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全部话题 - 话题: lnlnt
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i*******g
发帖数: 276
1
来自主题: Mathematics版 - lnlnt 的upper bound
请问lnlnt 有什么bound呐? 除了ct, c constant, t^p( p constant). 现在我需要证明
sqrt(2t*lnlnt)-t/2 ->-infty 当t-》infty. 谢谢谢谢哈~~
k*******l
发帖数: 69
2
来自主题: Mathematics版 - lnlnt 的upper bound
read any elementary calculus book

证明
M****i
发帖数: 58
3
来自主题: Quant版 - 问个随机积分的问题
For this question, the simplest method that I can find is to use a
representation theorem of continuous local martingale and the theorem of
iterated logarithm of Brownian motion. An advantage of this method is that
c(t) can be allowed to be stochastic. More precisely,
Let c(t) be a stochastic process and we write
f(t)=\int_0^t c(s)^2 exp(2*\int_0^s c(r)dr) ds,
g(t)=exp(-\int_0^t c(r)dr).
Assume that
i)f(t)<\infty, a.s. for every t>=0;
ii)f(t) tends to infinity when t tends to infinity.
iii)g(t)*... 阅读全帖
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