发帖数: 1 | 1 Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
“I’m not a politician, and have never wanted to be one. But when I saw the
trouble our country was in, I knew I couldn’t stand by and watch any
longer. Our country has been so good to me, I love our country, I felt I had
to act,” said M... 阅读全帖 |
|
f***e
发帖数: 5443 | 2 作者：匿名用户
Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
今天， 在葛底斯堡Gettysburg，PA， 特朗普发布了他的革命性的入主白宫100天计划.
这个名为“我与广大美国选民的契约”将会保证重振美国经济， 确保国民安全。
“I’m not a politician, and have never wanted to be one. But when I saw the
trouble our country was in, I knew I couldn’t stand by and watch any... 阅读全帖 |
|
f***e
发帖数: 5443 | 3 作者：匿名用户
Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
今天， 在葛底斯堡Gettysburg，PA， 特朗普发布了他的革命性的入主白宫100天计划.
这个名为“我与广大美国选民的契约”将会保证重振美国经济， 确保国民安全。
“I’m not a politician, and have never wanted to be one. But when I saw the
trouble our country was in, I knew I couldn’t stand by and watch any... 阅读全帖 |
|
t**g
发帖数: 3107 | 4 发信人: feebe (现在是工作AA，以后是监狱AA), 信区: USANews
标 题: 特朗普葛底斯堡演说全文
发信站: BBS 未名空间站 (Sun Oct 23 10:57:00 2016, 美东)
作者：匿名用户
Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
今天， 在葛底斯堡Gettysburg，PA， 特朗普发布了他的革命性的入主白宫100天计划.
这个名为“我与广大美国选民的契约”将会保证重振美国经济， 确保国民安全。
“I’m not a politician, and have never... 阅读全帖 |
|
g*********y
发帖数: 500 | 5 网上嗖地，结论是后轮侧滑更危险及难以纠正，所以好胎要放到后面。
Is it dangerous to put tires with the most tread on the front wheels? PDF
Print E-mail
Yes. It has been researched and doucumented that tires with the most tread
must go on the back of the vehicle to help maintain better control!
Note the tire safety information below, taken from car-accident-rain.com,
brought to you by The Brain Injury Law Group - No Charge Unless We Win.
Two Tires Done Wrong. New Tires must go on the Back.
The depth of tread on a tire ... 阅读全帖 |
|
W***n
发帖数: 11530 | 6 Location: San Juan Mountains
Difficulty: Difficult
Directions: 13 miles outside Ouray on Hwy. 550
Time: Approximately 2-3 hours, one-way. 12 miles.
Trail Description
The infamous Black Bear Pass is one of the most difficult mountain passes in
Colorado. When you start the final descent into Telluride, it turns into a
one-way trail, so once you pass that point of no return, it’s do or die
time! I’ve only driven the road to that point and then turned around (didn
’t have good enough tread on my tir... 阅读全帖 |
|
C******a
发帖数: 32 | 7 谢谢楼主分享,偶也贴一个naive的实现,大家看看有什么问题.
int find(int* arr, int value, int begin, int end)
{
if (begin > end)
{
return begin - 1;
}
int mid = (begin + end) / 2;
if (arr[mid] == value)
{
return mid;
}
else if (arr[mid] > value)
{
return find(arr, value, begin, mid - 1);
}
else
{
return find(arr, value, mid + 1, end);
}
}
int findValue(int* arr, int value, int len)
{
return find(arr, value, 0, len - 1);
}
3. 给你一个从小到大排序好的数组，一个给定值value，如果value存在，返回value
的位置；不然，返回index，这个index的值是小于value的最大值；如果不存在这样一
个value，返回 |
|
b********e
发帖数: 53 | 8 #ifndef MERGE_SORTED_ARRAY_H
#define MERGE_SORTED_ARRAY_H
#include
using namespace std;
/* problem statement:
* Given an array of n elements and an integer k where k
* Elements {a[0].....a[k] and a[k+1].....a[n] are already sorted. Give an
* algorithm to sort in O(n) time and O(1) space.
*/
class MergeSortedArray
{
public:
// [begin, end), inflection is the beginning of the second sorted
beginning
void sort(int * begin, int * end, int * inflection)
{
if (begin > |
|
s*******e
发帖数: 93 | 9 为什么code 贴出来显得这么长。。我本来觉得思路挺简单的。
基本上就是，两个map，
一个存每个字母须要出现多少次（needToFind），
一个存每个字母出现了多少次（hasFound）,
查询修改都是O(1)
两个pointer,一个begin,一个end,一开始都在开头。
每轮end往后移动一格。对应的hasFound加一。
然后再看begin, 只要begin
begin就不断往后移。
只要满足都包含的条件，就看总长度有没有小于之前找到的最小长度。
characters, |
|
s*******e
发帖数: 93 | 10 这里count是判断满足条件的唯一依据
我的code里面是这样控制count的：
if(hasFound[index]<=needToFind[index])
{
count++;
}
就是说，如果只需要两个A,当看到第3个A的时候就不管了。
然后count一旦满足条件，既count == S2的长度，之后就永远都是满足条件的状态了
你的例子是
当end移动到S1中的C的位置，count应该就到4。这是begin应该在1（B），end应该在6
(C)
关于舍弃前面的string,当end到3(第3个A)的时候，begin应该还在0,
这是就因hasFound[A]=3，needsToFind[A]=2,就可以知道第一个A就可以不要
但是B不能丢掉，因为目前只有一个B,所以现在begin就在1 (B的位置)
然后end移动到8（最后一个B）,这是begin所在位置的B就可以丢掉了，然后之后的连续3个A
也可以丢掉，直到hasFound[A]==2，最终begin会在5(倒数第二个A) |
|
c******t
发帖数: 1500 | 11 我改了一点你的程序，刚在VS 2008下编译通过了
#include
using namespace std;
void reverse (char *str);
int main(){
char str[] = "hello";
reverse(str);
cout<
}
void reverse(char *str){
char* begin = str;
char* end = str;
char tmp;
if(str)
{
while(*end)
++end;
--end;
while(begin
{
tmp = *begin;
*begin = *end;
*end=tmp;
++begin;
--end;
}
}
... 阅读全帖 |
|
x********o
发帖数: 519 | 12 here is the C++ code:
#include
#include
#include
using namespace std;
void print_vector(const vector &v){
vector::const_iterator iter=v.begin();
while(iter!=v.end()){
cout<<*iter<<" ";
++iter;
}
cout<
}
void subset(vector v, vector sub, int size,set > &s){
if(sub.size()==size){
sort(sub.begin(),sub.end());
s.insert(sub);
return;
}
vector::iterator iter=v.begin();
size_t l=v.size();
for(int ... 阅读全帖 |
|
S**I
发帖数: 15689 | 13 ☆─────────────────────────────────────☆
recursive (递归) 于 (Mon Apr 11 10:56:49 2011, 美东) 提到:
大半夜收到HR的thank you note。不用管什么NDA了
本人ECE fresh PhD，背景是电路/EDA，跟G业务基本没什么关系
同学内部推荐的，很简单的一次电面就给了onsite
题都不难，但是自己没把握好机会，出了一些小bug。
总的感觉，出错就是硬伤，宁可从最简单的算法写起，也不能出错。
电面：
1，Skip list， http://en.wikipedia.org/wiki/Skip_list
写code实现struct skip_list * find(struct skip_list *head, int value)
2，sorted array with repeated elements
for given element, find out its range.
e.g. A A B B B B B C C D D E F G, given B, the out... 阅读全帖 |
|
S**I
发帖数: 15689 | 14 ☆─────────────────────────────────────☆
libei (Bei) 于 (Wed Jan 11 15:43:39 2012, 美东) 提到:
面试官是Google+组的，
一上来她说看到我简历上的一篇测试自动化的文章，读了一遍，感觉"very
informative"，让后让我介绍一下相关经验。让我小高兴了一下。
第一题是coding，做的还算顺利，后来她评价说所有的cases都覆盖到了。可能算是过
关吧。
第二题我想复杂了，然后在她提示下才解决。自我感觉很不好。其实sort一下就差不多
了，不过我往复杂的树结构想去了。虽然树结构确实能解决这个问题，不过当时我解释
得很不清楚。反正很不爽。
最后瞎聊时间，她说我提到的测试自动化实践和Google内部的基本完全一样blahblah。
。。，不过我觉得这点也算不上加分吧，是个人进google一段时间后都能学会。就怕她
觉得我想问题太复杂，直接negative。
大家有啥建议想法？？
☆─────────────────────────────────────☆
peking2 (myfac... 阅读全帖 |
|
w****x
发帖数: 2483 | 15 string digitMul(string str, int nDigit)
{
assert(nDigit >= 0 && nDigit <= 9);
int nCarrier = 0;
string strRes;
for (int i = str.size()-1; i >= 0; i--)
{
int nTmpDigit = str[i] - '0';
int nRes = nTmpDigit * nDigit;
nRes += nCarrier;
strRes.insert(strRes.begin(), ('0' + nRes%10));
nCarrier = nRes/10;
}
if (nCarrier > 0)
strRes.insert(strRes.begin(), ('0' + nCarrier));
return strRes;
}
string StrAdd(string str1, string ... 阅读全帖 |
|
w****x
发帖数: 2483 | 16 string digitMul(string str, int nDigit)
{
assert(nDigit >= 0 && nDigit <= 9);
int nCarrier = 0;
string strRes;
for (int i = str.size()-1; i >= 0; i--)
{
int nTmpDigit = str[i] - '0';
int nRes = nTmpDigit * nDigit;
nRes += nCarrier;
strRes.insert(strRes.begin(), ('0' + nRes%10));
nCarrier = nRes/10;
}
if (nCarrier > 0)
strRes.insert(strRes.begin(), ('0' + nCarrier));
return strRes;
}
string StrAdd(string str1, string ... 阅读全帖 |
|
I****h
发帖数: 33 | 17 PNode trim_list(PNode begin)
{
Node head = {0};
PNode anchor = NULL;
PNode prev = NULL;
PNode curr = NULL;
int trim = 0;
if ((begin == NULL) || (begin->key != 0))
{
head.key = 0;
}
else
{
head.key = 1;
}
head.next = begin;
anchor = &head;
prev = &head;
curr = begin;
while (curr != NULL)
{
if (prev->key != curr->key)
{
if (trim == 0)
{
anchor = prev;
... 阅读全帖 |
|
a*******y
发帖数: 1040 | 18 上面说的基本正确，第二步里面应该还是从end开始找
bool _next_permutation(int* begin, int* end)
{
if (begin == end) return false;
int* x1 = end - 1;
while (x1 >= begin && *x1 >= *(x1+1)) --x1;
if (x1 == begin)
{
reverse(begin, end);
return false;
}
int* x2 = end;
while (*x2 < *x1) --x2;
swap(*x1, *x2);
reverse(x1+1, end);
return true;
} |
|
d****o
发帖数: 1055 | 19 写了一个增加一个空头结点的简单代码。
node* reverse(node* head, int begin, int end){
assert(begin
if(head==NULL) return NULL;
node* newHead = new node();
newHead->next = head;
node* cur = newHead;
int cnt = end-begin+1; //3
while(begin>=2){ //
cur=cur->next;
if(!cur) return NULL;
begin--; //1
}
node* end=cur;
while(cnt>0){//
end = end->next;
if(!end) return NULL;
cnt--;
... 阅读全帖 |
|
b*****e
发帖数: 474 | 20 brutal force O(N*N) answer:
assuming input string a with strlen N.
int begin, end, i;
int len[N], maxlen=0;
for (i=0; i< 2*N-1; i++ ) {
// start from middle
begin = i/2;
end = (i+1)/2;
len[i] = 0;
while ( begin>=0 && end
len[i]+= (begin--==end++)? 1: 2;
if ( len[i] > maxlen ) maxlen = len[i];
}
output maxlen;
may be this can be optimized to reach O(N) |
|
A******g
发帖数: 612 | 21 Leetcode OJ里的word ladder, 过了小test，大test第一个就超时了，不解！
用的是BFS算法，请大牛们看看有什么问题，谢谢！
class Solution {
public:
typedef unordered_map > Graph;
bool has_edge(string a, string b) {
if (a.size() != b.size()) {
return false;
}
int diff = 0;
for (int i=0; i
if (a[i] != b[i])
diff++;
}
return diff==1;
}
void build_graph(string &start, string &end, unordered_set阅读全帖 |
|
c********p
发帖数: 1969 | 22 请大牛帮忙看看。
第一个是longest palindrome的，我按leetcode discussion的c++代码改的java的，怎
么就过不了了呢？一行行对过了阿。。。我知道有o(n)的算法，但这个dp的我就奇怪怎
么过不了呢，哪个细节写错了。。。
public class Solution {
public String longestPalindrome(String s) {
// Start typing your Java solution below
// DO NOT write main() function
if(s == null || s.length() <= 1){
return s;
}
int[][] P = new int[s.length()][s.length()];
int max = 1;
int begin = 0;
for(int i =... 阅读全帖 |
|
f**********t
发帖数: 1001 | 23 class Intervals {
vector> _vals;
public:
Intervals(initializer_list> prs) {
_vals.insert(_vals.end(), prs.begin(), prs.end());
}
void Dump() {
for_each(_vals.begin(), _vals.end(), [](const pair &p) {
cout << '(' << p.first << ',' << p.second << ')' << ", ";
});
cout << endl;
}
void Insert(const pair &pr) {
auto left = lower_bound(_vals.begin(), _vals.end(), pr,
[](const pair &x, const pair阅读全帖 |
|
|
|
w**z
发帖数: 8232 | 26 http://www.jobspringpartners.com/blog/posts/2013/3/4/the-war-fo
3/4/13 by Silicon Valley
By: Scott Purcell, Division Manager of Jobspring Silicon Valley
Anyone who has lived in Silicon Valley for a while and works in the high
tech world, particularly in software, can attest to a market where the
competition for solid talent has continued to grow more competitive by the
year. As a high tech recruiter managing an office focused on placing
software engineers I have seen both the competition for ta... 阅读全帖 |
|
a**********0
发帖数: 422 | 27 The Unix Commands
其实就是攒了一下网上的资料
# Create a new tar archive.
# the folder dirname/ is compressed into archive_name.tar
tar cvf archive_name.tar dirname/
# Extract from an existing tar archive
tar xvf archive_name.tar
# View an existing tar archive
tar tvf archive_name.tar
# Search for a given string in a file (case in-sensitive search).
grep -i "the" demo_file
# Print the matched line, along with the 3 lines after it.
grep -A 3 -i "example" demo_text
# Search for a given string in all files recur... 阅读全帖 |
|
d*k
发帖数: 207 | 28 好久没来贡献了，刚好有时间来，和大家交流一下。
这个题需要一个巧妙的思路，如果想不到是无法解答的。个人认为这种depend solely
on one key observation的题目不适合当面试题，而且以我的能力，除非有很好的提示
，不可能想出来。
设原来的结构为
a1a2a3...anb1b2b3...bn，需要变换为a1b1a2b2a3b3...anbn。可以把左右两个数组看
做A和B，长度分别为n。现在把A和B都划分成两个长度为n/2的数组，则输入可表示为
A1A2B1B2。这里的四个数组长度都是n/2（n是奇数也则A2和B2的长度比A1和B1的长度少
1）。有算法可以在O(n)时间内inplace地交换A2和B1得到A1B1A2B2。之后递归地处理
A1B1和A2B2。时间复杂度分析，上面的递归时间代价可以表示为
T(n) = O(n/2) + 2 * T(n / 2)
因此T(n) = O(nlogn)。
关于inplace地交换A2和B1的算法，相信大家都知道了。首先将A2B1这部分反序，设A2
长度为p，B1长度为q。反序后的部分，先将前q个元素反序，再将后面的p个... 阅读全帖 |
|
d*k
发帖数: 207 | 29 好久没来贡献了，刚好有时间来，和大家交流一下。
这个题需要一个巧妙的思路，如果想不到是无法解答的。个人认为这种depend solely
on one key observation的题目不适合当面试题，而且以我的能力，除非有很好的提示
，不可能想出来。
设原来的结构为
a1a2a3...anb1b2b3...bn，需要变换为a1b1a2b2a3b3...anbn。可以把左右两个数组看
做A和B，长度分别为n。现在把A和B都划分成两个长度为n/2的数组，则输入可表示为
A1A2B1B2。这里的四个数组长度都是n/2（n是奇数也则A2和B2的长度比A1和B1的长度少
1）。有算法可以在O(n)时间内inplace地交换A2和B1得到A1B1A2B2。之后递归地处理
A1B1和A2B2。时间复杂度分析，上面的递归时间代价可以表示为
T(n) = O(n/2) + 2 * T(n / 2)
因此T(n) = O(nlogn)。
关于inplace地交换A2和B1的算法，相信大家都知道了。首先将A2B1这部分反序，设A2
长度为p，B1长度为q。反序后的部分，先将前q个元素反序，再将后面的p个... 阅读全帖 |
|
z***y
发帖数: 73 | 30 比起这个还有更变态的，不过不是编码规则，是代码修改注释。
某公司是这么规定的，当产品到达一定的miletone以后，所有代码修改都需要有一个标
准注释。
首先，当然是要产生一个issue或者ticket描述为啥修改，然后：
如果你是单纯的新增代码，那么：
// begin ISSUE-XXX ADD BY XXXXX(姓名拼音) YYYYYYYY(工号), 20XX/XX/XX
your code
// end ISSUE-XXX ADD BY XXXXX(姓名拼音) YYYYYYYY(工号), 20XX/XX/XX
修改代码就是把以上ADD替换成MODIFIED。然后就可以经常看到如下代码：
// begin ISSUE-966 MODIFIED BY GEBILAOWANG 99999, 2011/11/11
// begin ISSUE-485 MODIFIED BY ZHAOSI 99998, 2010/11/11
// begin ISSUE-333 MODIFIED BY ZHANSAN 99990, 2010/05/11
// begin ISSUE-234 ADD BY... 阅读全帖 |
|
g*****o
发帖数: 21 | 31 BRU有两款simmons beautyrest beginning的床垫, $179.99和$209.99.
$179.99的叫Simmons Beautyrest Beginnings Sophisticated Crib and Toddler Bed
Mattress.
$209.99的叫Simmons Beautyrest Beginnings Advanced Crib and Toddler Bed
Mattress.
而Amazon上卖的两款分别叫Simmons Kids Beautyrest Beginnings Nighttime Whimsy
Firm Baby Crib and Toddler Mattress和Simmons Kids Beautyrest Beginnings
Nighttime Whimsy Luxury Firm Baby Crib and Toddler Mattress.价钱要便宜些.
问题是这两家卖的是同样的型号吗？便宜的对应便宜的，贵的对应贵的吗？名字不完全
一样,看糊涂了。有JM知道的给说说.
231 |
|
c*******e
发帖数: 145 | 32 需要给即将出生的宝宝买crib mattress.两个标准： （1) 要有好的support,要比较硬
。（2）不要防水表面。因为之前有MM反应防水表面会不透气让宝宝出汗。看到大家推
荐simmons的beautyrest beginning,可上网查了一下他家有好几种叫beautyrest
beginning的：
1.Beautyrest Beginnings Pampering Nights 231 Pocketed Coil
2.Beautyrest Beginnings Renewed Spirits 231 Pocketed Coil
3.Beautyrest Beginnings Naturally Restored Comfort 231 Pocketed
请问到底JM们买的是哪种符合上述两种要求的？住的是小地方，估计只能网购，不想买
错了。多谢各位宝妈啦！ |
|
发帖数: 1 | 33 12月27日 为什么我要替中国辩护
我要替中国辩护，并不是因为我是一个中国人，而是因为我知道中国就和这世界上绝大
数的国家一样，虽然有很多丑陋的现象，但是他们是受害者。就
象这个犯罪集团里很多的人一样，他们来自各种种族，他们可能充当了工具，但他们不
是制造这一切，谋划这一切的人。虽然经常会暴露中国产品出现问题。但要知道中国是
世界工厂，他们只是打工者，他们只是按照各种雇主提供的配方来生产，他们并不知道
他们会产生怎样的后果。或者这些工人知道后果，但他们只是奴隶，他们又如何去改变
这一切？ 所以，当我的调查不断往前推进的时候，不可避免地会涉及各国的企业，但
这并不表明是针对这个国家或这个国家的人民，而是针对一种社会现实和丑陋现象。就
拿菲律宾来说，菲律宾是一个犯罪猖獗的国家，有很多犯罪分子，但是菲律宾人民却是
这个集团的受害者，他们／她们被绑架，沦为了牺牲品，人体实验对象。一个日本人，
强奸上千名菲律宾女孩，却没有受到惩罚。以前我也提到过，有20个国家的名单，这20
个国家的人民其实都是受害者。现在他们把矛头对准中国，或许仅仅是因为我揭示了他
们图害世界人民的内幕，而我是一个中国人的缘... 阅读全帖 |
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N**********m
发帖数: 212 | 34 Wrong!
this is end of the beginning of the end of the beginning of the end for the
mid-term.
this is the beginning of the end of the beginning of the end of the
beginning for the long term. |
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a**u
发帖数: 8107 | 35 http://www.leveringorchard.com/tartcherries.aspx
Daily Cherry Hotline update: 336-786-4316 or 276-755-4837
Packhouse (business hours) 276-755-3593
NOTE: All dates are ESTIMATED. PHONING AHEAD ADVISED.
Early Sweet Cherries begin Wednesday, May 26, 2010
Mid to Late Season Cherries begin June 11, 2010 and run (weather permitting)
to early to mid-July
Tart (pie) Cheeries begin (estimated) June 12, 2010
Lodi Cooking Apples begin June 26, 2010
Peaches begin Friday, July 30, 2010
McIntosh-type Summer A |
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o*****9
发帖数: 47 | 36 可以约一下，一起看热闹去～～
FULL SCHEDULE
3:00pm - 5:00pm Adult/Couple/Group Registration opens at SPIN (800 W
. Belmont)
FLOATS/Official Groups (e.g. Spirit Brigade) check-in at the Northeast
Corner of Halsted & Clark
4:30pm - 5:30pm Kids/Pets Registration & Activities begin at Space
Park
5:30pm - 6:00pm Kids/Pets Judged at Space Park and prizes are
awarded
5:00pm - 5:45pm FLOATS/ Official Groups should be lined up on
Halsted between Belmont and Clark
5:15pm - 6:15pm ... 阅读全帖 |
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S*******h
发帖数: 7021 | 37 IN IOWA, DONALD TRUMP OFFERS VISION OF HOPE FOR THE POWERLESS AND
DISENFRANCHISED
Thank you. I am thrilled to be here in Iowa among so many good friends.
Iowa is fortunate to have some of the best and most dedicated public
servants in the country – including Governor Terry Branstad, Lt. Governor
Kim Reynolds, State GOP Chairman Jeff Kauffman, Senator Chuck Grassley and,
of course, our great host, Senator Joni Ernst.
What an incredible roster.
I also want to take a moment to thank the Bikers who ... 阅读全帖 |
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j****1
发帖数: 15497 | 38 June 25
Rose Bowl 下午6点有足球赛，届时Pasadena 西北部乃至old town地区都会比较堵。
http://www.rosebowlstadium.com/RoseBowl_Soccer_2011.php
the Galen Center有篮球赛,Jefferson Boulevard will be closed between Figueroa
Street and Flower Street from 5:30 a.m. until 4 p.m.
June 26
Black Entertainment Awards Show in the Shrine Auditorium
Jefferson Boulevard will be closed in both directions from Figueroa
Street to Hoover Street beginning at 6 a.m.
32nd Street will be closed from Figueroa Street to Hoover Street
beginnin... 阅读全帖 |
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f******e
发帖数: 48 | 39 I just bought mine from local dealer for $6400 (including tax/delivery/1
free tune), sorry can't wait :)
You can ask the dealer for the serial number first. (it should be something
like 6******)
Check this website to make sure it's made for US market and production Year.
2008 6220000
2009 6250000
2010 6280000
http://usa.yamaha.com/support/finding_age_of_yamaha_piano/
Yamaha Pianos produced for the U.S. market have been manufactured in 6
locations:
Hamamatsu, Japan
Thomaston, Georgia
Sou... 阅读全帖 |
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f******e
发帖数: 48 | 40 I just bought mine from local dealer for $6400 (including tax/delivery/1
free tune), sorry can't wait :)
You can ask the dealer for the serial number first. (it should be something
like 6******)
Check this website to make sure it's made for US market and production Year.
2008 6220000
2009 6250000
2010 6280000
http://usa.yamaha.com/support/finding_age_of_yamaha_piano/
Yamaha Pianos produced for the U.S. market have been manufactured in 6
locations:
Hamamatsu, Japan
Thomaston, Georgia
Sou... 阅读全帖 |
|
j****y
发帖数: 597 | 41 作者：匿名用户
Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
今天， 在葛底斯堡Gettysburg，PA， 特朗普发布了他的革命性的入主白宫100天计划.
这个名为“我与广大美国选民的契约”将会保证重振美国经济， 确保国民安全。
“I’m not a politician, and have never wanted to be one. But when I saw the
trouble our country was in, I knew I couldn’t stand by and watch any... 阅读全帖 |
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j****y
发帖数: 597 | 42 作者：匿名用户
Gettysburg, PA: Today, in historic Gettysburg, PA, Donald J. Trump presented
a game-changing plan for his first 100 days in office. This revolutionary
“Contract with the American Voter” will ensure that America’s economy is
revitalized and citizens are protected.
今天， 在葛底斯堡Gettysburg，PA， 特朗普发布了他的革命性的入主白宫100天计划.
这个名为“我与广大美国选民的契约”将会保证重振美国经济， 确保国民安全。
“I’m not a politician, and have never wanted to be one. But when I saw the
trouble our country was in, I knew I couldn’t stand by and watch any... 阅读全帖 |
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c*******g
发帖数: 475 | 43 新年短信集锦
Before the golden sun sets,
old calender is destroyed,
And mobile networks get jammed,
I wish in new year every moment is enjoyed
( Characters: 132)
For last year's words belong to last year's language
And next year's words await another voice.
And to make an end is to make a beginning.Happy New Year. (Characters:
157)
God Bless U N Keep U Safe Not Only Today But Throughout Life That is coming
In Ur Way. May Year To Follow Be Among The Best U ve Ever Spend. (
Characters: 140)
Beauty..... 阅读全帖 |
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d**u
发帖数: 1639 | 44 ☆─────────────────────────────────────☆
betwfingers (费帮_城管大叔) 于 (Thu Dec 30 14:08:07 2010, 美东) 提到:
版二ditu隆重赞助
_________________________________
又是一年要过去了。。。
祝大家新年好。。。
明年更好。。。。希望合家安康，事业顺利，世界太平。。。
发包子吧，限常驻ID...
(难道没有公司赞助点实物的吗。。。)
☆─────────────────────────────────────☆
ARSU (do people need thick road) 于 (Thu Dec 30 14:41:08 2010, 美东) 提到:
排实物包子
☆─────────────────────────────────────☆
recoco (Teddybaobao) 于 (Thu Dec 30 16:23:31 2010, 美东) 提到:
吃
☆─────────────────────────────────────☆
... 阅读全帖 |
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d*****3
发帖数: 79 | 45 Several blocks of major roads in downtown D.C. will be closed tomorrow for
events connected to the National Cherry Blossom Festival. Tomorrow features
both the Sakura Matsuri, a Japanese street fair, as well as the annual
National Cherry Blossom Festival Parade.
With the events, the District Department of Transportation will be closing
off key thoroughfares to vehicular traffic beginning early Saturday morning.
Beginning at 4:30 a.m., DDOT will close off the parade's staging area,
which takes up... 阅读全帖 |
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N****t
发帖数: 156 | 46 Hi Racket Swingers,
It's that time again. BADMINTON!
The following is the clip from the Spring Brochure:
ADULT BADMINTON - ADVANCED/INTERMEDIATE
Open courts for intermediate and advanced players. Mostly doubles, but
singles when court space available. Bring your own racket; feather
shuttlecocks provided. Lane School Gym. (max 22) Tues., 7:30 – 10:00pm, 4
/5 - 6/7 (no use 4/19) Fee: $15
Set up night is 4/5, play will be conducted once set up is complete
ADULT BADMINTON - BEGINNER/INTERM... 阅读全帖 |
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i*********5
发帖数: 19210 | 47 【 以下文字转载自 Tri 讨论区 】
发信人: ironman2015 (IMMT 2013), 信区: Tri
标 题: 2013 Fall Epic 8 Hour 比赛报告
发信站: BBS 未名空间站 (Mon Sep 30 01:16:04 2013, 美东)
What a great day of racing at Hardwood Hill! Never rode my mountain bike so
long in a day before. But since it's the only day I get to ride my MTB for
the year, why not make it worth the trip. After all 8-hour is relatively
short compared to an 11-hour Ironman.
All the preparation was checking out last year's solo result and comparing
that to my times in the re... 阅读全帖 |
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l*x
发帖数: 14021 | 48 Feb 10: you are here
----------------------------------
Feb 17: Teams may designate one Franchise/Transition Player
Feb 19-25: NFL Scouting Combine, Lucas Oil Stadium, Indianapolis, IN
Mar 3: Deadline for designating one Franchise/Transition player (3:00 PM CST)
Mar 8-11: Clubs are permitted to enter into contract negotiations with
certified agents of players who will be Unrestricted Free Agents at the end
of the current League Year.
--------------------------------
Mar 11: 2014 League Year star... 阅读全帖 |
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B**I
发帖数: 601 | 49 http://ezine.kungfumagazine.com/info/tournament/2010RULES_PushH
US Rules
RULES FOR TAI CHI PUSH HAND DIVISIONS
1. General Rules
a. Competitors must be over 18 years of age, have practiced Tai Chi Kung Fu
for more than 2 years, be able to show proof of coverage by a valid health
insurance policy (a valid insurance card is sufficient), and be willing to
sign the Liability Waiver. Competitors are required to follow the rules and
demonstrate courtesy to the judges and officials, the audience, and fe... 阅读全帖 |
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W********s
发帖数: 2256 | 50 Texas is the king of college football.
Texas expects almost 2x the amount of SEC money in 2011
According to multiple sources, Texas stands to increase its TV revenue by $
12 million per year thanks to an
agreement reached with ESPN to distribute the Longhorn Network on cable
systems beginning in the fall of
2011.
The sources said the deal is for 10 years and guarantees Texas $12 million
annually on top of the TV
revenue UT would receive as part of the Big 12's current television
contracts wit... 阅读全帖 |
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