w*****r 发帖数: 92 | 1 macro code应该循环执行两次%step1 %step2,最后将结果输出到z_a
和z_b里, Step1 & 2是调用的比较复杂的code,单独运行没有问题。可是code怎么改也
不执行循环,最后只出来一个z_a.哪位前辈指点一二啊,谢谢了!
%let job=z;
%let name=a b;
%let count = %sysfunc(countw(&method));
%macro x;
%do i=1 %to &count;
%let m = %scan(&name, &i);
%let jobname = &job._&m;
%step1(jobname=&job, ...);
%step2(Jobname=&jobname, label=&m, ...);
%end;
%mend x;
用下面的code试了下就可以,难道是step1 2内部的问题?
%macro part1(jobname=, cov=);
data &job;
set eco;
keep &cov;
run;
%mend;
%macro part2(jobname=... 阅读全帖 |
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