g****9
发帖数: 163 | 1 写了一个graph的class 但是下面第一种写法是错误的，我不是太明白，是因为
GNode node1 = null;GNode node2 = null吗？这时候node1跟node2并没有allocate
memory，所以就算后面if statement里面的node1 = new GNode(key1) 也只是在if这个
block里面有效的吧，在最后node1.connect(node2）里node1 是不是还是null呢 求指
点。第二个graph class 就可以work的。
public Graph(int[][] adjacencyMatrix) {
nodes = new HashMap();
GNode node1 = null;
GNode node2 = null;
for (int i = 0; i < adjacencyMatrix.length; i++) {
int key1 = i + 1;
... 阅读全帖 |
|
s*****o
发帖数: 1262 | 2 我用graph command很多，但是一直都只很基础，不知道那里有例子可以让我跟深入的
使用graph command？
简单的graph例子：
graph -T X my.data
哪位能指点一下graph command，挥着给个连接？ 多谢！！！
（更先进的gnuplot完全不会用，暂时不想学） |
|
j***n
发帖数: 301 | 3 【 以下文字转载自 Mathematics 讨论区 】
发信人: jamen (jamen), 信区: Mathematics
标 题: Vertex Cover in Cubic Graph
发信站: BBS 未名空间站 (Fri Feb 20 22:24:44 2009), 转信
Hi Everyone,
I need to proof Vertex Cover problem is NP complete even for cubic graphs. N
otice that a cubic graph is a graph such that every vertex has degree of *ex
actly three*. I found one paper but his definition for cubic graph is a litt
le loose in that the degree can be less than 3.
Can anybody give me a hint?
Thanks! |
|
D*******a
发帖数: 207 | 4 各位同好，我不学EE已经很久了。现在需要查个signal flow graph的问题，可是不知
道关键词，查不到。希望得到大家的帮助。
如图所示的两个signal flow graph,他们的传输函数是一样的。这叫什么定理？我查了
dual signal flow graph, conjugate signal flow graph等等，没找到什么说法。在
wiki的signal flow graph词条里面，也没有提到。希望知道的人提供个关键字我好去
搜索，或者有网页更好。谢谢！ |
|
t****a
发帖数: 1212 | 5 I have a graph matching problem that I want to solve. This problem involves
a weighted undirected graph and is very similar to the maximum weighted
graph matching problem http://jorisvr.nl/maximummatching.html
With respect to a weighted graph, a maximum weight matching is a matching
for which the sum of the weights of the matched edges is as large as
possible. I can find some software for solving this problem.
However, my problem is a little bit different from the standard one in that
I wish the... 阅读全帖 |
|
c******n
发帖数: 4965 | 6 【 以下文字转载自 Mathematics 讨论区 】
发信人: creation (努力自由泳50m/45sec !), 信区: Mathematics
标 题: graph question: what is "genus" ?
发信站: BBS 未名空间站 (Wed May 29 18:58:51 2013, 美东)
tried to read wikipedia but still got very confused
in this paragraph:
"
The Asymmetric Traveling Salesman Problem on Graphs with Bounded Genus
Shayan Oveis Gharan∗ Amin Saberi∗
.....
We present the first constant-factor approximation algorithm for the
Asymmetric Traveling Salesman
Problem (ATSP) for metrics deᤙ... 阅读全帖 |
|
y***a
发帖数: 840 | 7 I have a 2X2 graph which contains 4 subfigures in my latex file as follows.
The problem is that this 2X2 graph is not big enough for one page (I estimate
that it only occupies 50% of the page), but latex doesnot put the neighboring
text in the same page with this graph. Anybody knows how to force latex to
squeeze some text into the same page with the graph? thanks.
\begin{figure}[htbp]
\centering
\begin{minipage}{6.5cm}
\subfigure[situation1.]{
\includegraphics[width=6.55cm]{experiments/1.eps} |
|
c******n
发帖数: 4965 | 8 【 以下文字转载自 Mathematics 讨论区 】
发信人: creation (努力自由泳50m/45sec !), 信区: Mathematics
标 题: graph question: what is "genus" ?
发信站: BBS 未名空间站 (Wed May 29 18:58:51 2013, 美东)
tried to read wikipedia but still got very confused
in this paragraph:
"
The Asymmetric Traveling Salesman Problem on Graphs with Bounded Genus
Shayan Oveis Gharan∗ Amin Saberi∗
.....
We present the first constant-factor approximation algorithm for the
Asymmetric Traveling Salesman
Problem (ATSP) for metrics deᤙ... 阅读全帖 |
|
x**l
发帖数: 12 | 9 I am using a Exel sheet as storage for database and want to
make graph out of the data then display the graph in
VB program. each time if the data is changed , graph should
be refreshed.
I've tried the excel graph ActiveX component but something
is not right.
anyone know how to do it?
thx |
|
b*****e
发帖数: 474 | 10 Using brutal force:
is2stepsConnected(A, B) : bool
foreach node n, SA(n) = set of person linked from A
SB(n) = set of person linked to B
UA = Union SA(n)
UB = Union SB(n)
foreach node n, isConnected(n) = exists edge E (X, Y)
such that X in UA and Y in UB
return OR isConnected(n)
Same thing using equivalent database query: table Graph contains edges (X, Y
):
SELECT X, Y from Graph G
WHERE G.X in (SELECT K.Y from Graph K WHERE K.X = A)
AND G.Y in (SE... 阅读全帖 |
|
l***i
发帖数: 2 | 11 I am also new to xml.. donno the correct presentation of the
solution, but I guess the basic idea is to convert the graph
into the tree, one very simple solution will be:
...
...
....
<--! above list the elements, following with the connection
points-->
na,nb,..
...
nx, ny..
something like this should be enough for a graph
representation..
there is also a S |
|
j***n
发帖数: 301 | 12 Hi Everyone,
I need to proof Vertex Cover problem is NP complete even for cubic graphs. N
otice that a cubic graph is a graph such that every vertex has degree of *ex
actly three*. I found one paper but his definition for cubic graph is a litt
le loose in that the degree can be less than 3.
Can anybody give me a hint?
Thanks! |
|
h*****o
发帖数: 1476 | 13 【 以下文字转载自 Statistics 讨论区 】
发信人: haipiao (海漂), 信区: Statistics
标 题: 新人请教一下用R做一个简单graph问题
发信站: BBS 未名空间站 (Tue Jan 25 19:16:11 2011, 美东)
没用过R，但只有R是免费的，所以下载了想做个graph，关于工作的一个presentation。
如果用R做一个附件中的两个graph，请问code怎么写？小红圈代表已知点。
最好做出的graph也能用不同颜色分别显示点和线，比如红色的点，蓝色的线。
非常感谢。 |
|
y******d
发帖数: 65 | 14 graph on the left
plot(1,1,type="n",xlim=c(1,5),ylim=c(1,5))
lines(c(2:4),c(4:2),lty=1,col="red")
points(2,4,pch=21,col="blue")
points(4,2,pch=21,col="blue")
graph on the right
plot(1,1,type="n",xlim=c(1,5),ylim=c(1,5))
lines(c(1:2),rep(2,length(c(1:2))),lty=1,col="red")
lines(c(2:3),rep(3,length(c(1:2))),lty=1,col="red")
lines(c(3:4),rep(4,length(c(1:2))),lty=1,col="red")
points(1,2,pch=21,col="blue")
points(2,2,pch=19,col="blue")
points(2,3,pch=21,col="blue")
points(3,3,pch=19,col="blue")
poin... 阅读全帖 |
|
r******l
发帖数: 1118 | 15 二手交易风险自负！请自行验证是否合法和一手卡！:
谁知道TI-84 Plus Graphing Calculator rebate limit?
我想卖的物品:
谁知道TI-84 Plus Graphing Calculator rebate limi
单张面值:
谁知道TI-84 Plus Graphing Calculator rebate limit?
谢谢。
可接受价格(必须明码标价！):
物品新旧要求:
邮寄方式要求:
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
其他补充说明:
广告的有效期:
物品来源(Required for All Cards!):
我的联系方式:
Warranty期限:
能否证明是合法的一手卡?(Required for All Cards!):
state and zip: |
|
d********t
发帖数: 9628 | 16 Chapter 4 -- Trees and Graphs里面Graph就一题，是不是graph不重要？ |
|
f*********m
发帖数: 726 | 17 前些时候本版大牛面过的linkedin的题，没什么好思路。贴出来请大家指点。
Given a social graph, find if there is a path between two persons with at
most 2 steps (3rd level connection), how to handle it in distributed way (
large graph stored at a large number of nodes, minimize cross-communication)
不会涉及到graph merge/split 的问题吧？ |
|
发帖数: 1 | 18 Title: Lead Big Data Server Engineer, Graph Team
Work type: FULL-TIME
Location: San Mateo, CA
Salary: 160k+ Stock option+ bonus
Build smart, scalable systems, high throughput, low latency systems like
Adservers. Work with top notch engineers and contribute to design,
implementation and code reviews. Write APIs for Campaign Management and
Reporting in Java. Write SQL queries and optimization. Follow REST standards
for building new APIs using open source frameworks like Spring and
Hibernate. Have ... 阅读全帖 |
|
y***u
发帖数: 101 | 19
Yes, this should be a very difficult problem.
Just consider a much easier case where we put an edge between each pair
of vertices with probability p, and ask if the graph is connected. People
have shown that there exists some threshold for p, if p is below the
threshold, the graph is almost certainly disconnected; if p is above
the threshold, the graph is almost certainly connected. This is called
the phase transition phenomena. More interestingly, many other monotone
properties besides conn |
|
c*********n
发帖数: 128 | 20 A graph {E, V}. The edges of the graph are assigned randomly between
vertices.
For two random vertices i and j, with degrees k_i and k_j, respectively,
what is the probablity that there is an edge between them?
I think the result is
k_i*k_j/m
where m is the total number of edges in the graph.
For any edge E, the probability that E is connecting vertices j is
k_j/m
Considering i is connected with k_i edges, then the probability is
k_i * (k_j/m)
But some paper gives
k_i*k_j/(2m)
What do you guys s |
|
t*****k
发帖数: 390 | 21 For a directed graph without cycles, if I removed some paths from this graph
(does not mean removing edges), how can I reconstruct the graph without the
se edges easily? Thanks!
If someone knows the references, that will be also good :) Many thanks! |
|
t*****k
发帖数: 390 | 22 比如graph里有4条paths：A->B->C->D, E->B->C->F, E->B->C->D, A->B->C->F，我rem
ove掉前2条paths，但保留后两条，有没有可能重新reconstruct graph实现这个目的，
可以加一些dummy nodes...
graph
the |
|
v********e
发帖数: 1058 | 23 Let X = (V, E) be a graph. A parttition \pi of V(X) with cells C_1, ..., C_r
is equitable if the number of neighbours in C_j of a vertex u in C_i is a
constant b_ij, independent of u. An equivalent definition is that the
subgraph of X induced by each cell is regular, and the edges joining any two
distinct cells form a semiregular bipartite graph. The directed graph with
the r cells of \pi as its vertices and b_ij arcs from the i-th to the j-th
cells of \pi is called the quotient of X over \pi. |
|
w******c
发帖数: 574 | 24 is there any java graph library that can extract cuts from a graph?
like, given the vitices and edges of a graph, generate all the cuts for a
specified source and destination?
//thx |
|
v****s
发帖数: 1112 | 25 What'll be the best algorithm for finding signed triad in large scale
graph, details as follows:
Given a graph with 1 million nodes and about 8 million edges (so, avg
degree is 8 ), 85% of the edges are marked as "+" and 15% as "-".
What will be the best algorithm or data structure involved to find
out the numbers of these 4 possible types of signed triad (a triangle
subgraph having 3 nodes and 3 edges) in this graph.
The four kinds of signed triad are:
+++
+--
++- |
|
f*********m
发帖数: 726 | 26 Given a social graph, find if there is a path between two persons with at
most 2 steps (3rd level connection), how to handle it in distributed way (
large graph stored at a large number of nodes, minimize cross-communication)
不会涉及到graph merge/split 的问题吧？
能不能把每个边界node都存两个copy，两个相邻的机器各一个？比如：node_a和node_b
是边界node，在两台机器上各有一个copy。
机器1 机器2
node_c---node_a---node_b | node_a---node_b---node_d
|
找node_a的k-level 邻居，可以先在机器1上用bfs,遇到node_b后（可... 阅读全帖 |
|
c******n
发帖数: 4965 | 27 tried to read wikipedia but still got very confused
in this paragraph:
"
The Asymmetric Traveling Salesman Problem on Graphs with Bounded Genus
Shayan Oveis Gharan∗ Amin Saberi∗
.....
We present the first constant-factor approximation algorithm for the
Asymmetric Traveling Salesman
Problem (ATSP) for metrics defined by a weighted directed graph with a
bounded orientable genus.
This is a natural special case: consider a metric obtained by shortest path
distances in a city ... 阅读全帖 |
|
h*****o
发帖数: 1476 | 28 没用过R，但只有R是免费的，所以下载了想做个graph，关于工作的一个presentation。
如果用R做一个附件中的两个graph，请问code怎么写？小红圈代表已知点。
最好做出的graph也能用不同颜色分别显示点和线，比如红色的点，蓝色的线。
非常感谢。 |
|
w*******y
发帖数: 60932 | 29 OfficeDepot.com has coupon code "93545847" which saves 15% off select Texas
Instruments graphing calculators through July 24. The coupon can be stacked
with another coupon code for additional savings, and some models have a $10
mail-in rebate available. Free delivery.Texas Instruments TI-84 Plus Silver
Edition Graphing Calculator:
http://www.officedepot.com/catalog/catalogSku.do?id=493752
, Item # 493752
Texas Instruments TI-84 Plus Silver Edition Graphing Calculator, Black:
http://www.officedep |
|
L*******r
发帖数: 119 | 30 我也是闲的蛋疼。
我猜他是想问random graph相关的问题。如果换一种看得懂的表述方式，他的问题可能
是这样的：现在图里有K+1个点，然后我不断往里添加点，每次添加一个点，就随机的
和已有的K个点相连。然后不断的往里加，问当加入无穷多个点之后，任意两点联通的
概率是多大。
然后估计有人用渗透理论解决了这个问题。如果搜 percolation theory random graph
，大约能有些论文讲这个问题。比如这个：
http://math.uchicago.edu/~shmuel/Network-course-readings/van%20
不过反正我是没看懂。有谁看懂了的上来讲讲吧。 |
|
C****u
发帖数: 1464 | 31 我想要的物品:
TI-84 Plus Graphing Calculator (at least 15 in one shipment): $80 each + my Fedex label in one box to me
不需要屯货.
EMAIL Only.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@80 - Your id
BBSID: xxxxx，
数量，总金额，期货还是现货
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to me.
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
pp etc
其他补充说明:
无故反悔加黑名单，多谢理解 |
|
j******f
发帖数: 768 | 32 我想要的物品:
TI-84 Plus Graphing Calculator $ 78
可接受的价格(必须明码标价！):
$ 78
物品新旧要求:
NEW
邮寄方式要求:
MY USPS LABEL
付款方式说明:
PAYPAL Or BOA
其他补充说明:
Send Email to j***[email protected]
标题：TI-84 Plus Graphing Calculator
Including:
BBS ID
名字
电话
所在地 (州 + 邮编）
颜色
数量
PAYPAL or BOA account infotmation.
LABEL EMAIL: |
|
C****u
发帖数: 1464 | 33 我想要的物品:
TI-84 Plus Graphing Calculator:
$80 each (at least 10 in one shipment)+ my Fedex label in one box to me 不需
要屯货
$78 each (at least 5 in one shipment)+ my Fedex label in one box to me 不需
要屯货
EMAIL or PM.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator$80/78 - Your id
BBSID: xxxxx，
数量，总金额，期货还是现货
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to m |
|
i***i
发帖数: 1835 | 34 我想要的物品:
TI-84 Plus Graphing Calculator @ 85
求一些，label ready
单张面值:
$109- 25 coupon ～～ 85 + tax - 30 SER
可接受的价格(必须明码标价！):
85 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY Fedex/USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
non-cc paypal, boa, bill pay
其他补充说明:
广告的有效期:
直到喊停为止。。
物品来源:
Staples
我的联系方式:
1) 请email: i*********[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator @ 85 - Your id
BBSID: xxxxx，
数量，总金额
State: xxxxx
Zipcode: xxxxx
收款方式： paypal, o |
|
r******l
发帖数: 1118 | 35 summary:
谁知道TI-84 Plus Graphing Calculator rebate limit?
UPS/FEDEX/DHL/USPS..?(请写明carrier或写shipping）:
货物金额:
谁知道TI-84 Plus Graphing Calculator rebate limit?
谢谢。
Ground/Express/...?:
original/destination:
医生/病人？:
具体问题:
有奖/无奖征答: |
|
C****u
发帖数: 1464 | 36 我想要的物品:
Texas Instruments TI-84 Plus Graphing Calculator
http://www.staples.com/Texas-Instruments-TI-84-Plus-Graphing-Calculator/product-nr_566641?cmArea=SEARCH
单张面值:
109.99-30 easy rebate-25 off coupon + tax (save 10% more if you have gc)
=55+tax
I can provide coupons free of charge (instore or online).
可接受的价格 (required):
$70 my label (5 or more will be best to save my shipping fee)
If you have more than 10 items, pm for price;
If you use your own coupons, $2 more for each item.
物品新旧要求:
brand n |
|
L******1
发帖数: 8133 | 37 我想要的物品:
TI-84 Plus Graphing Calculator@７８
单张面值:
可接受的价格(必须明码标价！):
78 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
PAYPAL
其他补充说明:
标题：TI-84 Plus Graphing Calculator-YOUR ID
BBS ID
名字
电话
邮编（STATE+ZIP)
数量
计算方式
)PAYPAL(ONLY PAYPAL)
LABEL EMAIL:
广告的有效期:
物品来源:
我的联系方式:
y******[email protected]
二手交易风险自负！请自行验证是否合法和一手卡！: |
|
C****u
发帖数: 1464 | 38 我想要的物品:
TI-84 Plus Graphing Calculator: $78 each + my Fedex label to me 不需要屯货(at least 5 in one shipment; if less than 5, your label to me)
EMAIL or PM.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@78 - Your id
BBSID: xxxxx，
数量，总金额
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to me.
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
pp etc
其他补充说明:
无 |
|
A*Z
发帖数: 1105 | 39 我想要的物品:
TI-84 Plus Graphing Calculator @ 78
数量不限， 越多越好
单张面值:
$109- 25 coupon ～～ 85 + tax - 30 SER
可接受的价格(必须明码标价！):
78 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY Fedex/USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
non-cc paypal, boa, bill pay
其他补充说明:
广告的有效期:
直到喊停为止。。
物品来源:
Staples
我的联系方式:
1) 请email: a********[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator @ 78 + my label - Your id
BBSID: xxxxx，
数量，总金额
State: xxxxx
Zipcode: xxxxx
收款方式： payp |
|
x********u
发帖数: 3321 | 40 我想要的物品:
TI-84 Plus Graphing Calculator @ 78
数量不限， 越多越好
单张面值:
$109- 25 coupon ～～ 85 + tax - 30 SER
可接受的价格(必须明码标价！):
78 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY Fedex/USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
non-cc paypal, check, bill pay
其他补充说明:
广告的有效期:
直到喊停为止。。
物品来源:
Staples
我的联系方式:
1) 请email: x***********[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator @ 78 -Your id
BBSID: xxxxx，
数量，总金额
State: xxxxx
Zipcode: xxxxx
收款方式： paypal, or |
|
e**********0
发帖数: 7133 | 41 我想要的物品:
TI-84 Plus Graphing Calculator @ 78.88
数量不限， 越多越好
单张面值:
$109- 25 coupon ～～ 85 + tax - 30 SER
可接受的价格(必须明码标价！):
78.88 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY Fedex/USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
non-cc paypal, bill pay
其他补充说明:
广告的有效期:
直到喊停为止。。
物品来源:
Staples
我的联系方式:
1) 请email: e*******************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator @ 78.88 - Your id
BBSID: xxxxx，
数量，总金额
State: xxxxx
Zipcode: xxxxx
收款方式： |
|
C****u
发帖数: 1464 | 42 我想要的物品:
TI-84 Plus Graphing Calculator (at least 15 in one shipment): $80 each + my Fedex label in one box to me
不需要屯货.
EMAIL Only.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@80 - Your id
BBSID: xxxxx，
数量，总金额，期货还是现货
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to me.
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
pp etc
其他补充说明:
无故反悔加黑名单，多谢理解 |
|
j******f
发帖数: 768 | 43 我想要的物品:
TI-84 Plus Graphing Calculator $ 78
数量不限， 越多越好
单张面值:
可接受的价格(必须明码标价！):
1 to 5 @ 78
5 to 10 @ 79
More than 10 @ 80
物品新旧要求:
NEW
邮寄方式要求:
MY USPS LABEL
付款方式说明:
PAYPAL Or BOA
其他补充说明:
Send Email to j***[email protected]
标题：TI-84 Plus Graphing Calculator
Including:
BBS ID
名字
电话
所在地 (州 + 邮编）
颜色
数量
PAYPAL or BOA account infotmation.
LABEL EMAIL: |
|
C****u
发帖数: 1464 | 44 我想要的物品:
TI-84 Plus Graphing Calculator:
$78 each (at least 10 in one shipment)+ my Fedex label in one box to me 不需
要屯货
$76 each (at least 5 in one shipment)+ my Fedex label in one box to me 不需
要屯货
EMAIL or PM.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@78/76 - Your id
BBSID: xxxxx，
数量，总金额，期货还是现货
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to m |
|
p*****8
发帖数: 282 | 45 我想要的物品:
TI-84 Plus Graphing Calculator:
$80 each (at least 10 in one shipment)
$79 each (at least 5 in one shipment)
EMAIL or PM.
1) 请email: p************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@80 - Your id
BBSID: xxxxx，
数量，总金额
Zipcode: xxxxx
收款方式： paypal(masspay),billpay, check?
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to me.
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
pp etc
其他补充说明:
广告的有 |
|
L******1
发帖数: 8133 | 46 我想要的物品:
TI-84 Plus Graphing Calculator:
$80 each (at least 10 in one shipment)
$79 each (at least 5 in one shipment)
EMAIL or PM.
1) 请email: p************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator@80 - Your id
BBSID: xxxxx，
数量，总金额
Zipcode: xxxxx
收款方式： paypal(masspay),billpay, check?
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to me.
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
pp etc
其他补充说明:
广告的有 |
|
j******f
发帖数: 768 | 47 我想要的物品:
TI-84 Plus Graphing Calculator $ 78
可接受的价格(必须明码标价！):
$ 78
物品新旧要求:
NEW
邮寄方式要求:
MY USPS LABEL
付款方式说明:
PAYPAL Or BOA
其他补充说明:
Send Email to j***[email protected]
标题：TI-84 Plus Graphing Calculator
Including:
BBS ID
名字
电话
所在地 (州 + 邮编）
颜色
数量
PAYPAL or BOA account infotmation.
LABEL EMAIL: |
|
C****u
发帖数: 1464 | 48 我想要的物品:
TI-84 Plus Graphing Calculator:
$80 each (at least 10 in one shipment)+ my Fedex label in one box to me 不需
要屯货
$78 each (at least 5 in one shipment)+ my Fedex label in one box to me 不需
要屯货
EMAIL or PM.
1) 请email: g************[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator$80/78 - Your id
BBSID: xxxxx，
数量，总金额，期货还是现货
Zipcode: xxxxx
收款方式： paypal etc.
电话号码： (xxx)xxx-xxxx
单张面值:
可接受的价格(必须明码标价！):
above
物品新旧要求:
brand new sealed
邮寄方式要求:
my label to m |
|
i***i
发帖数: 1835 | 49 我想要的物品:
TI-84 Plus Graphing Calculator @ 85
求一些，label ready
单张面值:
$109- 25 coupon ～～ 85 + tax - 30 SER
可接受的价格(必须明码标价！):
85 EACH
物品新旧要求:
NEW
邮寄方式要求:
MY Fedex/USPS LABEL
买卖双方谁承担邮寄损失(Required if not code only):
BEFORE U AFTER ME
付款方式说明:
non-cc paypal, boa, bill pay
其他补充说明:
广告的有效期:
直到喊停为止。。
物品来源:
Staples
我的联系方式:
1) 请email: i*********[email protected]
2) email的格式如下：
Subject:【求购】TI-84 Plus Graphing Calculator @ 85 - Your id
BBSID: xxxxx，
数量，总金额
State: xxxxx
Zipcode: xxxxx
收款方式： paypal, o |
|
k***e
发帖数: 556 | 50 你平常是在哪找到的这些题目？能告知一下吗？我只知道careercup。
bfs can be used only for the undirected graph. it is easy to give a counter
example of directly graph that bfs did not work.
dfs works in both cases.
marking is definitely needed. |
|
