y***6
发帖数: 46 | 1 Hi All,
I just started learning C programming. Can someone help me with the
following C code? Thanks!
------------C code starts here-------------
typedef struct {
int row;
int col;
} MATHEAD;
#define Mathead(a) ((MATHEAD *) (MATHEAD *)(a)-1))
------------C code ends here--------------
My questions are:
i) What does (MATHEAD *)(a)-1 mean? Why minus 1?
ii) What does ((MATHEAD *) (MATHEAD *)(a)-1)) return? |
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t****t
发帖数: 6806 | 2 basically i believe you put a MATHEAD structure immediately before your real
data. if A points to your real data; then macro Mathead(A) returns the
pointer to the MATHEAD right before your data.
but i don't think that macro makes sense to cast (a) twice into (MATHEAD*).
it doesn't hurt though. |
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m*******e
发帖数: 20 | 3 (i) (MATHEAD *)(a)-1 means you explictely convert pointer "a" into a MATHEAD
type pointer("a" is very likely to be a void* pointer originally), and then
make the pointer point to the memory place immediately before the current
place it does.
(ii) Not very sure about your second question. Actually I think such macro
does not make any sense...Well hope somebody can give out a more precise
answer. |
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a***y
发帖数: 2803 | 4 1个int有4个byte,所以一个struct MATHEAD就有8个字节.
(MATHEAD *)(a)-1表示的是减去一个struct单位的地址,也就是减去8个字节.
这是指针类的加减法的特殊的地方. |
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