g******i
发帖数: 251 | 1 Using Gauss' Law, we can obtain E1=rho/epslon. when we calculate the force on
the unit area, we should know the field at this point is the sum of the field
of created by all other charges plus the field created by the unit area. We
can prove these two are equal. So the field due to all other charges are
E=rho/2*epslon, so the force is f=Rho*Rho/(2*epslon).
By the way, rho should be surface charge density ba.
导体表面将受到张力,单 |
|
o*******w
发帖数: 349 | 2 问题是这个Pi你给不出. 而"1/3"则可以; e.g., -- is 1/3 of ------
这就是无理数的本质区别。同理 √2 也一样。
有的极限，有一个存在的数与它相等，e.g.
lim 1/n = 0
而有些极限却没有一个数与它相等(i.e. 仅仅是一个极限), e.g.
lim Xn = √2
√2 只是一个极限 (符号）（meaning “given an epslon, we can find a big N,
such that |Xn － √2| < epslon when n > N ", no more!) |
|
o*******w
发帖数: 349 | 3 问题是这个Pi你给不出. 而"1/3"则可以; e.g., -- is 1/3 of ------
这就是无理数的本质区别。同理 √2 也一样。
有的极限，有一个存在的数与它相等，e.g.
lim 1/n = 0
而有些极限却没有一个数与它相等(i.e. 仅仅是一个极限), e.g.
lim Xn = √2
√2 只是一个极限 (符号）（meaning “given an epslon, we can find a big N,
such that |Xn － √2| < epslon when n > N ", no more!) |
|
b***u
发帖数: 12010 | 4 其他好说。如果有零状态转换，可能会有死循环。我记得课上说epslon转换可以变成没
零转换的。谁记得怎么搞？ |
|
