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全部话题 - 话题: ccosx
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s*****r
发帖数: 11545
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来自主题: Military版 - 几何题求助
Three basic rules:
c^2=a^2+b^2-2abcosC
cosC=(a^2+b^2-c^2)/2ab
sinC=c/2R
Solution:
(FD)^2
= (CF)^2+(a/2)^2-2(CF)(a/2)cos(C-X)
=(bcosX)^2+(a/2)^2-2(bcosX)(a/2)(cosCcosX+sinCsinX)
=(bcosX)^2+(a/2)^2-2(bcosX)(a/2)((a^2+b^2-c^2)/2abcosX+(c/2R)sinX))
=a^2/4+(b^2+c^2-a^2)(cosX)^2/2-abcsinX/2R
(ED)^2
=(BE)^2+(a/2)^2-2(BE)(a/2)cos(B-X)
=(ccosX)^2+(a/2)^2-2(ccosX)(a/2)(cosBcosX+sinBsinX)
=(ccosX)^2+(a/2)^2-2(ccosX)(a/2)((a^2+c^2-b^2)/2accosX+(b/2R)sinX))
=a^2/4+(b^2+c^2-a^2)(cosX)^2/2-abcsinX/2R
So, FD=ED
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