k*****y
发帖数: 744 | 1 int main()
{
const int N = 63;
const int MAX = N + 6;
double prob[ MAX+1 ];
double ans[ MAX+1 ];
double visit[ MAX+1 ];
for( int ith=0; ith<=MAX; ++ith ){
prob[ ith ] = ( ith>=1 && ith<=6 ) ? 1./6 : 0;
ans[ ith ] = 0; visit[ ith ] = 0;
}
for( int runtime=2; runtime<=MAX; ++runtime ){
for( int ith=MAX; ith>=0; --ith ){
if( ith <= N) prob[ ith ] = 0; // reset if the state is
transient
for( int num=1;... 阅读全帖 |
|
k*****y
发帖数: 744 | 2 Maintain the increasing subsequence ending at current position. Should run
in O(n) time.
int largestRectangleArea( vector &height ){
stack< pair > st;
st.push( make_pair(-1, 0) );
int ans = 0;
for( int ith=0; ith
int pos = ith;
while(1){
pair &top = st.top();
if(top.second > height[ith] ){
pos = top.first;
ans = max( ans, top.second*(ith - pos) );
... 阅读全帖 |
|
s*********e
发帖数: 197 | 3 为了积攒人品RP，为了H1B顺利，为了有更好的工作，为了有一个更好的将来，开始追
leetcode，并写下自己的做题感受和大家分享，更是作为自己的督促。做题目的原则如
下：
1) Optimized Algorithms to pass the "large" test.
2) Proper abstraction
3) Write the code whose correctness is *easy* to reason about.
4) Favor readability over efficiency without compromising item 1).
5) Rearrangement and tweaking
我试图对自己进行训练的目标就是写完代码，能够确认自己写对了。目前为止，我有一
些小小的心得，会贯穿在下面和以后的文章中。第一，循环不变式；第二，优化控制流
；第三，适度抽象，语义精确的子函数。
抛砖引玉，献上第一弹：Text Justification. 为了更好的可读性，想用一种类C的伪
代码并尽量省略一些类型声明。很多叙述可能比较罗嗦，见谅。
首先要考虑的... 阅读全帖 |
|
p*h
发帖数: 450 | 4 二手交易风险自负！请自行验证是否合法和一手卡！:
y
我想卖的物品:
enterprise $40 certificate
单张面值:
可接受价格(必须明码标价！):
20
物品新旧要求:
new, expire 8/14/2013
邮寄方式要求:
email pdf
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
boa/chase/paypal
其他补充说明:
To redeem, call 1-866-304-7681 to speak w ith an Enterprise Preferred
Reservations representative or log onto enterprise.com and use customer
number DISCBB.
One Certificate per rental. Minimum Purchase of $40. If you have questions
regarding making a reservation, please call 1-866-
304-7681 ... 阅读全帖 |
|
p*h
发帖数: 450 | 5 二手交易风险自负！请自行验证是否合法和一手卡！:
y
我想卖的物品:
enterprise $40 certificate
单张面值:
可接受价格(必须明码标价！):
20
物品新旧要求:
new, expire 8/14/2013
邮寄方式要求:
email pdf
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
boa/chase/paypal
其他补充说明:
To redeem, call 1-866-304-7681 to speak w ith an Enterprise Preferred
Reservations representative or log onto enterprise.com and use customer
number DISCBB.
One Certificate per rental. Minimum Purchase of $40. If you have questions
regarding making a reservation, please call 1-866-
304-7681 ... 阅读全帖 |
|
a*****y
发帖数: 791 | 6 我想卖的物品:
Enterprise Rent-A-Car — $40 eCertificate
单张面值:
$40
可接受的价格(必须明码标价！):
$18
物品新旧要求:
邮寄方式要求:
email pdf file
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
BOA
其他补充说明:
must use with your Discover Credit Card
expiration date: 02/07/2013
One Certificate per rental. Minimum Purchase of $40. If you have questions
regarding making a reservation, please call 1-866-
304-7681 to speak w ith an Enterprise Preferred Reservations representative.
Applicable at all North American locations and
participati... 阅读全帖 |
|
l***y
发帖数: 207 | 7 我要买T520
都刚好1000出头
请问下面哪个配置好些？
CPU和内存哪个更重要？
谢谢大家了，呵呵
配置1 $1001.47
Intel Core i5-2540M Processor (2.60GHz, 3MB L3)
Genuine Window s 7 Professional 64
15.6" HD+ (1600 x 900) LED Backlit Anti-Glare Display, Mobile Broadband
Ready
NVIDIA NVS 4200M Graphics w ith Optimus Technology, 1GB DDR3 Memory
6 GB PC3-10600 DDR3 SDRAM 1333MHz SODIMM Memory (2 DIMM)
UltraNav w ith TrackPoint & touchpad
500 GB Hard Disk Drive, 7200rpm
DVD recordable multiburner
6 cell Li-Ion Battery - 55+
No Bluetooth
ThinkPad b/g... 阅读全帖 |
|
w*******9
发帖数: 1433 | 8 Let X be the vector whose ith element indicates whether the ith stupid fish
takes math;
Let Y be the vector whose ith element indicates whether the ith stupid fish
takes phys.;
Correlation of (X, Y).
We can test whether they are correlated but I guess you wanna test something
stronger. |
|
s******x
发帖数: 15232 | 9 可以考虑在ithaca, NY附近停一下
buf-ith大概开3个小时，在接近ith的时候会有一堆州立公园可以玩（纽约的规定是买
一张票可以一天内在不同的公园反复用），ith还有cornell campus可以参观
ith-bos大概6个小时，正好一天轻轻松松地开 |
|
l******x
发帖数: 163 | 10 给个第二题我的想法，大家讨论下
let Xi = 1 if a update of min needed at A[i], w.p. Pr{ith comparision
invloves a update of min}
= 0 if no update of min needed
Pr{ith comparision invloves a update of min} = Pr{ith number is the min of A
[1...i]} = 1/i
E[X] = sum Xi = 1 + 1/2 + ... + 1/n
number |
|
i**********e
发帖数: 1145 | 11 刚想到很精简的 code，不需要用 post-fix stack-based expression，直接储存进一
个 string 数组即可。
效率应该是不错的了，有一些方面可以考虑提高效率，例如用 vector 需要删除元素可
能会慢些，但 vector 里的元素很少，应该影响不大。
还有一点就是每次传递归的时候，都需要把所有的数组重新 copy 一次。这是无可避免
的，因为每次进入下一层递归时必须传 copy，不能在原有数组中更改。
#include
#include
#include
#include
#include
using namespace std;
void generate(vector A, int target, int s, vector expression);
template
void eraseAt(vector &vec, int i) {
typename vector::iterator ... 阅读全帖 |
|
r*********n
发帖数: 4553 | 12 record = , assuming weight > 0
1. sort records w.r.t. start
2. make an array called aux, with the ith value being equal to the largest
weight sum of any subset of the first i records and containing the ith
record.
3. iterate through all records, and maintain an interval tree (when
encounter end, remove the corresponding interval from the tree). For the ith
record, use the tree to find the first non-overlapping interval j, and set
aux[i] = aux[j] + weight at i
4. iterate throu... 阅读全帖 |
|
r*********n
发帖数: 4553 | 13 record = , assuming weight > 0
1. sort records w.r.t. start
2. make an array called aux, with the ith value being equal to the largest
weight sum of any subset of the first i records and containing the ith
record.
3. iterate through all records, and maintain an interval tree (when
encounter end, remove the corresponding interval from the tree). For the ith
record, use the tree to find the first non-overlapping interval j, and set
aux[i] = aux[j] + weight at i
4. iterate throu... 阅读全帖 |
|
d****n
发帖数: 397 | 14 这个算法行不行，基本上和上面的同学说的差不多。
第一步，把身高数组和b数组，一起按身高数组排序。
第二步，从最小的element开始，reconstruct 新的数组。
第一步是O(nlgn).第二步，最坏是O(n^2)。（当b全为0）时。
以下是程序。
#include
#include
#include
using namespace std;
struct mypair {
int a;
int b;
mypair(int c,int d) {a=c;b=d;}
friend bool operator<(const mypair&,const mypair&);
};
bool operator<(const mypair &p1,const mypair &p2) {
return (p1.a
}
vector heightcomp(vector& a,vector& b) {
int i,k,j,n,m;
n=a.size();
vector阅读全帖 |
|
R*o
发帖数: 3781 | 15 6:5 In v. 5 Paul further explains (gavr, gar) how it is that we can walk in
new life. We do so because of the ongoing effects of our participation in th
e death of Christ and our current participation in the resurrection of Chris
t. The future tense, “we will certainly also be united,” refers not to the
eschatological future (cf. John 5:28-29), but rather to the future with res
pect to the logic of the process of salvation. First, we are reckoned dead w
ith Christ, then we are reckoned to partic... 阅读全帖 |
|
c******j
发帖数: 149 | 16
guess
wearing
guess
Denote the color number for ith person is Ai, then A = sum(i = 1 to 100)Ai,
take the mode of A with respect to 100, the result could be only 0, 1, ... ,
99, totally 100 possibilities. This tells us the strategy.
Before wearing the hats, each of them will be assigned a number from 0 to 99
. Say the ith person is assigned 7, then after everyone gets his hat, this
ith guy sum up the color number of all other people, say Bi, he tries to
find a color number for himself, say AAi, |
|
l********e
发帖数: 349 | 17 请教一下，为什么mode(Bi+AAi, 100)= 7 代表他猜对了呢？不是应该 AAi=7 才是猜对
了吗？
能否再说的详细些呢？
Denote the color number for ith person is Ai, then A = sum(i = 1 to 100)Ai,
take the mode of A with respect to 100, the result could be only 0, 1, ... ,
99, totally 100 possibilities. This tells us the strategy.
Before wearing the hats, each of them will be assigned a number from 0 to 99
. Say the ith person is assigned 7, then after everyone gets his hat, this
ith guy sum up the color number of all other people, say Bi, he tri |
|
c******0
发帖数: 59 | 18 Well normally when you consider a matrix, the ith root of it is done by:
diagonalize the matrix, into P'AP, where 'means inverse
then you take the ith root of its eigenvalues, say A becomes B
Now the ith root of Matrix is P'BP. This is because P'P = I
I assume the approach is gonna be similar to this problem |
|
m*****8
发帖数: 27 | 19 You made a mistake,i doesn't stand for ith trial. It stands for ith
observation or ith case within one sampling.
a
beta0 |
|
w*********g
发帖数: 30882 | 20 四 “美国例外论”与美国文化的全球扩张
在美国盎格鲁-撒克逊新教文化信仰体系中，“美国例外论”具有很重要的一席之
地。这种把美国与世界上其他国家从本源上区别开来的命题，旨在为美国对世界承担特
殊责任或义务提供一种合理的解释，说穿了无非是为美国在履行上帝赋予的一种特殊“
使命”的名义下以各种形式向外扩张进行辩解。因此，“美国例外论”不仅是美国持续
不断的全球文化扩张的意识形态根源之一，而且使美国政府从中寻找到了合理解释的依
据。
美国文化的核心是新教伦理，这是经过长期的历史演变而形成的。因此，与“美国
例外论”密切联系在一起的使命观自然就体现在信仰新教的美国人的身上。在美国历史
上，他们把宗教的狂热与在国外传播美国文化有机地结合在一起，形成了美国文化向非
基督教世界扩张的几次大的浪潮。美国文化向外传播很长时期多是由基督教传教士作为
载体的，美国人甘愿到陌生落后的地方以自身的文化价值观来影响当地的发展，很大程
度上是从其所信仰的宗教中获得鼓舞或驱动力。美国宗教团体在这方面对美国人的号召
力丝毫不亚于美国各级政府，它们那些充满宗教激情的语言固然主要是出于皈依非基督
教世界和实现基督教在整个世... 阅读全帖 |
|
n******l
发帖数: 4407 | 21 希望能呆180天。
表中2.1 11 申请入境事由 Major purpose of your visit是选哪一个？
这个
□ 短期探望中国公民或者具有中国永久居留资格的
外 国 人 Short-term Short-term Short-term visit rt-term visit to Chinese
Chinese Chinese citizen hinese citizen citizen or r
foreigner foreigner foreigner with eigner with Chinese ith Chinese Chinese
permanent nese permanent permanent residence manent residence residence
status idence status
还是这个？
□ 与中国公民或者具有中国永久居留资格的外国人
家庭团聚居留超过 180 日 Family reunion ily reunion reunion for nion for over
180 days 80 days with Chi... 阅读全帖 |
|
g*******y
发帖数: 1930 | 22 来自主题: JobHunting版 - 一道面试题 for second stack, ith element record the max among 1st~ith element. |
|
g*******y
发帖数: 1930 | 23 state: A[i][j][k]
1<=i<=D: A[i]: subproblem from 1th digit to ith digit
-7D<= j <= 7D: you can add/remove j matches
0<= k <= K: the number of moves you've made
value of A[i][j][k] = number of distinct integers
result: sum of A[D][0][所有k]
对ith digit， 它有可能转变到其他的9个(加自身10个)数字 by move x matches +
add/remove y matches
加一个10*10的matrix记录任意两个数字之间的变化
这样就有状态方程了 |
|
n*******s
发帖数: 482 | 24 just wake up and consider it again:
Trying to solve it in this way:
original problem: a1, a2, ....ai, ...an-1, an
subproblem : a1, a2, ... ai
Define array: L[2][n]
L[0][i] --> the max donation where the ith neighbor won't donate
L[1][i] -->the max donation where the ith neighbor will donate
Recursive relation:
L[0][i+1] = max {L[0][i], L[1][i]}
L[1][i+1] = L[0][i] + a[i]
However, during this extension, we don't consider the head/tail collision, but this will be problem. So at the final st |
|
n*******s
发帖数: 482 | 25 l's inital value would be
L[0][0] = 0
L[1][0] = a[0]
since, L[0][i] means the possible max if the ith does not donate
L[1][i] means the possible max if the ith does donate
Here is the code:
int a[] = { 94, 40, 49, 65, 21, 21, 106, 80, 92, 81, 679, 4, 61, 6, 237
, 12, 72, 74, 29, 95, 265, 35, 47, 1, 61, 397, 52, 72, 37, 51, 1, 81, 45,
435, 7, 36, 57, 86, 81, 72 };
int size = sizeof(a)/sizeof(int);
int l[2][size];
int m[size];
int type=0;
int i =0, j=0, max=0;
m |
|
c*****n
发帖数: 96 | 26 My thought on this issue:
To generalize the problem, let say, for machine i, it has an array A[i], A[i
+1] ... A[j]. The initial state is i = 0; j = N-1;
Assuming there is a controller machine C.
1) Sort N numbers on each machine.
2) For each machine, randomly pick up a number A[k] (i<=k<=j) and send it to
the controller C. The Controller C calculates the median M from these N
numbers
3) Controller sends M back to each machine and let them report P[i] back
which is number of data that are less t... 阅读全帖 |
|
b*****n
发帖数: 482 | 27 I have got a semi-baked solution. It deals with input [A, B] if A = 10^n
and B= 10^(n+1) - 1, e.g. [10, 99], or [100, 999].
Starting with B, store B into a vector(vBEnd) for easy processing.
Set CurSumB to the sum of each digits in B;
Set SumNeededB to 7 * number of digits in B;
Set extra = CurSumB - SumNeededB. Here extra means how much we can
decrease for the digits in B and still make the average >= 7;
e.g. if B=999, CurSumB = 27, SumNeededB = 7*3 = 21, extra = 6.
Let i = index of LSB of B, d... 阅读全帖 |
|
i**********e
发帖数: 1145 | 28 x ^= ((1U << i) | (1U << j));
1 ^ 0 = 1
0 ^ 1 = 1
0 ^ 0 = 0
1 ^ 1 = 0
所以如果要 toggle 第 ith bit ，就直接
x = x ^ (1 << i);
要 toggle ith and jth bit:
x = x ^ (1 << i);
x = x ^ (1 << j);
把以上两行简写，就是：
x ^= ((1U << i) | (1U << j)); |
|
c**********e
发帖数: 2007 | 29 Can anybody look at this problem? The answer seems different from mine. 我觉
得答案不对。
Facebook Hacker Cup 2011 Round 1A
First or Last
As a top driver in European racing circles, you find yourself taking more
than your fair share of risks. You go into every race knowing it may be your
last, but generally with the suspicion it won't be. Today, however, may
turn out to be different. The Fédération Internationale de l'Automobile
has sanctioned a new track in the Bernese Alps that may prove to be death o... 阅读全帖 |
|
b*******e
发帖数: 217 | 30 来自主题: JobHunting版 - 请问G一题 DP problem: knapsack
Recursive formulation:
Exist(i, j, k) = Exist(i-1, j, k) || Exist(i-1, j-Xi, k-1)
Where i is the index of ith element, j is the sum targeted, and k is the
number of elements selected to get the j and Xi is the value of the ith
element.
We need to decide whether any Exist(n, j, n/2) is true for j = X0, X0+1, ...
n/2.
For all j where Exist(n, j, n/2) == true, pick the j which is closest to Sum
(n) / 2. ------(3)
Then, Abs(Sum(n) /2 - j - j) is the smallest delta of the two su... 阅读全帖 |
|
b*******e
发帖数: 217 | 31 来自主题: JobHunting版 - 请问G一题 how can you write your recursive function based on the understanding of your
"i".
my i and the i in MIT website is the "ith" element or the "first ith"
elements. |
|
b*******e
发帖数: 217 | 32 来自主题: JobHunting版 - 请问G一题 DP problem: knapsack
Recursive formulation:
Exist(i, j, k) = Exist(i-1, j, k) || Exist(i-1, j-Xi, k-1)
Where i is the index of ith element, j is the sum targeted, and k is the
number of elements selected to get the j and Xi is the value of the ith
element.
We need to decide whether any Exist(n, j, n/2) is true for j = X0, X0+1, ...
n/2.
For all j where Exist(n, j, n/2) == true, pick the j which is closest to Sum
(n) / 2. ------(3)
Then, Abs(Sum(n) /2 - j - j) is the smallest delta of the two su... 阅读全帖 |
|
b*******e
发帖数: 217 | 33 来自主题: JobHunting版 - 请问G一题 how can you write your recursive function based on the understanding of your
"i".
my i and the i in MIT website is the "ith" element or the "first ith"
elements. |
|
c********t
发帖数: 5706 | 34 来自主题: JobHunting版 - EA 面筋 第二题可不可以用linkedlist, 每次循环找到ith min number, then insert into ith
position
(1+n)*n/2 = O(n^2)? |
|
b*******e
发帖数: 217 | 35 my recursive function is
Xba(i) = Min { Xab(i-1) + D(i-2, i) ; Xba(i-1) + D(i-1, i);
Xaa(i-1) + D(i-1, i) ; Xab(i-2) + D(i-3, i) + D(i-2, i-1);
Xab(i-3) + D(i-4, i) + D(i-3, i-1),
....
Xab(1) + D(1, i) + D(1, i-1)}
Where ba indicates i-1 th city is visited by b and ith city is visited by a.
aa indicates i-1 th city visited by a and ith city also visited by a.
ab, and bb following the same.
Following same method,
We can have the recurs... 阅读全帖 |
|
d****n
发帖数: 233 | 36 按endtime的话， 当你处理ith job时， 可以通过binarysearch 很快找到最接近的job
which
is not overlapping with ith job。 因为前面i-1个的endtime是递增的。 |
|
d****n
发帖数: 233 | 37 按endtime的话， 当你处理ith job时， 可以通过binarysearch 很快找到最接近的job
which
is not overlapping with ith job。 因为前面i-1个的endtime是递增的。 |
|
z**u
发帖数: 1025 | 38 Hi，十分感谢！
请问是不是必须，A-B,B-C,C-A这样，才能免费有一个stop over B?
因为UA去美东去夏威夷要22.5k miles, AA只要17.5k miles，所以我是打算去的时候
ITH-SAN-HNL是用UA换，HNL-ITH回程用AA换。 |
|
a*****g
发帖数: 19398 | 39 围棋帮助提高 ADHD 儿童的大脑认知能力zz
Baduk (the Game of Go) Improved Cognitive Function and Brain Activity in Chi
ldren with Attention Deficit Hyperactivity Disorder
Abstract
Objective
Attention deficit hyperactivity disorder (ADHD) symptoms are associated with
the deficit in executive functions. Playing Go involves many aspect of cogn
itive function and we hypothesized that it would be effective for children w
ith ADHD.
Methods
Seventeen drug na?ve children with ADHD and seventeen age and sex matched co
mpa... 阅读全帖 |
|
a*****g
发帖数: 19398 | 40 围棋帮助提高 ADHD 儿童的大脑认知能力zz
Baduk (the Game of Go) Improved Cognitive Function and Brain Activity in Chi
ldren with Attention Deficit Hyperactivity Disorder
Abstract
Objective
Attention deficit hyperactivity disorder (ADHD) symptoms are associated with
the deficit in executive functions. Playing Go involves many aspect of cogn
itive function and we hypothesized that it would be effective for children w
ith ADHD.
Methods
Seventeen drug na?ve children with ADHD and seventeen age and sex matched co
mpa... 阅读全帖 |
|
n******l
发帖数: 4407 | 41 希望能呆180天。
表中2.1 11 申请入境事由 Major purpose of your visit是选哪一个？
这个
□ 短期探望中国公民或者具有中国永久居留资格的
外 国 人 Short-term Short-term Short-term visit rt-term visit to Chinese
Chinese Chinese citizen hinese citizen citizen or r
foreigner foreigner foreigner with eigner with Chinese ith Chinese Chinese
permanent nese permanent permanent residence manent residence residence
status idence status
还是这个？
□ 与中国公民或者具有中国永久居留资格的外国人
家庭团聚居留超过 180 日 Family reunion ily reunion reunion for nion for over
180 days 80 days with Chi... 阅读全帖 |
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n******l
发帖数: 4407 | 42 希望能呆180天。
表中2.1 11 申请入境事由 Major purpose of your visit是选哪一个？
这个
□ 短期探望中国公民或者具有中国永久居留资格的
外 国 人 Short-term Short-term Short-term visit rt-term visit to Chinese
Chinese Chinese citizen hinese citizen citizen or r
foreigner foreigner foreigner with eigner with Chinese ith Chinese Chinese
permanent nese permanent permanent residence manent residence residence
status idence status
还是这个？
□ 与中国公民或者具有中国永久居留资格的外国人
家庭团聚居留超过 180 日 Family reunion ily reunion reunion for nion for over
180 days 80 days with Chi... 阅读全帖 |
|
a*****g
发帖数: 19398 | 43 围棋帮助提高 ADHD 儿童的大脑认知能力zz
Baduk (the Game of Go) Improved Cognitive Function and Brain Activity in Chi
ldren with Attention Deficit Hyperactivity Disorder
Abstract
Objective
Attention deficit hyperactivity disorder (ADHD) symptoms are associated with
the deficit in executive functions. Playing Go involves many aspect of cogn
itive function and we hypothesized that it would be effective for children w
ith ADHD.
Methods
Seventeen drug na?ve children with ADHD and seventeen age and sex matched co
mpa... 阅读全帖 |
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u*******m
发帖数: 3395 | 44 两年加一个礼拜啊……飞了总共一百二十多小时。不过今天总算过关了。
从ITH起飞的时候天气不是特别好，有小雨，还好celing有7000，FA说整
条路线VFR。要了Radar Following，结果起飞后才给Squawk Code，叫我
Contact ELM Departure，我说，有Departure Freq吗？来回两三次，我
还把Squawk号弄错了一位。ELM告诉我对的Code。然后往东飞到BGM。
Level 5500。
过了BGM，找到了我选的Alternate Airport CZG，考官把我油门关了，说
咋办，我一边忙活，他一边取消了Radar Following，我就缓缓的滑到了
CZG上面，地面人说用Runway 21，我转了一圈，到Downwind高度刚好是
1000AGL，然后就Dead-stick, Forward slip，这在ITH练过至少10来次，
最后降得还是满轻的。
然后就是模拟Soft & Short，再爬起来之后就是Ground-Ref-Maneuver，
Steep Turn，Slow Flight，Instrument。觉得考官成心想放 |
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s******x
发帖数: 15232 | 45 不搞笑，太正常了。
比如LGA-ITH，300多
BWI-LGA-ITH，80多
但是一程不坐后面作废。
你倒是可以考虑
CLE-LAX-CLE-CHM的，看看是不是便宜。最后一段不坐没有关系。 |
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s******x
发帖数: 15232 | 46 电话打不通就直接去机场找agent
ith这种小地方应该去机场非常方便吧
另外，你觉得飞机都飞不了，你自己能从ith开到ewr?
别冒险吧 |
|
j****m
发帖数: 8 | 47 看到有人指出在icmlc 2011会议中同一个作者发表论文达10多篇。本文深知做学术
的不易，觉得在短时间内能在同一个会议上发表10多篇论文，不是造假抄袭，就是粗制
滥造。于是随便找了一篇搜索了一下。发现不如所料，亩产万斤果然是有问题的。
请相关专业人员鉴定是否属于抄袭，以及是否还有其他未发现之处。
抄袭文（以下简称USOM文）
Le Li, Xiaohang Zhang, Zhiwen yu, Zijian Feng, Ruiping Wei, USOM: Mining
and Visualizing Uncertain Data Based on Self-Organizing Maps, Proceedings
of the 2011 International Conference on machine Learning and Cybernetics,
804-809
作者单位：
School of Computer Science and Engineering, South China University of
Technology, Guangzhou, China
... 阅读全帖 |
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C****i
发帖数: 1776 | 48 CHAPTER III
Of God’s Eternal Decree
I. God, from all eternity, did, by the most wise and holy counsel of his own
will, freely, and unchangeably ordain whatsoever comes to pass:[65] yet so,
as thereby neither is God the author of sin,[66] nor is violence offered to
the will of the creatures; nor is the liberty or contingency of second caus
es taken away, but rather established.[67]
II. Although God knows whatsoever may or can come to pass upon all supposed
conditions,[68] yet hath he not decreed ... 阅读全帖 |
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C****i
发帖数: 1776 | 49 CHAPTER XXXIII
Of the Last Judgment
I. God hath appointed a day, wherein he will judge the world, in righteousne
ss, by Jesus Christ,[573] to whom all power and judgment is given of the Fat
her.[574] In which day, not only the apostate angels shall be judged,[575] b
ut likewise all persons that have lived upon earth shall appear before the t
ribunal of Christ, to give an account of their thoughts, words, and deeds; a
nd to receive according to what they have done in the body, whether good or
evi... 阅读全帖 |
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