 以下文字转载自 PDA 讨论区 】
发信人: JustSac (置鼎), 信区: PDA
标 题: Surface Pro二月九号开卖，64G$899,128G$999，Touch Cover单卖
发信站: BBS 未名空间站 (Tue Jan 22 12:22:01 2013, 美东)
Microsoft’s transformation into a devices and services company got off to a
rocky start last October.
The first entry in the company’s ambitious foray into the hardware market,
the Surface with Windows RT, fizzled, earning tepid reviews and moderate
sales.
Now, 90 days later, Microsoft is poised to take another crack at the market,
with a second memb... 阅读全帖 |
|
N****m
发帖数: 236 | 7 Your Chance to Buy Google Glass
Hi there
When you asked us how to get Glass on this site, we told you there would be
more chances to join the Explorer Program…someday. Well, today’s the day.
The sneak peek of the Glass Developer Kit (GDK) is available now, making it
possible to build new and innovative kinds of Glassware. We’re now inviting
you, as a developer, to purchase Glass, become an Explorer, and join us in
taking the next step in developing for Glass.
Click on the purchase code be... 阅读全帖 |
|
J**S
发帖数: 25790 | 8 **WARNING** - Counterfeit Sennheiser HD598 Headphones - $25
condition: new
make / manufacturer: Sennheiser
model name / number: HD598
There seem to be a lot of counterfeit, craptastic, made-in-China Sennheiser
headphones around, all in "brand new retail packaging", so watch out. If you
're in the market for this headphone, make sure you check it carefully to
make sure you're getting the real thing. What to look for (courtesy of http://www.head-fi.org/t/705384/counterfeit-sennheiser-hd-598):
1) T... 阅读全帖 |
|
r****y
发帖数: 1437 | 9 Physics Today, November 2005
A letter from a Caltech alumni
Perhaps my most striking memory of a Feynman lecture was not of one
I attended, but of one being prepared for the class ahead of me. I was doing
my weekly lab work in the freshman physics lab. At one point, as I walked
out into the hall to get a drink of water, I heard a familiar voice coming
from the lecture room at the other end of the hall. I peeked in to discover
Feynman practicing to an empty lecture hall th |
|
X*****r
发帖数: 2521 | 10 谢谢分享！
刚才下了几个你推荐的软件，果然很方便
多谢
我也推荐个
evernote和evernote peek
挺好玩的
freebies |
|
m****1
发帖数: 736 | 11 Never as a pervert who wants to expose privacy or peek others' privacy. |
|
m*******1
发帖数: 84 | 12 Look at this:
http://www.bbcamerica.com/anglophenia/2012/08/10-things-america
Notice that British people founded both US and Australia and other colonies.
Immigrating is just part of their long history and culture.
That does not mean that UK is a bad country!! They can easily immigrate
precisely means that they are capable!! Do you want to and can you immigrate
to US?
This also supports the claim that coming to US from the UK is not impossible
.
Also, did you do any research on how many American... 阅读全帖 |
|
h******1
发帖数: 94 | 13 One needs 2 keys in order to enter the condo.
No one can be crazy enough to break 3 doors only to have a peek in my
bedroom.
Once when I entered my bedroom right after shower I smelled his body odor.
I don't lock my bedroom (I close the door) when I take shower. He has such
strong stinky body odor that the odor lingers for a while every where he
goes. |
|
s*******t
发帖数: 148 | 14 I do have bad records, as you wisely predicted. I have had several speeding
tickets, I lied to my parents about my 4th grade math scores, I took
numerous peeks on my college english teacher's hot body from different
angles....more importantly, I was penalized for most of these things and the
rest are not very significant.
Having had an affair and not feeling too much guilty is not just a minor bad
record. It is different because it challenges your ethics bottomline.
Conferssing with tears is not... 阅读全帖 |
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H******e
发帖数: 767 | 15 You should not peek his wechat account at the first place. please respect
others privacy. |
|
H******e
发帖数: 767 | 16 You should not peek his wechat account at the first place. please respect
others privacy. |
|
o****l
发帖数: 62 | 17 TV Stand （glass&metal) $25
Dutailier Luxary rocking chair/glider $150
Ikea Two-Seat Sofa with cover $40
Two Ikea Wood Beds - queen size $50 each
Ikea Changing Table with Two drawers $40
dining tale with four chairs $20
nursing stool $5
Wood Cabinet & Small Wood Shelf $6-$10
L shape study table $20
plastic storage cabinet $8 each
Laudry Cart with laudry bags $8
two bicycles $20 each
twin size mattress & box &shelf $60
two computer/study desks $15 each
are... 阅读全帖 |
|
o****l
发帖数: 62 | 18 email: b****[email protected] for a complete list.
2005 Toyota camry low mileage, low price for sale,great condition
2006 Honda Element, low mileage, low price for sale,excellent condition
big TV Stand （glass&metal) $25
Dutailier Luxary rocking chair/glider $150
Ikea Two-Seat Sofa with cover $40
Two Ikea Wood Beds - queen size $50 each
Ikea Changing Table with Two drawers $40
dining tale with four chairs $20
nursing stool $5
Wood Cabinet & Small Wood Shelf $6-$10
L shape study ta... 阅读全帖 |
|
o****l
发帖数: 62 | 19 email: b****[email protected] for a complete list.
2005 Toyota camry low mileage, low price for sale,great condition
2006 Honda Element, low mileage, low price for sale,excellent condition
big TV Stand （glass&metal) $25
Dutailier Luxary rocking chair/glider $150
Ikea Two-Seat Sofa with cover $40
Two Ikea Wood Beds - queen size $50 each
Ikea Changing Table with Two drawers $40
dining tale with four chairs $20
nursing stool $5
Wood Cabinet & Small Wood Shelf $6-$10
L shape study ta... 阅读全帖 |
|
|
M*******e
发帖数: 3792 | 21 实体卡 50 100面额的 600人民币 0.915 billpay
25面额 596 人民币0.91
电子卡及特殊面额价格
请单独咨询，谢谢
明日deal
target 9折，85折with 红卡
http://www.totallytarget.com/2016/03/10/sneak-peek-target-weekl
任意面额，任意状态（实体，电子）只要是正规的itunes卡都收，特殊面额请咨询qq
49751 o 8报价，谢谢
美元billpay （不做cash）原则上2000美元以上
欢迎加入moneycome的itunes供需交流群，群号码：251583921，群主长期收itunes（务
必提供mit id），提供打折信息及各国itunes行情 以及发红包，欢迎护士加入，同行
神医及马甲请避让，
群内价格可能更优哦。
如果你有支付宝账户，也可以自己通过支付宝国际汇款wire过来。
麻烦附上 mit id，谢谢
50 100面额的实体卡，标题价格
25面值的 比50/100的少点，
10面额的575
[email protected]/* */ (优先优先或... 阅读全帖 |
|
|
w********d
发帖数: 6 | 23 去过的人都知道，可爱岛的房价都至少在＄１５０以上。我们也是做了好多research以
后选的这个地方。review很不错。
We recently booked a condo in Kiahuna Plantation for 10 days, but our plan
changed. We can only stay for 4 days there, so Nov 10-16 is open now. The
total price including tax and fees for the 10 days stays are $1531 ($135 per
night). We can offer $100 per night for the period( Nov 10-16), and the
price also
negotiable.
You can check the link:
http://www.vrbo.com/172917
如果有兴趣， 可以联系我：
cell :４０８－４０９－３０６８
或者email： w********[email protected]
... 阅读全帖 |
|
b*****e
发帖数: 1125 | 24 Of course the programmer/quant is not that stupid, they most likely will
have level 2 data in which they can peek in and know the market depth.
out |
|
a*******7
发帖数: 131 | 25 中长期投资。
出租房，不太想考虑，因为近点的的区，房少，而且房价已经高于07/08年的peek期了
。不敢再下手了。 |
|
u****e
发帖数: 99 | 26 Agree on vanguard. Just put it in retirement target fund 2045 or whichever
year you plan to retire. Expense ratio around 0.16% I think. Set and forget
, don't peek all the time.
However, be aware if your income climbs up and exceeds roth contribution
limit, and if you want to do backdoor Roth, this rollover Ira will get in
the way for tax consequence. Try to roll it over to another 401k if you get
a chance. |
|
u****e
发帖数: 99 | 27 This. Follow MinaHarker recommendation. Don't peek, don't tweak. Choose an
allocation, set and forget. |
|
s*******e
发帖数: 174 | 28 public void postOrderTraversal(TreeNode root)
{
Stack s = new Stack();
s.push(root);
while(!s.isEmpty())
{
TreeNode node = (TreeNode)s.peek();
if(node.left != null && !node.left.visited)
s.push(node.left);
else if(node.right != null && !node.right.visited)
s.push(node.right);
else
{
System.out.print(node.value+" ");
node.visited = true;
s.pop();
}
}
|
|
c*****y
发帖数: 90 | 29 来自主题: JobHunting版 - 一道面试题 对，就是每个node从queue里面dequeue出来后它的nextRight指向queue的peek。
我现在在想，能否有recursion的方法？想了下想不出来。 |
|
s******t
发帖数: 2374 | 30 一道是给一个binary tree，按照BFS的方式
===========================
如果只是顺序打印不用换行
a
b c
e f g h
public void BFSTree(Node root){
Queue q = new LinkedList();
if(root!=null) q.offer(root);
Node next = null;
while(q.peek()!= null){
next = q.poll();
print(next.value);
if(next.left!=null) q.offer(next.left);
if(next.right!=null) q.offer(next.right);
}
}
if need start a new line:
public void BFSTree(Node root){
Queue q = new LinkedList();
|
|
h****u
发帖数: 277 | 31 gdb进process peek 下，看伊在干什么。
没有gdb，就看下进程状态，睡觉呢，run呢，还是等I/O.
再到/proc/processID里看看文件是不是打开了，还是写到别的文件里去了。 |
|
z****n
发帖数: 1379 | 32 代码
int maxPath = 0;
s.push(root);
while(!s.empty)
{
Node* n = s.peek();
if(n->left!=null&&!n->left->visited)
s.push(n->left);
else
{
if(n->right!=null&&!n->right->visited)
s.push(n->right)
else
{
Visit(n);
n->visited=true;
/* calculating path length */
if(n->left==null&&n->right==null) //leaf
{
int path = s.size();
if(path> |
|
i**********e
发帖数: 1145 | 33 我以前贴过，但不知道为什么找不回那个帖子了。
#include
#include
#include
using namespace std;
const int TAB_SPACE = 4;
void outputJSon(istream &in, int indentLevel) {
bool firstChar = true;
bool inBracket = false;
while (in) {
char c = in.get();
if (firstChar) {
cout << endl << setw(indentLevel) << c;
firstChar = false;
}
else {
cout << c;
}
if (c == '{') {
outputJSon(in, indentLevel+TAB_SPACE);
c = in.get();
assert(c == '... 阅读全帖 |
|
J*******e
发帖数: 63 | 34 1) Given a legacy server, which can service 100 requests/second, design a
proxy server to meet the growing customer request traffic. For example, the
peek traffic is grown to 125 requests/second.
2)Design a UNIX login system, log all the activity of the login users in ONE
file.
3)Given a complicated real-time distributed system, how to detect and solve
memory leak problem? no third-party tools.
4) difference between open(), fopen() and corresponding ops in UNIX. |
|
n*****g
发帖数: 16 | 35 ihasleetcode, 抱歉没有来得及回你的帖子！是的，peek（）的意思是返回top
element，如果不存在应该返回null。我还没有run 这个code，晚上我来run一下看是不
是会crash。 |
|
c***2
发帖数: 838 | 36 void tree_postorder_traversal_no_recursion (tree_node_type *root)
{
Element *top=NULL, *node, *tmp;
tree_node_type *current_node=root;
if (!root)
return;
/* push current_node into stack */
node=(Element *)malloc(sizeof(Element));
memset(node,0,sizeof(Element));
node->tree_node_ptr=current_node;
top=stack_push(top,node);
while(top) {
/* peek stack */
current_node=top->tree_node_ptr;
/* push current_node->left ... 阅读全帖 |
|
g****7
发帖数: 45 | 37 Why keyword-scanning tools are used on resumes: A recruiter's perspective
Date: November 15th, 2010
Author: Tim Heard
Category: General
Tags: Hiring, Job, Skill, Position, Tool, Candidate, Hiring Manager,
Recruitment & Staffing, Workforce Management, Productivity
0 comment(s)
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1
Toni Bowers: Recruiter Tim Heard wanted to respond to my blog about the
misuse of keywo... 阅读全帖 |
|
|
i**********e
发帖数: 1145 | 39 不是大侠，贴一贴我的代码，代码如果不好看 请多多包涵
恐怕只能 handle 以上的 sample test case。
基本思路就是递归，如果有更复杂的情况可以再慢慢改进。
#include
#include
#include
using namespace std;
const int TAB_SPACE = 4;
void outputJSon(istream &in, int indentLevel) {
bool firstChar = true;
bool inBracket = false;
while (in) {
char c = in.get();
if (firstChar) {
cout << endl << setw(indentLevel) << c;
firstChar = false;
}
else {
cout << c;
}
if (c == '{') {
outputJSon(in... 阅读全帖 |
|
i**********e
发帖数: 1145 | 40 其实不递归 代码或许会更简单些
void outputJSon(istream &in) {
bool newLine = false;
bool inBracket = false;
int indentLevel = 0;
while (in) {
char c = in.get();
if (newLine) {
cout << endl << setw(indentLevel) << c;
newLine = false;
}
else {
cout << c;
}
if (c == '{') {
indentLevel += TAB_SPACE;
newLine = true;
} else if (!inBracket && c == ',') {
newLine = true;
} else if (c == '}') {
newLine = true;
} else if (c == '[') {
... 阅读全帖 |
|
g***s
发帖数: 3811 | 41 It is very quick even for n = Integer.MAX_VALUE;
public static void main(String arg[]){
preprocess();
int n=Integer.MAX_VALUE;
System.out.println("squares sum of " + n + " : ");
for (int num : getSquaresSum(n)){
System.out.print(" " + num);
}
System.out.println("\ntotal callCount= " + callCount);
}
public static Collection getSquaresSum(int n){
Stack cur = new Stack();
Stack阅读全帖 |
|
s*****n
发帖数: 5488 | 42 二楼的说的很好啊。用stack
string removeSubstringRecursively(string s, string matchString){
struct stackElement{
char s,
int index,
}
Stack stack= new Stack();
int index = 0;
foreach (char c in s) {
if (matchString[index] == c){
stack.push(c,index++);
if (index == matchString.Length){
for( int i = 0; i < index ; i++)
stack.Pop();
index = stack.peek().index;
... 阅读全帖 |
|
s*****n
发帖数: 5488 | 43 把矩阵左边的边界删掉了。不走几个例子真找不出来。
else if (top.value > a[i]) {
int leftbound = 0;
while (!s.isEmpty() && s.peek().value>=a[i]) {
Node prev = s.pop();
leftbound = prev.x;
if (prev.value*(i-prev.x) > max) max = prev.value*(i-
prev.x);
}
s.push(leftbound, a[i]);
s.push(node); |
|
g**********y
发帖数: 14569 | 44 第8题，O(n)
public int hold(int[] a) {
Stack stack = new Stack();
int level = 0;
int total = 0;
for (int i=0; i
while (!stack.isEmpty()) {
Bar prev = stack.peek();
if (prev.height <= a[i]) {
total += (i - prev.x - 1) * (prev.height - level);
level = prev.height;
stack.pop();
}
else {
bre... 阅读全帖 |
|
g**********y
发帖数: 14569 | 45 第8题，O(n)
public int hold(int[] a) {
Stack stack = new Stack();
int level = 0;
int total = 0;
for (int i=0; i
while (!stack.isEmpty()) {
Bar prev = stack.peek();
if (prev.height <= a[i]) {
total += (i - prev.x - 1) * (prev.height - level);
level = prev.height;
stack.pop();
}
else {
bre... 阅读全帖 |
|
v***n
发帖数: 562 | 46 find all the positive numbers a smaller than N, such that
a=b^3+c^3=d^3+e^3.
It means that a should be the sum of the cube of two different pairs
another: given an iterator, with only next() and hasNext(), create a stack
with method pop() and peek() |
|
v***n
发帖数: 562 | 47 find all the positive numbers a smaller than N, such that
a=b^3+c^3=d^3+e^3.
It means that a should be the sum of the cube of two different pairs
another: given an iterator, with only next() and hasNext(), create a stack
with method pop() and peek() |
|
l****p
发帖数: 397 | 48 这是我当时的实现：
class PeekingIterator{
private Iterator it;
private Object next = null;
public PeekingIterator(Iteractor it){
this.it = it;
}
public boolean hasNext(){
return next !=null || it.hasNext();
}
public Object next(){
if(next != null)
{
Object result = next;
next = null;
return retsult;
}else{
return it.next();
}
}
public Object peek(){
if(next == null)
next... 阅读全帖 |
|
s******n
发帖数: 3946 | 49 加了重复value处理，选value相同的index最大的一个，这样可以了吧？
class PowerImpl {
static class Node {
public int index;
public int value;
int compare(Node anotherNode) {
return this.value - anotherNode.value;
}
}
PriorityQueue values;
public PowerImpl() {
values.add(new Node(2, 4));
}
public int next() {
Node n = values.pop();
int retValue = n.value;
// find all nodes with least value
// for such nodes, values*=index
// find out n: the least value node with largest index
A... 阅读全帖 |
|
f*********i
发帖数: 197 | 50 不需要两个stack，一个就可以了
就是在push的时候判断，如果当前push的是{，那么如果stack不为空就是false
如果当前的push是[，那么stack.peek只能是{或者为空，否则返回false
如果当前push(，无所谓。
接下来就是和没有优先级别一样了。 |
|
