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全部话题 - 话题: bajb
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A***C
发帖数: 143
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来自主题: Mathematics版 - 请教大家一个矩阵的问题
Qij = vec(Ai)^T B^T \x B vec(Aj)
When B^T \x B is positive semi-definite,
Q is positive semi-definite,
you can further determine when Q is full rank to see
when Q is positive definite,
\x is the Kronecker product here.
You can use the matrix vectorization
http://en.wikipedia.org/wiki/Vectorization_(mathematics)
and make use of
Tr AiBAjB = = vec(Ai)^T vec(BAjB)
to obtain my conclusion
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